Problem 3
Question
For Problems 1 through 9, simplify the following expressions. $$ \frac{\sqrt{2 x^{3}}+\sqrt{12 y^{3} x^{4}}}{\sqrt{6 y^{2} x^{5}}} $$
Step-by-Step Solution
Verified Answer
The simplified expression is \( \frac{\sqrt{x}(x + 2xy)}{y\sqrt{3x}} \)
1Step 1: Simplify the terms
\[ \frac{\sqrt{2 x^{3}}+\sqrt{12 y^{3} x^{4}}}{\sqrt{6 y^{2} x^{5}}} \] can be simplified by splitting each of the square roots.
2Step 2: Breaking down the square roots
\[ \frac{\sqrt{2 x^{3}}+\sqrt{12 y^{3} x^{4}}}{\sqrt{6 y^{2} x^{5}}} = \frac{x\sqrt{2x} + 2xy\sqrt{2x}}{yx\sqrt{6x}} \]. This was done by factoring out common factors and simplifying such as for \(\sqrt{12 y^{3} x^{4}} = 2xy\sqrt{2x}\) and for \(\sqrt{6 y^{2} x^{5}} = yx\sqrt{6x}\)
3Step 3: Simplify further
The expression \[ \frac{x\sqrt{2x} + 2xy\sqrt{2x}}{yx\sqrt{6x}} = \frac{\sqrt{2x}(x + 2xy)}{yx\sqrt{6x}} \] can be broken down further by factoring out \(\sqrt{2x}\) from the numerator. This way, we reduce the numerator to a single square root term.
4Step 4: Final Simplification
The expression can be turned into \( \frac{\sqrt{2x}(x + 2xy)}{yx\sqrt{6x}} = \frac{\sqrt{x}(x + 2xy)}{y\sqrt{3x}} \) by simplifying the denominator \(\sqrt{6x} = \sqrt{3x}\)
Key Concepts
Radical ExpressionsSimplifying Square RootsAlgebraic Fractions
Radical Expressions
Radical expressions are mathematical expressions that involve roots, the most common of which are square roots. Simplifying these expressions is a foundational skill in algebra that allows for easier manipulation and understanding of equations. To simplify a radical expression, one generally looks for factors within the radicand (the number under the root) that are perfect squares, as these can be taken out of the radical.
For instance, in the given exercise, \[\sqrt{12 y^{3} x^{4}}\] can be simplified because it contains the perfect square \(x^{4}\), which is \(x^2\) squared, and the number 12, which is \(4\) times \(3\) — with \(4\) being a perfect square. Thus, the expression can be broken down to \(2x^2\) times the square root of the remaining factors. By recognizing these perfect squares, we create simpler expressions that are easier to work with in equations.
For instance, in the given exercise, \[\sqrt{12 y^{3} x^{4}}\] can be simplified because it contains the perfect square \(x^{4}\), which is \(x^2\) squared, and the number 12, which is \(4\) times \(3\) — with \(4\) being a perfect square. Thus, the expression can be broken down to \(2x^2\) times the square root of the remaining factors. By recognizing these perfect squares, we create simpler expressions that are easier to work with in equations.
Simplifying Square Roots
When simplifying square roots, the goal is to find the largest square factor of the radicand and separate it from the rest of the expression. This process often involves prime factorization or recognizing common squares. For the expression \[\sqrt{2 x^{3}}\], we see that \(x^3\) can be written as \(x^2\) times \(x\), allowing us to pull out an \(x\) from under the square root since \(x^2\) is a perfect square.
Similarly, \(\sqrt{12 y^{3} x^{4}}\) simplifies to \(2xy\sqrt{2y}\) by taking out \(\sqrt{x^4}\) as \(x^2\) and \(\sqrt{4y^2}\) as \(2y\). The square root of the leftover product, \(2y\), remains under the radical. It's critical to isolate the largest square factors possible to maximize simplification.
Similarly, \(\sqrt{12 y^{3} x^{4}}\) simplifies to \(2xy\sqrt{2y}\) by taking out \(\sqrt{x^4}\) as \(x^2\) and \(\sqrt{4y^2}\) as \(2y\). The square root of the leftover product, \(2y\), remains under the radical. It's critical to isolate the largest square factors possible to maximize simplification.
Algebraic Fractions
Algebraic fractions, also called rational expressions, are fractions that contain polynomials in the numerator, the denominator, or both. Simplifying these expressions often involves factoring polynomials, canceling common factors, and applying the properties of exponents. In our example, we have an algebraic fraction with radicals in both the numerator and denominator.
The process starts with simplifying the individual square roots in the numerator and the denominator before combining terms. For the given exercise, after breaking down the square roots separately, we can combine like terms in the numerator by factoring out the common \(\sqrt{2x}\), as shown in Step 3. Finally, we ensure that any common factors between numerator and denominator are simplified. Taking care when simplifying the individual terms is crucial to ensuring accuracy throughout the process, and applying these principles correctly leads to a simpler and more manageable expression.
The process starts with simplifying the individual square roots in the numerator and the denominator before combining terms. For the given exercise, after breaking down the square roots separately, we can combine like terms in the numerator by factoring out the common \(\sqrt{2x}\), as shown in Step 3. Finally, we ensure that any common factors between numerator and denominator are simplified. Taking care when simplifying the individual terms is crucial to ensuring accuracy throughout the process, and applying these principles correctly leads to a simpler and more manageable expression.
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