Problem 3
Question
Match each equation in Column I with the appropriate description in Column II. Do not use a calculator. A. Hyperbola; center \((2,4)\) B. Ellipse; foci \((\pm 2 \sqrt{3}, 0)\) C. Hyperbola; foci \((0, \pm 2 \sqrt{5})\) D. Hyperbola; center \((-2,4)\) E. Ellipse; center \((-2,4)\) F. Center \((0,0) ;\) horizontal transverse axis G. Ellipse; foci \((0, \pm 2 \sqrt{3})\) H. Vertical major axis; center \((2,-4)\) $$\frac{x^{2}}{4}-\frac{y^{2}}{16}=1$$
Step-by-Step Solution
Verified Answer
The hyperbola is centered at (0,0) with a horizontal transverse axis.
1Step 1: Identify the Conic Section
The given equation is \( \frac{x^{2}}{4} - \frac{y^{2}}{16} = 1 \). This equation has the form \( \frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1 \), which is the standard form of a hyperbola. Hyperbolas are characterized by their 'minus' sign between the squared terms.
2Step 2: Determine the Center of the Hyperbola
The standard form of a hyperbola \( \frac{(x-h)^{2}}{a^{2}} - \frac{(y-k)^{2}}{b^{2}} = 1 \) has a center at \((h, k)\). Since our equation is \( \frac{x^2}{4} - \frac{y^2}{16} = 1 \), it implies \( h = 0 \) and \( k = 0 \), so the center is \((0,0)\).
3Step 3: Identify Orientation of the Transverse Axis
In a hyperbola of the form \( \frac{(x-h)^{2}}{a^{2}} - \frac{(y-k)^{2}}{b^{2}} = 1 \), the transverse axis is horizontal because the \( x \)-term is positive. This means the hyperbola opens horizontally.
Key Concepts
HyperbolaCenter of HyperbolaHorizontal Transverse Axis
Hyperbola
A hyperbola is a type of conic section that is formed when a plane intersects both nappes of a double cone. It's visually distinct with its two separate curves called "branches." Unlike ellipses and circles, hyperbolas are open-ended and extend infinitely.
What sets a hyperbola apart from other conic sections is its equation form. It has a characteristic 'minus' sign between the squared terms. For instance, the equation \( \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \) is the standard equation of a hyperbola.
Some important properties of hyperbolas include:
What sets a hyperbola apart from other conic sections is its equation form. It has a characteristic 'minus' sign between the squared terms. For instance, the equation \( \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \) is the standard equation of a hyperbola.
Some important properties of hyperbolas include:
- Each hyperbola has two transverse points called vertices.
- There are two axes: transverse and conjugate.
- The transverse axis contains the centers and vertices.
Center of Hyperbola
The center of a hyperbola is a critical point, as it helps in understanding and graphing the hyperbola effectively. This point is essentially the midpoint between the vertices and the foci.
In the standard form equation \( \frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1 \), the coordinates \((h, k)\) represent the center of the hyperbola. From this equation, you can see that any shift in the values of \(h\) or \(k\) will move the entire hyperbola along the x-axis or y-axis, respectively.
To locate the center of the hyperbola:
In the standard form equation \( \frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1 \), the coordinates \((h, k)\) represent the center of the hyperbola. From this equation, you can see that any shift in the values of \(h\) or \(k\) will move the entire hyperbola along the x-axis or y-axis, respectively.
To locate the center of the hyperbola:
- Identify \((h, k)\) from the equation.
- The center divides the hyperbola symmetrically along the transverse axis.
Horizontal Transverse Axis
The transverse axis of a hyperbola indicates the direction in which its branches open. In hyperbolas, this axis is significant for understanding their orientation.
For a hyperbola given in the form \( \frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1 \), the transverse axis is horizontal. This means the equation begins with \(x\) and it "opens" along the x-axis. The transverse axis contains important points like the center and the vertices of the hyperbola.
Consider these features when dealing with a horizontal transverse axis:
For a hyperbola given in the form \( \frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1 \), the transverse axis is horizontal. This means the equation begins with \(x\) and it "opens" along the x-axis. The transverse axis contains important points like the center and the vertices of the hyperbola.
Consider these features when dealing with a horizontal transverse axis:
- The standard horizontal equation ensures the hyperbola opens left and right.
- The distance \(2a\) represents the length of the transverse axis.
- The equation \( \frac{x^2}{4} - \frac{y^2}{16} = 1 \) in our example indicates a horizontal transverse axis since it starts with the \(x^2\) term.
Other exercises in this chapter
Problem 3
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View solution Problem 3
The equation of a conic section is given in a familiar form. Identify the type of graph (if any) that each equation has, without actually graphing. See the summ
View solution Problem 3
Skills Match each equation in Column I with the appropriate description in Column II. Do not use a calculator. A. Circle; center \((3,-4) ;\) radius 5 B. Parabo
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Graph each pair of parametric equations by hand, using values of t in \([-2,2] .\) Make a table of \(t=x\) - and \(y\) -values, using \(t=-2,-1,0,1,\) and \(2 .
View solution