Problem 3
Question
For each statement, write an equivalent statement in logarithmic form. Do not use a calculator. $$\left(\frac{1}{2}\right)^{-4}=16$$
Step-by-Step Solution
Verified Answer
Equivalent logarithmic form is \( \log_{\frac{1}{2}}(16) = -4 \).
1Step 1: Understand the Exponential Form
The given statement in exponential form is \( \left(\frac{1}{2}\right)^{-4}=16 \). This means we have a base \( \frac{1}{2} \), an exponent \( -4 \), and the result is \( 16 \).
2Step 2: Recall the Logarithmic Form
The general form to convert an exponential statement \( b^x = y \) to logarithmic form is \( \log_b(y) = x \). Here, \( b \) is the base, \( x \) is the exponent, and \( y \) is the result.
3Step 3: Apply the Conversion
Using the form \( \log_b(y) = x \), identify \( b = \frac{1}{2} \), \( y = 16 \), and \( x = -4 \). Substituting these values into the logarithmic form gives us \( \log_{\frac{1}{2}}(16) = -4 \).
Key Concepts
Exponential FormBase and ExponentConversion Between Logarithms and Exponents
Exponential Form
The exponential form is a way to write numbers that have been raised to a power, where this structure is expressed as \( b^x = y \). Here, \( b \) represents the base, \( x \) is the exponent, and \( y \) is the result. For example, in the statement \( \left(\frac{1}{2}\right)^{-4} = 16 \), \( \frac{1}{2} \) is the base, \( -4 \) is the exponent, and 16 is the result.
Understanding exponential form is crucial because it allows you to express large numbers compactly or to break down complex calculations. The base tells you the number that is multiplied by itself, whereas the exponent tells you how many times the base is used as a factor. In this context, having a negative exponent like \(-4\) means you are taking the reciprocal of the base raised to the positive exponent.
This form is very useful in various math and science disciplines to describe exponential growth, decay, and other phenomena in a simplified manner.
Understanding exponential form is crucial because it allows you to express large numbers compactly or to break down complex calculations. The base tells you the number that is multiplied by itself, whereas the exponent tells you how many times the base is used as a factor. In this context, having a negative exponent like \(-4\) means you are taking the reciprocal of the base raised to the positive exponent.
This form is very useful in various math and science disciplines to describe exponential growth, decay, and other phenomena in a simplified manner.
Base and Exponent
In mathematical expressions involving exponents, the base and the exponent play critical roles. The base is the number that is multiplied by itself, and the exponent tells us how many times to perform this multiplication. Let's take a closer look using \( \left(\frac{1}{2}\right)^{-4} \) as an example:
- Base: The base here is \( \frac{1}{2} \). It's the number you start with before applying the power of the exponent.
- Exponent: The exponent is \(-4\). Because it is negative, it means you take the reciprocal of the base raised to the opposite positive power. So, \( \left(\frac{1}{2}\right)^{-4} \) becomes \( 2^4 \).
Conversion Between Logarithms and Exponents
Converting between exponential and logarithmic forms is an essential skill in mathematics. It can often simplify solving equations and understanding relationships between numbers. The conversion makes use of the fact that logarithms can be thought of as the inverse operation of exponentiation.
For any exponential expression \( b^x = y \), you can convert this to a logarithmic expression using the formula \( \log_b(y) = x \). The base \( b \) stays the same, \( y \) becomes the number you find the log of, and \( x \) is the result of the logarithm. In our context, with the exponential form \( \left(\frac{1}{2}\right)^{-4} = 16 \), you can easily transform this to the logarithmic form as \( \log_{\frac{1}{2}}(16) = -4 \).
For any exponential expression \( b^x = y \), you can convert this to a logarithmic expression using the formula \( \log_b(y) = x \). The base \( b \) stays the same, \( y \) becomes the number you find the log of, and \( x \) is the result of the logarithm. In our context, with the exponential form \( \left(\frac{1}{2}\right)^{-4} = 16 \), you can easily transform this to the logarithmic form as \( \log_{\frac{1}{2}}(16) = -4 \).
- This transformation shows you that the logarithm gives the exponent to which the base must be raised to get the given result.
- With this understanding, operations like solving for unknown exponents or bases become more intuitive.
Other exercises in this chapter
Problem 2
Solve each equation. Express all solutions in exact form. Do not use a calculator. $$\frac{1}{2} e^{x}=13$$
View solution Problem 2
Graph each function. Do not use a calculator. $$f(x)=4^{x}$$
View solution Problem 3
Solve each equation. Express all solutions in exact form. Do not use a calculator. $$2\left(10^{x}\right)=14$$
View solution Problem 3
Graph each function. Do not use a calculator. $$f(x)=\left(\frac{1}{3}\right)^{x}$$
View solution