Problem 3
Question
How many amperes will a \(75.0\) -W lamp draw on a \(11 \overline{0}-\mathrm{V}\) line?
Step-by-Step Solution
Verified Answer
The lamp draws approximately 0.6818 amperes.
1Step 1: Understand the Formula
To find the current (in amperes) that the lamp draws, we need to use the formula relating power, voltage, and current: \[ P = V imes I \] where \( P \) is the power in watts, \( V \) is the voltage in volts, and \( I \) is the current in amperes.
2Step 2: Rearrange the Formula
We need to solve for the current \( I \). Rearrange the formula to isolate \( I \):\[ I = \frac{P}{V} \]
3Step 3: Substitute the Values
Now substitute the given values into the equation: \( P = 75.0 \) watts and \( V = 110 \) volts.\[ I = \frac{75.0}{110} \]
4Step 4: Calculate the Current
Perform the division to find the current:\[ I = 0.6818 \] amperes (rounded to four decimal places).
Key Concepts
Electrical Power FormulaCurrent CalculationVoltage and Current Relationship
Electrical Power Formula
Electrical power is an essential concept when dealing with electrical circuits. This formula helps us understand the relationship between power (P) in watts, voltage (V) in volts, and current (I) in amperes. The formula is as follows: \[ P = V \times I \].
Power (P) represents the rate at which energy is consumed or generated by a device.
Voltage (V) is the potential difference that drives electric charge through the circuit. Current (I) is the flow of electric charge.
Power (P) represents the rate at which energy is consumed or generated by a device.
Voltage (V) is the potential difference that drives electric charge through the circuit. Current (I) is the flow of electric charge.
- A higher voltage or current increases power consumption in a circuit.
- Power is crucial to understanding how much energy a device uses over time.
Current Calculation
Calculating the current in an electrical circuit is a straightforward process once you know the power and voltage.
From the Electrical Power Formula, we can derive the formula for current (I) as follows: \[ I = \frac{P}{V} \].
When performing the calculation, simply plug in the known values of power (P) and voltage (V) into the equation.
From the Electrical Power Formula, we can derive the formula for current (I) as follows: \[ I = \frac{P}{V} \].
When performing the calculation, simply plug in the known values of power (P) and voltage (V) into the equation.
- The unit for current is amperes (A).
- Ensure that you use consistent units such as watts for power and volts for voltage.
Voltage and Current Relationship
Voltage and current have a direct and crucial relationship in the context of electrical circuits. Ohm's Law and the Electrical Power Formula both illustrate these dynamics.
According to the Electrical Power Formula, current ( I ) is directly proportional to power ( P ) when voltage ( V ) is constant.
This means:
According to the Electrical Power Formula, current ( I ) is directly proportional to power ( P ) when voltage ( V ) is constant.
This means:
- Increasing voltage will lead to a higher current, assuming that power consumption remains unchanged.
- For any electrical device, balancing voltage and current is vital for optimal operation.
Other exercises in this chapter
Problem 2
What is the field magnitude of an electric field in which a negative charge of \(2.00 \times 10^{-8} \mathrm{C}\) experiences a force of \(0.0600 \mathrm{~N} ?\
View solution Problem 2
The force of repulsion between two identical positive charges is \(0.800 \mathrm{~N}\) when the charges are \(0.100 \mathrm{~m}\) apart. Find the value of each
View solution Problem 3
The emf of a battery is \(12.0 \mathrm{~V}\). If the internal resistance is \(0.300 \Omega\) and the voltage applied to the circuit is \(11.6 \mathrm{~V}\), wha
View solution Problem 3
An electric heater draws a maximum of \(14.0 \mathrm{~A}\). If its resistance is \(15.7 \Omega\), on what voltage is it operating?
View solution