Problem 3
Question
Let \(f(x)=3 x+5\) and \(g(x)=x^{2} .\) Perform each function operation. $$ f(x)-g(x) $$
Step-by-Step Solution
Verified Answer
So the result of subtracting \(g(x) = x^2\) from \(f(x) = 3x + 5\) is \(f(x) - g(x) = 3x + 5 - x^2\)
1Step 1: Identify the functions
The two functions to be used in the operation are \(f(x) = 3x + 5\) and \(g(x) = x^2\).
2Step 2: Perform the subtraction
Subtract the function \(g(x) = x^2\) from the function \(f(x) = 3x + 5\). This is performed as follows: \(f(x) - g(x) = (3x + 5) - x^2\).
3Step 3: Simplify the result
In this particular case, no further simplification is needed, because there are no like terms to combine.
Key Concepts
Function SubtractionPolynomial FunctionsAlgebraic Expressions
Function Subtraction
Function subtraction is a method we use to subtract one function from another. It is an essential skill in algebra that helps us understand and manipulate functions. Given two functions, like \( f(x) \) and \( g(x) \), function subtraction is expressed as \( f(x) - g(x) \). Here's the simple process:
- First, identify both functions involved.
- Next, subtract the second function from the first.
- Finally, simplify the resulting expression.
Polynomial Functions
Polynomial functions are expressions that involve variables raised to whole number powers. They are fundamental in algebra due to their simple to complex structures. A polynomial function can have:
- Constant terms like \(5\) or \(12\)
- Linear terms like \(3x\)
- Quadratic terms like \(x^2\)
Algebraic Expressions
Algebraic expressions are combinations of numbers, variables, and arithmetic operators like addition or subtraction. They form the backbone of algebra, allowing us to express mathematical ideas in a concise form.An algebraic expression can include:
- Constants, which are fixed numbers (e.g., \(5\))
- Variables, which are symbols that represent numbers (e.g., \(x\))
- Operators, which indicate operations to be performed (e.g., +, -)
Other exercises in this chapter
Problem 3
Find the inverse of each relation. Graph the given relation and its inverse. $$ \begin{array}{|c|c|c|c|c|}\hline x & {0} & {1} & {2} & {3} \\ \hline y & {0} & {
View solution Problem 3
Solve. \(\sqrt{x+3}=5\)
View solution Problem 3
Add or subtract if possible. $$ 4 \sqrt{3}+4 \sqrt[3]{3} $$
View solution Problem 3
Multiply, if possible. Then simplify. $$ \sqrt[3]{9} \cdot \sqrt[3]{-81} $$
View solution