Problem 3
Question
How many nanoseconds does it take light to travel 1.00 \(\mathrm{ft}\) in vacuum? (This result is a useful quantity to remember.)
Step-by-Step Solution
Verified Answer
It takes approximately 1.0167 nanoseconds for light to travel 1 foot in a vacuum.
1Step 1: Understanding the Speed of Light
The speed of light in a vacuum is a constant and denoted by the symbol \( c \). Its value is approximately \( c = 299,792,458 \) meters per second.
2Step 2: Convert Feet to Meters
We need to convert the distance from feet to meters. Since 1 foot is equal to 0.3048 meters, we have: \( 1 \text{ ft} = 0.3048 \text{ m} \).
3Step 3: Calculate the Time in Seconds
Time can be calculated using the formula \( \text{time} = \frac{\text{distance}}{\text{speed}} \). Substituting the values, we get: \[ \text{time} = \frac{0.3048 \text{ m}}{299,792,458 \text{ m/s}} \].
4Step 4: Calculate the Time in Seconds
Perform the division to find the time in seconds: \[ \text{time} \approx 1.0167 \times 10^{-9} \text{ s} \].
5Step 5: Convert Seconds to Nanoseconds
Since 1 nanosecond (ns) equals \( 10^{-9} \) seconds, we convert the time from seconds to nanoseconds: \[ 1.0167 \text{ ns} \].
Key Concepts
Physics Problem SolvingUnit ConversionTime CalculationSpeed in Vacuum
Physics Problem Solving
Solving physics problems involves breaking down a situation into manageable parts. This problem is about finding the time it takes for light to travel a certain distance. By understanding the constant nature of the speed of light in a vacuum, we can apply relevant formulas to calculate the desired result. Light travels incredibly fast, so it is important to use precise and systematic approaches when solving related problems.
To master this, you need to:
To master this, you need to:
- Comprehend the constants involved, like the speed of light (denoted as \(c\) and approximately equal to \(299,792,458\) meters per second).
- Identify what is asked, in this case, the time it takes for light to traverse one foot in a vacuum.
- Follow a systematic approach to apply mathematical and physics concepts, ensuring accuracy at each step.
Unit Conversion
Unit conversion is crucial when dealing with physics problems, especially when dealing with international and local measurement standards. In this exercise, our goal was to determine how long it takes light to travel a specified distance. The initial distance was given in feet but needed to be in meters, since scientific calculations typically utilize the metric system.
To perform the conversion:
To perform the conversion:
- Understand the conversion factor: 1 foot equals 0.3048 meters.
- Apply this factor to the distance in feet: \(1 \text{ ft} = 0.3048 \text{ m}\).
Time Calculation
Time calculation is a key element in finding out how long a process or event lasts. In our exercise, we used a formula to determine the time light takes to travel a given distance.The formula used is the fundamental equation: \[ \text{time} = \frac{\text{distance}}{\text{speed}} \]This involves dividing the distance (converted to meters) by the speed of light (\(299,792,458 \text{ m/s}\)). This results in the time in seconds: \[ \text{time} \approx 1.0167 \times 10^{-9} \text{ s} \]As it's evident, light travels very short distances in tiny fractions of a second.
By understanding this approach, you can tackle a variety of physics-based time problems, ranging from astronomical calculations to everyday time assessments.
By understanding this approach, you can tackle a variety of physics-based time problems, ranging from astronomical calculations to everyday time assessments.
Speed in Vacuum
The speed of light in a vacuum is a fundamental constant in physics. Denoted by \(c\), it is approximately \(299,792,458\) meters per second, an incredibly high speed that plays a critical role in the theories of relativity and quantum physics. In vacuum, light travels without interacting with matter, experiencing no resistance that could alter its velocity. This consistency makes it a reliable basis for scientific laws and equations.
- Understanding this constant allows for accurate predictions and measurements in various fields of science and technology.
- It serves as the ultimate speed limit in the universe, according to current physical theories.
Other exercises in this chapter
Problem 1
Starting with the definition 1 in. \(=2.54 \mathrm{cm},\) find the number of (a) kilometers in 1.00 mile and (b) feet in 1.00 \(\mathrm{km}\) .
View solution Problem 2
According to the label on a bottle of salad dressing, the volume of the contents is 0.473 liter (L). Using only the conversions \(1 \mathrm{L}=1000 \mathrm{cm}^
View solution Problem 4
The density of lead is 11.3 \(\mathrm{g} / \mathrm{cm}^{3} .\) What is this value in kilograms per cubic meter?
View solution Problem 5
The most powerful engine available for the classic 1963 Chevrolet Corvette Sting Ray developed 360 horsepower and had a displacement of 327 cubic inches. Expres
View solution