Problem 3
Question
Graph each pair of parametric equations by hand, using values of tin \([-2,2] .\) Make a table of \(t_{*}, x_{*}\) and \(y\) -values, using \(t=-2,-1,0,1,\) and \(2 .\) Then plot the points and join them with a line or smooth curve for all values of \(t\) in \([-2,2] .\) Do not use a calculator. $$x=t+1, \quad y=t^{2}-1$$
Step-by-Step Solution
Verified Answer
Plot the points and connect them to form a parabola.
1Step 1: Set Up the Table
Create a table with three columns labeled \( t \), \( x \), and \( y \), and five rows corresponding to the values of \( t \) we will use: \(-2, -1, 0, 1,\) and \(2\).
2Step 2: Calculate x-values
Using the equation \( x = t + 1 \), calculate \( x \) for each \( t \) value in the range:- For \( t = -2 \), \( x = -2 + 1 = -1 \)- For \( t = -1 \), \( x = -1 + 1 = 0 \)- For \( t = 0 \), \( x = 0 + 1 = 1 \)- For \( t = 1 \), \( x = 1 + 1 = 2 \)- For \( t = 2 \), \( x = 2 + 1 = 3 \)
3Step 3: Calculate y-values
Using the equation \( y = t^2 - 1 \), calculate \( y \) for each \( t \) value:- For \( t = -2 \), \( y = (-2)^2 - 1 = 4 - 1 = 3 \)- For \( t = -1 \), \( y = (-1)^2 - 1 = 1 - 1 = 0 \)- For \( t = 0 \), \( y = (0)^2 - 1 = 0 - 1 = -1 \)- For \( t = 1 \), \( y = (1)^2 - 1 = 1 - 1 = 0 \)- For \( t = 2 \), \( y = (2)^2 - 1 = 4 - 1 = 3 \)
4Step 4: Fill in the Table
Combine your results to complete the table:\[\begin{array}{|c|c|c|}\hline t & x & y \\hline-2 & -1 & 3 \-1 & 0 & 0 \ 0 & 1 & -1 \ 1 & 2 & 0 \ 2 & 3 & 3 \\hline\end{array}\]
5Step 5: Plot the Points
Using the table, plot the points \((-1, 3)\), \((0, 0)\), \((1, -1)\), \((2, 0)\), and \((3, 3)\) on a graph. Each point corresponds to a \((x, y)\) pair derived from each \(t\) value.
6Step 6: Draw the Curve
Once all points are plotted, smoothly connect the points with either a straight line segment or a curve as indicated by the plotted points' pattern. This forms a part of a parabola.
Key Concepts
Graphing TechniquesCoordinate GeometryParabolic Curves
Graphing Techniques
Graphing techniques refer to the methods used to visually represent equations or data. When dealing with parametric equations, you often graph these by identifying key points on the graph based on a parameter, usually denoted as \( t \). To start:
- Create a table that involves the parameter \( t \) and corresponding \( x \) and \( y \) values.
- Choose a suitable range for \( t \). In our example, we use \([-2, 2]\).
- Compute the \( x \) and \( y \) values using the given parametric equations. Here, it's \( x = t + 1 \) and \( y = t^2 - 1 \).
- Plot the calculated points \((x, y)\) on a coordinate graph.
- Finally, connect these points smoothly to reflect the relationship the equations depict.
Coordinate Geometry
Coordinate geometry, also known as analytic geometry, uses algebraic equations to represent geometric shapes like lines, curves, and points in a 2D plane through coordinates like \((x, y)\). Here’s how you apply it to our problem:
- Parametric equations are translated into coordinate points by considering each parameter \( t \) as an instance.
- The calculated \( (x, y) \) pairs from the parametric equations are plotted in the 2D coordinate system.
- Each point on the plane represents a specific \( t \) value, allowing the graph of the parametric equations to unfold.
Parabolic Curves
A parabolic curve is a symmetrical, U-shaped curve. Parabolas are fundamental shapes seen in quadratic functions and parametric forms can often illustrate them. For our example:
- The equation \( y = t^2 - 1 \) itself describes a typical parabolic curve.
- The parameter \( t \) guides the curve's direction and shape on the graph.
- Our computed points, like \((1, -1)\) or \((3, 3)\), when plotted, and connected will form this familiar shape.
Other exercises in this chapter
Problem 2
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