Problem 3
Question
In Exercises \(1-18,\) graph each ellipse and locate the foci. $$\frac{x^{2}}{9}+\frac{y^{2}}{36}=1$$
Step-by-Step Solution
Verified Answer
The semi-major axis \(a=3\) and the semi-minor axis \(b=6\). The ellipse is plotted with the center at the origin, the major axis along the y-axis from \(-6\) to \(6\) and the minor axis along the x-axis from \(-3\) to \(3\). The foci are \((0,5)\) and \((0,-5)\).
1Step 1: Identify the semi-major axis and semi-minor axis
From the equation \(\frac{x^{2}}{9}+\frac{y^{2}}{36}=1\), we can see that \(a^{2}=9\) and \(b^{2}=36\). So, the semi-major axis \(a=3\) and the semi-minor axis \(b=6\).
2Step 2: Graph the ellipse
Plot the center of the ellipse at the origin point \((0,0)\). The semi-major axis extends along the y-axis from \(0\) to \(6\) and from \(0\) to \(-6\). The semi-minor axis extends along the x-axis from \(0\) to \(3\) and from \(0\) to \(-3\). Plot these points and draw the ellipse.
3Step 3: Calculate foci points
To calculate the foci, use the formula \(c=\sqrt{b^2-a^2}\) where \(c\) is the distance from the center to each of the foci. Substituting the given values, we get \(c=\sqrt{36-9}=5\). The foci are located at \(0\) plus or minus \(c\) on the y-axis, or \((0,5)\) and \((0,-5)\). Plot these on the ellipse.
Key Concepts
Semi-Major AxisSemi-Minor AxisFoci of an Ellipse
Semi-Major Axis
The semi-major axis of an ellipse is one of its most crucial features. In an ellipse's equation, such as \[ \frac{x^{2}}{9} + \frac{y^{2}}{36} = 1, \]the semi-major axis can be identified depending on which denominator is larger. Here, since the larger denominator 36 is under the \(y^2\) term, the ellipse is vertically oriented, and the semi-major axis is determined by \(b = 6\). This means that the ellipse stretches farther along the y-axis.
- For ellipses, the axis aligned with the larger value in the equation is always the semi-major axis.
- If \(a^2\) were larger, the semi-major axis would be aligned with the x-axis.
Semi-Minor Axis
The semi-minor axis complements the semi-major axis by defining the ellipse's width. In the equation \[ \frac{x^{2}}{9} + \frac{y^{2}}{36} = 1, \]we find that \(a^2 = 9\), so \(a = 3\). This makes the semi-minor axis 3 units long and oriented along the x-axis. This axis is important for completing the shape of the ellipse, ensuring that it is not circular but elongated in one direction.
- A semi-minor axis should be thought of as the shorter radius of the ellipse.
- If the ellipse is horizontal, the semi-minor axis would still align with the secondary dimension, usually the y-axis.
Foci of an Ellipse
The foci of an ellipse are pivotal points that contribute to the definition and properties of an ellipse. They lie along the major axis and help in understanding the ellipse's geometric properties. From the equation \[ \frac{x^{2}}{9} + \frac{y^{2}}{36} = 1, \]we compute the foci using the formula \( c = \sqrt{b^2 - a^2} \) to find \( c = \sqrt{36 - 9} = 5 \). Therefore, the foci are located at \((0, 5)\) and \((0, -5)\) along the y-axis because the ellipse is vertical.
- The foci are symmetrical with respect to the center of the ellipse.
- They lie on the major axis of the ellipse, determining its overall shape and direction.
Other exercises in this chapter
Problem 1
In Exercises \(1-18,\) graph each ellipse and locate the foci. $$\frac{x^{2}}{16}+\frac{y^{2}}{4}=1$$
View solution Problem 2
In Exercises \(1-18,\) graph each ellipse and locate the foci. $$\frac{x^{2}}{25}+\frac{y^{2}}{16}=1$$
View solution Problem 4
In Exercises \(1-18,\) graph each ellipse and locate the foci. $$\frac{x^{2}}{16}+\frac{y^{2}}{49}=1$$
View solution Problem 5
In Exercises \(1-18,\) graph each ellipse and locate the foci. $$\frac{x^{2}}{25}+\frac{y^{2}}{64}=1$$
View solution