Problem 3
Question
Find the value of the following expressions when \(x=2, y=-2,\) and \(z=-5\). $$ \frac{y^{3}}{y^{2}-1} $$
Step-by-Step Solution
Verified Answer
The value of the expression is \(-\frac{8}{3}\).
1Step 1: Substitute Values
First, substitute the given values of \(y\) and \(z\) into the expression. Since \(x\) is not in the expression, we only substitute \(y=-2\) into \(\frac{y^{3}}{y^{2}-1}\).
2Step 2: Calculate the Numerator
The numerator of the expression is \(y^3\). Substitute \(y = -2\) to get \((-2)^3 = -8\).
3Step 3: Calculate the Denominator
The denominator of the expression is \(y^2 - 1\). Substitute \(y = -2\) to calculate \((-2)^2 - 1 = 4 - 1 = 3\).
4Step 4: Solve the Expression
Now that we have the values for the numerator and the denominator, substitute them into the expression: \(\frac{-8}{3}\).
5Step 5: Simplify the Fraction
The fraction \(\frac{-8}{3}\) is already in its simplest form as the numerator and the denominator do not have any common factors other than 1.
Key Concepts
Substitution MethodExponentsSimplifying Fractions
Substitution Method
The substitution method is an essential technique in algebra, especially when solving expressions with variables. To use this method, we replace each variable with its given value. In the problem at hand, we need to find the value of \[ \frac{y^{3}}{y^{2}-1} \] when \(y = -2\). Here, the variable \(y\) is given a specific integer value. By substituting \(-2\) for \(y\), you craft a numeric equation instead of one with multiple abstract variables. This makes operations like addition, subtraction, multiplication, and division easier to perform as they are now numeric rather than algebraic.
Exponents
Exponents are a shorthand way of expressing repeated multiplication. For example, \(y^3\) means \(y\) is multiplied by itself three times. In this exercise, after substituting \(y = -2\), we calculate:
- \((-2)^3\): This means multiplying \(-2\) by itself three times, equalling \(-2 \times -2 \times -2 = -8\).
- \((-2)^2\): This involves multiplying \(-2\) by itself two times, which calculates as \(-2 \times -2 = 4\).
Simplifying Fractions
Simplifying fractions involves reducing them to their simplest form. In this problem, we obtained the fraction \[ \frac{-8}{3} \] after substituting and evaluating both the numerator \((-8)\) and the denominator \(3\). A fraction is simplified when the numerator and the denominator have no common factors other than 1. Here:
- The greatest common divisor of \(-8\) and \(3\) is 1.
- Since the numbers are relatively prime, \(\frac{-8}{3}\) is the most simplified version of the fraction.
Other exercises in this chapter
Problem 2
Perform each indicated operation. Simplify if possible. \(\frac{15}{7 a}+\frac{8}{6 a}\)
View solution Problem 3
$$ \frac{4 m}{3 n}+\frac{5 m}{3 n} $$
View solution Problem 3
Simplify each complex fraction. $$ \frac{-\frac{4 x}{9}}{-\frac{2 x}{3}} $$
View solution Problem 3
Find each product and simplify if possible. See Examples 1 through 3. $$ \frac{8 x}{2} \cdot \frac{x^{5}}{4 x^{2}} $$
View solution