Problem 3
Question
Give an example to show that the product of two imaginary numbers is not always imaginary.
Step-by-Step Solution
Verified Answer
The product of \( 2i \) and \( 3i \) is \(-6\), a real number.
1Step 1: Understanding Imaginary Numbers
Imaginary numbers are numbers of the form \( a + bi \), where \( a \) and \( b \) are real numbers and \( i \) is the imaginary unit, defined by \( i^2 = -1 \). Here, the term \( bi \) is the imaginary component.
2Step 2: Choosing Two Purely Imaginary Numbers
Let's consider two purely imaginary numbers \( z_1 = 2i \) and \( z_2 = 3i \). A purely imaginary number is one where the real part is zero (i.e., of the form \( 0 + bi \)).
3Step 3: Multiplying the Imaginary Numbers
To find the product \( z_1 \cdot z_2 \), use multiplication of complex numbers:\[(2i)(3i) = 2 \cdot 3 \cdot i^2 = 6i^2.\]
4Step 4: Simplifying the Product Using \( i^2 = -1 \)
Substitute \( i^2 = -1 \) into the equation:\[6i^2 = 6(-1) = -6.\]
5Step 5: Interpreting the Result
The result \( -6 \) is a real number, not an imaginary number. This shows that the product of two imaginary numbers can result in a real number.
Key Concepts
Complex NumbersPurely Imaginary NumbersMultiplication of Complex Numbers
Complex Numbers
Complex numbers are an intriguing mathematical concept that extends the idea of the traditional number line into a complex plane. These numbers take the form of \( a + bi \), where \( a \) and \( b \) are real numbers, and \( i \) is the imaginary unit. The imaginary unit \( i \) is defined by its unique property: \( i^2 = -1 \). This definition allows complex numbers to incorporate quantities that involve the square root of negative numbers.
- **Real Part**: The real part of a complex number is the \( a \) in \( a + bi \). It lies along the horizontal axis in the complex plane.- **Imaginary Part**: The imaginary part is \( bi \). This component defines the vertical position on the complex plane.
Complex numbers are essential in fields like engineering and physics as they effectively describe waveforms, oscillations, and alternating currents. They provide a comprehensive framework to solve equations that don't have real solutions, offering insights that are not possible in the realm of real numbers alone.
- **Real Part**: The real part of a complex number is the \( a \) in \( a + bi \). It lies along the horizontal axis in the complex plane.- **Imaginary Part**: The imaginary part is \( bi \). This component defines the vertical position on the complex plane.
Complex numbers are essential in fields like engineering and physics as they effectively describe waveforms, oscillations, and alternating currents. They provide a comprehensive framework to solve equations that don't have real solutions, offering insights that are not possible in the realm of real numbers alone.
Purely Imaginary Numbers
A purely imaginary number is a special type of complex number where the real part is zero. In mathematical terms, it can be expressed as \( 0 + bi \) or simply \( bi \). Here, \( b \) is a real number, and \( i \) is again the imaginary unit. Observing this form, it's clear that purely imaginary numbers contain only an imaginary component and are "imaginary" in their entirety.
For example:
For example:
- \( 2i \) is purely imaginary because it contains no real part.
- \( -3.5i \) is another example, where the coefficient of \( i \) is a real number (in this case, \(-3.5\)).
Multiplication of Complex Numbers
Multiplying complex numbers follows a specific set of rules similar to multiplying binomials, due to their extended form \( (a+bi) \). The crucial step is remembering the fundamental property \( i^2 = -1 \). This allows the conversion of imaginary parts into real ones when they are squared.
Here's a simple breakdown of how multiplication works:
Here's a simple breakdown of how multiplication works:
- Write both complex numbers in their standard form.
- Use the distributive property: \((a+bi)(c+di) = ac + adi + bci + bdi^2\).
- Since \( i^2 = -1 \), simplify: \( adi + bci + bdi^2 = (ac - bd) + (ad + bc)i \).
Other exercises in this chapter
Problem 3
Your friend tries to calculate the value \(-9^{\frac{3}{2}}\) and keeps getting an ERROR message. What mistake is he or she probably making?
View solution Problem 3
When we solve a quadratic equation by factoring, why do we move all terms to one side, having zero on the other side?
View solution Problem 3
If the total amount of money you had to invest was $$\$ 2,000$$and you deposit \(x\) amount in one investment, how can you represent the remaining amount?
View solution Problem 3
How do we recognize when an equation, for example \(y=4 x+3,\) will be a straight line (linear) when graphed?
View solution