Problem 3
Question
Match the equation in Column I with its solution(s) in Column II. Do not use a calculator. (II) A. \(\pm 2 i\), B. \(\pm 2 \sqrt{2}\), C. \(\pm i \sqrt{2}\), D. 2, E. \(\pm \sqrt{2}\), F. \(-2\), G. \(\pm 2\), H. \(\pm 2 i \sqrt{2}\) (I) $$x^{2}+2=0$$
Step-by-Step Solution
Verified Answer
The solution is option C: \( \pm i \sqrt{2} \).
1Step 1: Understanding the Equation
The given equation is \( x^2 + 2 = 0 \). This is a quadratic equation in the form \( ax^2 + bx + c = 0 \), where \( a = 1 \), \( b = 0 \), and \( c = 2 \).
2Step 2: Move Constant to Other Side
Rewrite the equation by transferring the constant to the other side to isolate the \( x^2 \): \( x^2 = -2 \).
3Step 3: Solve for x Using Square Roots
To solve for \( x \), take the square root of both sides. Since the right-hand side is negative, the solutions will be complex: \( x = \pm \sqrt{-2} \).
4Step 4: Simplify the Square Root
Simplify \( \sqrt{-2} \) by expressing it as \( \sqrt{2} \times i \), where \( i \) represents the imaginary unit. Therefore, the solutions are \( x = \pm i \sqrt{2} \).
5Step 5: Match the Solutions with Column II
The solutions \( \pm i \sqrt{2} \) correspond to option C in Column II.
Key Concepts
Complex NumbersImaginary UnitSquare Roots
Complex Numbers
Complex numbers are a fascinating part of mathematics, expanding beyond the realm of real numbers. They are expressed in the form of \( a + bi \), where \( a \) and \( b \) are real numbers, and \( i \) is the imaginary unit. This unique combination allows for the resolution of equations that have no real solutions, like \( x^2 + 2 = 0 \). In this equation, the solution involves taking the square root of a negative number, which is where complex numbers shine.
- The real part of a complex number is \( a \).
- The imaginary part is \( bi \).
- They are particularly useful in various fields such as engineering, physics, and applied mathematics.
Imaginary Unit
The imaginary unit, denoted as \( i \), is the cornerstone of complex numbers and a crucial concept in the quadratic equation \( x^2 + 2 = 0 \). It is defined as \( i = \sqrt{-1} \). This definition allows mathematicians to extend the real number system to include solutions to equations like \( x^2 = -1 \). In the process of solving quadratic equations involving negative numbers under the square root, the imaginary unit leads to the formation of complex numbers.
- \( i^2 = -1 \) because squaring the imaginary unit returns a negative real number.
- \( i \) enables the computation of square roots of negative numbers, which are non-real numbers.
- The imaginary unit is not just theoretical; it has practical applications, especially in electrical engineering and signal processing.
Square Roots
The concept of square roots is integral to solving quadratic equations like \( x^2 + 2 = 0 \). Typically, a square root is a value that, when multiplied by itself, gives the original number. However, when dealing with negative numbers within square roots, we transition into the complex plane. Let's break it down:
- \( \sqrt{a} \) is understood as the number which, when squared, results in \( a \).
- For negative numbers, such as \( -2 \), we use the imaginary unit \( i \) to express \( \sqrt{-2} \).
- This transforms the problem from illogical in the real number system to solvable in complex numbers, yielding \( \pm i \sqrt{2} \) as solutions.
Other exercises in this chapter
Problem 3
Find a cubic polynomial in standard form with real coefficients, having the given zeros. Let the leading coefficient be \(1 .\) Do not use a calculator. 5 and \
View solution Problem 3
Each expression. Apply the property \(\frac{a+b}{c}=\frac{a}{c}+\frac{b}{c}\) if necessary. Do not use a calculator. $$\frac{8 x^{9}}{3 x^{7}}$$
View solution Problem 3
Solve each problem. Do not use a calculator. Find the minimum \(y\) -value on the graph of \(y=3 x^{2}-24 x+50\)
View solution Problem 4
For each complex number, (a) state the real part, (b) state the imaginary part, and (c) identify the number as one or more of the following: real, pure imaginar
View solution