Problem 3
Question
For Problems 1-36, graph each linear equation. (Objective 2) $$ x-y=3 $$
Step-by-Step Solution
Verified Answer
Graph the line with slope 1 through points (0,-3) and (1,-2).
1Step 1: Solve for y
To graph a line, it's often easiest to express the equation in slope-intercept form, where it reads as \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept. Start by solving the equation \(x-y=3\) for \(y\).\[ x - y = 3 \] Subtract \(x\) from both sides to isolate \(-y\):\[ -y = -x + 3 \] Multiply through by \(-1\) to solve for \(y\):\[ y = x - 3 \]. This is now in the form \(y = mx + b\), with \(m = 1\) and \(b = -3\).
2Step 2: Identify the Slope and Y-intercept
From the equation \(y = x - 3\), identify the slope \(m\) and the y-intercept \(b\). The slope \(m = 1\), which means the line rises by 1 unit for every 1 unit it moves to the right. The y-intercept \(b = -3\) indicates that the line crosses the y-axis at \(y = -3\).
3Step 3: Plot the Y-intercept
Start by plotting the y-intercept on the graph. Locate \(y = -3\) on the y-axis and place a point there. This represents the point \((0, -3)\) on the Cartesian plane, where the line crosses the y-axis.
4Step 4: Use the Slope to Find Another Point
Using the slope \(m = 1\), find another point on the line. Since the slope is 1, from the y-intercept \((0, -3)\), move up 1 unit and 1 unit to the right to reach \((1, -2)\). Plot this point on the graph.
5Step 5: Draw the Line
Using a ruler, draw a straight line through the two points \((0, -3)\) and \((1, -2)\). Extend the line across the graph in both directions, ensuring it intersects the y-axis where it should.
Key Concepts
Graphing Linear EquationsSlope-Intercept FormY-InterceptFinding Slope
Graphing Linear Equations
Graphing linear equations allows us to visually represent relationships between two variables on a coordinate plane. When we graph a linear equation, we typically look for two things: the slope and the y-intercept, which tell us the incline and starting point of the line, respectively.
To graph a line like in the original exercise, you'll usually start with the equation in one of the standard forms, with the slope-intercept form being the most straightforward for graphing. The goal is to find points that the line passes through and then draw a straight line that connects these points.
Here's a simple approach to graphing a line:
To graph a line like in the original exercise, you'll usually start with the equation in one of the standard forms, with the slope-intercept form being the most straightforward for graphing. The goal is to find points that the line passes through and then draw a straight line that connects these points.
Here's a simple approach to graphing a line:
- Solve for "y" to get the equation in the slope-intercept form, if needed.
- Identify the y-intercept and plot it on the y-axis.
- Use the slope to find at least one more point on the line.
- Draw a straight line through the points.
Slope-Intercept Form
The slope-intercept form of a linear equation is expressed as \( y = mx + b \), where \( m \) represents the slope and \( b \) denotes the y-intercept. This form is incredibly useful for graphing because it gives us both the angle of the line and where it crosses the y-axis directly.
Knowing the slope-intercept form allows you to graph a line quickly by following these easy steps:
For example, in the exercise's equation \( y = x - 3 \), the slope \( m = 1 \) tells us the line moves up and right at the same rate, and the y-intercept \( b = -3 \) points to its crossing at \( y = -3 \).
This concise form makes it easier to interpret and plot linear equations.
Knowing the slope-intercept form allows you to graph a line quickly by following these easy steps:
- Identify \( m \), the slope, to understand the slant of the line: how much it rises or falls as you move along the x-axis.
- Identify \( b \), the y-intercept, to know where the line crosses the y-axis, which is a key point to plot.
For example, in the exercise's equation \( y = x - 3 \), the slope \( m = 1 \) tells us the line moves up and right at the same rate, and the y-intercept \( b = -3 \) points to its crossing at \( y = -3 \).
This concise form makes it easier to interpret and plot linear equations.
Y-Intercept
The y-intercept is a vital element in understanding linear equations. It is the point where the line crosses the y-axis, represented in the slope-intercept form as \( b \).
Here's how the y-intercept helps you when graphing:
Here's how the y-intercept helps you when graphing:
- The value of \( b \) tells you the exact point on the y-axis where the line will pass through, meaning when the x-value is zero, the y-value is \( b \).
- In the example given, the y-intercept is \( -3 \), meaning the point \( (0, -3) \) lies on the graph.
Finding Slope
The concept of slope is central to understanding how a line behaves and how steep it is. The slope is represented by \( m \) in the slope-intercept form \( y = mx + b \) and describes the line's inclination.
To determine the slope:
The slope makes it easy to find other points on the line. Starting from the y-intercept, apply the rise-over-run approach to find another point, ensuring accuracy in the graph you create. This understanding is key to effectively plotting and interpreting linear graphs.
To determine the slope:
- Analyze how much the line rises vertically for every unit it moves horizontally.
- This is often written as \( \frac{\text{rise}}{\text{run}} \).
The slope makes it easy to find other points on the line. Starting from the y-intercept, apply the rise-over-run approach to find another point, ensuring accuracy in the graph you create. This understanding is key to effectively plotting and interpreting linear graphs.
Other exercises in this chapter
Problem 3
Find the equation of the line that contains the given point and has the given slope. Express equations in the form \(A x+B y=C\), where \(A, B\), and \(C\) are
View solution Problem 3
For Problems 1-12, find the equation of the line that contains the given point and has the given slope. Express equations in the form \(A x+B y=C\), where \(A,
View solution Problem 3
Use the elimination-by-addition method to solve each system. $$\left(\begin{array}{l}6 x-7 y=15 \\ 6 x+5 y=-21\end{array}\right)$$
View solution Problem 3
Find the slope of the line determined by each pair of points. $$(-1,3),(-6,-4)$$
View solution