Problem 3
Question
If \(y\) varies inversely as \(x\) and \(y=-14\) when \(x=12,\) find \(x\) when \(y=21\)
Step-by-Step Solution
Verified Answer
\(x = -8\)
1Step 1: Understand the Inverse Variation
When a variable \( y \) varies inversely as \( x \), it means \( y \cdot x = k \), where \( k \) is a constant. So, our main goal is to first find \( k \).
2Step 2: Find the Constant \( k \)
We know that \( y = -14 \) when \( x = 12 \). Substitute \( x = 12 \) and \( y = -14 \) into the inverse variation equation to find \( k \): \(-14 \cdot 12 = k\). So, \( k = -168 \).
3Step 3: Set Up the Equation with the New \(y\) Value
Now, we apply the value of \( k = -168 \) to find \( x \) when \( y = 21 \). Plug \( y = 21 \) into the inverse relationship: \( 21 \cdot x = -168 \).
4Step 4: Solve for \( x \)
Solve the equation \( 21x = -168 \). Divide both sides by 21 to isolate \( x \): \( x = \frac{-168}{21} \).
5Step 5: Simplify the Fraction
Simplifying \( \frac{-168}{21} \) gives \( x = -8 \). After division, you can verify that \( 21 \times -8 = -168 \).
Key Concepts
Understanding the Constant of VariationSolving Equations in Inverse VariationExploring Proportional Relationships
Understanding the Constant of Variation
In inverse variation problems, the constant of variation is a key concept. It's a number that remains unchanged as the variables change. Here, the relationship between the two variables is expressed through a multiplication equation:
- For inverse variation, the product of the variables is constant.
- The formula is: \( y \cdot x = k \)
Solving Equations in Inverse Variation
Solving equations in inverse variation involves finding unknown variable values using the constant of variation. Once \( k \) is determined, substitute any other known value and solve for the unknown:
- First, set up the equation using the known constant: if \( y \cdot x = k \), and \( y \) is known, solve for \( x \).
Exploring Proportional Relationships
In mathematics, understanding proportional relationships helps in comprehending inverse variations better. In inverse variations, although the two variables multiply to a constant, they don't increase or decrease together:
- If one variable increases, the other decreases to maintain the proportional constant.
- This is opposite to a direct proportional relationship, where the variables change in tandem.
Other exercises in this chapter
Problem 2
Simplify each expression. \(\frac{a+b}{a^{2}-b^{2}}\)
View solution Problem 3
Solve each equation. Check your solutions. $$ \frac{1}{x-1}+\frac{2}{x}=0 $$
View solution Problem 3
Graph each rational function. $$ f(x)=\frac{x}{x+1} $$
View solution Problem 3
Find the LCM of each set of polynomials. $$ x^{2}-2 x, x^{2}-4 $$
View solution