Problem 3
Question
(I) (a) What is the power of a 23.5 -cm-focal-length lens? (b) What is the focal length of a -6.75 -D lens? Are these lenses converging or diverging?
Step-by-Step Solution
Verified Answer
(a) Power is 4.26 D (converging lens). (b) Focal length is -0.148 m (diverging lens).
1Step 1: Understanding Lens Power
The power of a lens, denoted by \( P \), is given by the equation \( P = \frac{1}{f} \), where \( f \) is the focal length of the lens in meters. Here, the focal length of the given lens is 23.5 cm, which needs to be converted into meters for use in the formula.
2Step 2: Convert Focal Length to Meters
Convert 23.5 cm to meters by dividing by 100. Thus, \( f = \frac{23.5}{100} = 0.235 \) meters.
3Step 3: Calculate Power of the Lens
Use the formula \( P = \frac{1}{f} \) to find the power of the lens. Substitute \( f = 0.235 \) meters into the equation: \( P = \frac{1}{0.235} \approx 4.26 \) diopters. Since the power is positive, this indicates a converging lens.
4Step 4: Understanding Diopter Power and Focal Length
The power of a lens is also given in diopters (D), where \( P = \frac{1}{f} \). For part (b), we need to find the focal length given the power \( P = -6.75 \) D.
5Step 5: Calculate Focal Length from Diopters
Rearrange the formula from \( P = \frac{1}{f} \) to \( f = \frac{1}{P} \) to solve for the focal length. Substitute \( P = -6.75 \): \( f = \frac{1}{-6.75} \approx -0.148 \) meters.
6Step 6: Determine Lens Type
Since the power for part (b) is negative, the lens is a diverging lens. In general, a positive power indicates a converging lens, while a negative power indicates a diverging lens.
Key Concepts
Focal LengthConverging LensDiverging Lens
Focal Length
The focal length of a lens is an important concept in optics. It is defined as the distance between the center of the lens and the point where it converges or diverges light. This point is called the focal point. The focal length is measured in meters and plays a crucial role in determining the "power" of the lens.
For a given lens, focal length affects how much it bends light. A shorter focal length means light converges more quickly, while a longer one allows light to converge more gently. The formula for calculating the power of a lens using its focal length is:
Depending on whether the focal length is positive or negative, the nature of the lens can be determined. Positive focal lengths generally signify a converging lens, while negative focal lengths indicate a diverging lens.
For a given lens, focal length affects how much it bends light. A shorter focal length means light converges more quickly, while a longer one allows light to converge more gently. The formula for calculating the power of a lens using its focal length is:
- Power (P) of a lens is given by the equation: \[ P = \frac{1}{f} \]
Depending on whether the focal length is positive or negative, the nature of the lens can be determined. Positive focal lengths generally signify a converging lens, while negative focal lengths indicate a diverging lens.
Converging Lens
Converging lenses are often referred to as "positive lenses" due to their positive power. They are designed to bring parallel rays of light to a single focal point. This characteristic is useful in applications like magnifying glasses and cameras. Converging lenses usually have a thicker middle and thinner edges.
- The power of a converging lens is positive.
- These lenses are used to correct farsightedness.
- They cause parallel light rays to meet or "converge" at the lens’s focal point.
Diverging Lens
Unlike converging lenses, diverging lenses scatter light rays apart, making them appear to diverge from a common focal point on the opposite side of the lens. These lenses are also called "negative lenses" because they have a negative power value. They are often thinner in the middle and thicker at the edges.
- Diverging lenses are identified by their negative power.
- They correct nearsightedness by spreading out light before it reaches the eye.
- Parallel rays of light begin to spread out as they pass through the diverging lens, emerging on the other side as if coming from the focal point.
Other exercises in this chapter
Problem 2
(I) Sunlight is observed to focus at a point \(18.5 \mathrm{~cm}\) behind a lens. (a) What kind of lens is it? (b) What is its power in diopters?
View solution Problem 2
(1) Sunlight is observed to focus at a point 18.5 \(\mathrm{cm}\) behind a lens, \((a)\) What kind of lens is it? \((b)\) What is its power in dionters?
View solution Problem 4
(II) A certain lens focuses an object \(1.85 \mathrm{~m}\) away as an image \(48.3 \mathrm{~cm}\) on the other side of the lens. What type of lens is it and wha
View solution Problem 5
(II) A 105 -mm-focal-length lens is used to focus an image on the sensor of a camera. The maximum distance allowed between the lens and the sensor plane is \(13
View solution