Problem 3
Question
In cold weather the temperature that we feel depends both on the actual air temperature and on whether the wind is blowing or not. Strong winds blow heat away from our bodies, increasing their rate of heat loss and making us feel colder, a phenomenon known as wind chill. In cold winters, weather forecasters report both the real temperature and the apparent temperature including wind chill. One widely used formula for the apparent temperature \(W\), when the air temperature (measured in \(\left.{ }^{\circ} \mathrm{F}\right)\) is \(T\), and the wind speed (measured in mph) is \(V\), is: $$W=35.74+0.6215 T-35.75 V^{0.16}+0.4275 T V^{0.16}$$ This formula is only accurate when \(T \leq 50^{\circ} \mathrm{F}\) and \(V \geq 3 \mathrm{mph}\). (a) Use \((10.2)\) to calculate the apparent temperatures felt by a person in each of the three following locations: (i) Boston in January \(\left(T=14^{\circ} \mathrm{F}, V=11 \mathrm{mph}\right)\) (ii) Minneapolis in January \(\left(T=23^{\circ} \mathrm{F}, V=13 \mathrm{mph}\right)\) (iii) Chicago in January \(\left(T=24^{\circ} \mathrm{F}, V=18 \mathrm{mph}\right)\) In which location will a person feel coldest? (b) In this part we will see the danger of trying to evaluate a function outside of its correct domain. Calculate the wind chill for Los Angeles in January \(\left(T=65^{\circ} \mathrm{F}, V=0.8 \mathrm{mph}\right) .\) [Note that these \((T, V)\) values are outside the domain for \(W(T, V) .]\) Does your answer make sense?
Step-by-Step Solution
VerifiedKey Concepts
Apparent Temperature
Wind Speed
Domain of Function
Calculation Steps
- First, identify the actual temperature (\(T\)) and the wind speed (\(V\)).
- Substitute these values into the formula \[ W = 35.74 + 0.6215T - 35.75V^{0.16} + 0.4275TV^{0.16} \]
- Perform the calculations by multiplying terms inside the formula.
- Solve each part step-by-step, and then combine them to find the final wind chill value (W).