Problem 3

Question

Finish the proof of Proposition 2.3.6. That is, suppose \(\left\\{x_{n}\right\\}\) is a bounded sequence and \(\left\\{x_{n_{k}}\right\\}\) is a subsequence. Prove \(\liminf _{n \rightarrow \infty} x_{n} \leq \liminf _{k \rightarrow \infty} x_{n_{k}}\).

Step-by-Step Solution

Verified
Answer
Thus, \( \liminf_{n \to \infty} x_n \leq \liminf_{k \to \infty} x_{n_k} \).
1Step 1: Understand the Definition of Lim Inf
The limit inferior (lim inf) of a sequence \( \{x_n\} \) as \( n \to \infty \) is defined as the greatest lower bound (infimum) of the set of all subsequential limits of \( \{x_n\} \). For the subsequence \( \{x_{n_k}\} \), the lim inf as \( k \to \infty \) is similarly defined. We need to show \( \liminf_{n \to \infty} x_n \leq \liminf_{k \to \infty} x_{n_k} \).
2Step 2: Identify the Limit Inferior of the Subsequence
Consider the subsequence \( \{x_{n_k}\} \). Because \( \{x_{n_k}\} \) is a subsequence of \( \{x_n\} \), any limit point of \( \{x_{n_k}\} \) is also a limit point of \( \{x_n\} \). Define \( L = \liminf_{k \to \infty} x_{n_k} \). By definition, for any \( \varepsilon > 0 \), there exists a \( K \) such that for all \( k \geq K \), \( x_{n_k} > L - \varepsilon \).
3Step 3: Connect the Sequence and Subsequences
Since \( x_{n_k} \) are terms of \( x_n \) itself, the values \( x_{n_k} > L - \varepsilon \) imply that there are infinitely many \( n \) such that \( x_n > L - \varepsilon \). Therefore, \( L - \varepsilon \) cannot be a strict upper bound on the values of \( x_n \) approaching lim inf. By definition of \( \liminf \), this implies \( \liminf_{n \to \infty} x_n \leq L = \liminf_{k \to \infty} x_{n_k} \).
4Step 4: Formalize the Proof
Let \( \liminf_{n \to \infty} x_n = a \) and \( \liminf_{k \to \infty} x_{n_k} = L \). Assume for contradiction that \( a > L \). Then there exists \( \varepsilon > 0 \) such that \( a \geq L + \varepsilon \). The definition of \( a \) as the greatest lower bound implies all subsequential limits of \( x_n \) are at least \( a \). Hence, \( \liminf_{k \to \infty} x_{n_k} < a \), a contradiction. Therefore, \( a \leq L \).

Key Concepts

Limit InferiorSubsequenceBounded SequenceSubsequential Limits
Limit Inferior
The concept of limit inferior, often written as \( \liminf_{n \rightarrow \infty} x_n \), is fundamental in real analysis. It provides insight into the behavior of a sequence as it progresses towards infinity.
Essentially, the limit inferior of a sequence \( \{x_n\} \) is the greatest lower bound (or infimum) of the set composed of all subsequential limits. It captures the lowest value that subsequences of \( \{x_n\} \) can converge to.
  • This means that no subpart of the entire sequence can limit to a value lying below this bound.
  • Understanding \( \liminf \) helps in analyzing the "floor" of subsequential behavior in extended sequences.

  • As such, in our proposition, we need to demonstrate \( \liminf_{n \to \infty} x_n \leq \liminf_{k \to \infty} x_{n_k} \) to understand how the sequence and its subsequences are intrinsically linked.
Subsequence
In real analysis, subsequences are key to revealing the hidden properties within sequences. A subsequence is derived by selecting elements from a sequence but in the same order as the original.
For instance, from a sequence \( \{x_n\} \), we can form a subsequence \( \{x_{n_k}\} \) by choosing indices that are strictly increasing. This means that each term \( x_{n_k} \) comes from \( \{x_n\} \) at positions determined stepwise from a selection process.
  • Subsequences can provide insight into the behavior of the original sequence, especially when looking for convergence properties.
  • Understanding subsequences is crucial as they form the building blocks for complex analysis in sequences.

  • Because subsequences inherit properties from their parent sequence, analyzing \( \{x_{n_k}\} \) unravels further information about \( \{x_n\} \), particularly in exploring convergence to particular limits, such as \( \liminf \).
Bounded Sequence
A bounded sequence is an essential type of sequence in real analysis where all terms lie within a fixed range. Specifically, a sequence \( \{x_n\} \) is bounded if there exists a real number \( M \) such that for all indices \( n \), \(|x_n| \leq M\).
This property ensures that the sequence doesn't deviate too wildly but instead remains within a predictable framework.
  • Boundedness is critical because it can imply the existence of convergent subsequences; a result from the Bolzano-Weierstrass theorem.
  • In practical terms, a bounded sequence assures us that the behavior of the sequence, and hence its subsequences, is controlled and predictable.

  • When addressing our proposition, the bounded nature of \( \{x_n\} \) guarantees that its behavior, especially involving limit infimum and subsequent subsequences, remains stable and analysable.
Subsequential Limits
Subsequential limits are the limiting points reached by subsequences of a given sequence \( \{x_n\} \). They represent the distinct values that various extracted subsequences can converge to.
Understanding subsequential limits is particularly valuable because not all sequences converge to a single limit. Instead, they might contain a variety of converging subtrajectories.
  • Subsequential limits highlight the versatility and complexity within sequences; showcasing stability or oscillations.
  • These limits are instrumental in determining the \( \liminf \) and \( \limsup \), as they contribute to finding the greatest lower or least upper bounds, respectively.

  • In our exercise, exploring the subsequential limits helps prove \( \liminf_{n \to \infty} x_n \leq \liminf_{k \to \infty} x_{n_k} \), by demonstrating how the sequence \( \{x_n\} \) and its subsequences \( \{x_{n_k}\} \) interact through their converging behaviors.