Problem 3
Question
Find values of the trigonometric functions of the angle (in standard position) whose terminal side passes through the given points. For Exercises \(3-14,\) give answers in exact form. For Exercises 15 and \(16,\) the coordinates are approximate. $$(6,8)$$
Step-by-Step Solution
Verified Answer
\( \sin(\theta) = \frac{4}{5}, \cos(\theta) = \frac{3}{5}, \tan(\theta) = \frac{4}{3} \).
1Step 1: Understand the Problem
We need to find the sine, cosine, and tangent of the angle whose terminal side passes through the point (6,8). This means that the angle is in the standard position where the initial side is along the positive x-axis.
2Step 2: Determine the Quadrant
Since both the x-coordinate (6) and the y-coordinate (8) are positive, the terminal side is in the first quadrant.
3Step 3: Find the Hypotenuse
The point (6,8) and the origin (0,0) form a right triangle. Use the Pythagorean theorem to find the hypotenuse: \( r = \sqrt{x^2 + y^2} = \sqrt{6^2 + 8^2} = \sqrt{36 + 64} = \sqrt{100} = 10 \).
4Step 4: Calculate Sine of the Angle
The sine of the angle is the ratio of the opposite side to the hypotenuse: \( \sin(\theta) = \frac{y}{r} = \frac{8}{10} = \frac{4}{5} \).
5Step 5: Calculate Cosine of the Angle
The cosine of the angle is the ratio of the adjacent side to the hypotenuse: \( \cos(\theta) = \frac{x}{r} = \frac{6}{10} = \frac{3}{5} \).
6Step 6: Calculate Tangent of the Angle
The tangent of the angle is the ratio of the opposite side to the adjacent side: \( \tan(\theta) = \frac{y}{x} = \frac{8}{6} = \frac{4}{3} \).
7Step 7: Verify the Results
Ensure that the calculated values are consistent with the conditions of the first quadrant, where both sine and cosine are positive.
Key Concepts
Pythagorean theoremright trianglestandard position angle
Pythagorean theorem
The Pythagorean theorem is a fundamental principle in geometry, especially useful when dealing with right triangles. It states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides. The formula looks like this: \[a^2 + b^2 = c^2\]where \( a \) and \( b \) are the lengths of the two legs, and \( c \) is the hypotenuse.
When encountering a point like \((6, 8)\), this point describes the legs of a right triangle when connected back to the origin \((0, 0)\) on a coordinate plane. Here:
When encountering a point like \((6, 8)\), this point describes the legs of a right triangle when connected back to the origin \((0, 0)\) on a coordinate plane. Here:
- \( x = 6 \) represents the horizontal leg
- \( y = 8 \) represents the vertical leg
right triangle
A right triangle is characterized by having one of its angles as a right angle, which is exactly \(90^\circ\). In the context of the problem, right triangles appear naturally when you draw a line from the origin to a point on the plane.
With the corners of the triangle positioned at the origin \((0,0)\), the x-coordinate \((6)\), and the y-coordinate \((8)\), the right angle is located at the origin:
With the corners of the triangle positioned at the origin \((0,0)\), the x-coordinate \((6)\), and the y-coordinate \((8)\), the right angle is located at the origin:
- The leg along the x-axis: \(AB = 6\)
- The leg along the y-axis: \(BC = 8\)
- Hypotenuse formed: \(AC = 10\)
- Sine: \( \sin(\theta) = \frac{8}{10} = \frac{4}{5} \)
- Cosine: \( \cos(\theta) = \frac{6}{10} = \frac{3}{5} \)
- Tangent: \( \tan(\theta) = \frac{8}{6} = \frac{4}{3} \)
standard position angle
An angle in standard position is one of the basics of trigonometry. It's an angle situated with its vertex at the origin of the coordinate plane. Here, the initial side of the angle is lined up along the positive x-axis. This is particularly important because this setup standardizes how angles are measured and understood, especially when calculating trigonometric functions.
For an angle in standard position:
For an angle in standard position:
- The rotation towards the terminal side determines the angle. Counter-clockwise is positive.
- Since the point \((6, 8)\) lies in the first quadrant, where both coordinates are positive, the angle's terminal side lies here as well.
- All trigonometric functions are positive.
- This provides a simplified environment to calculate the sine, cosine, and tangent values.
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