Problem 3

Question

Find the Maclaurin polynomial of order 4 for \(f(x)\) and use it to approximate \(f(0.12) .\) $$ f(x)=\sin 2 x $$

Step-by-Step Solution

Verified
Answer
The Maclaurin polynomial of order 4 is \(2x - \frac{4x^3}{3}\), and \(f(0.12) \approx 0.237696\).
1Step 1: Understand the Maclaurin Series
The Maclaurin series for a function \(f(x)\) is a Taylor series about \( x = 0 \). It is given by: \[ f(x) = f(0) + f'(0)x + \frac{f''(0)x^2}{2!} + \frac{f'''(0)x^3}{3!} + \frac{f^{(4)}(0)x^4}{4!} + \cdots \] For this problem, we need terms up to \(x^4\).
2Step 2: Differentiate the Function
Calculate the first four derivatives of \(f(x) = \sin(2x)\):\[ f'(x) = 2\cos(2x), \quad f''(x) = -4\sin(2x), \quad f'''(x) = -8\cos(2x), \quad f^{(4)}(x) = 16\sin(2x) \]
3Step 3: Evaluate the Derivatives at x = 0
Substitute \(x = 0\) into each derivative:\[ f(0) = \sin(0) = 0, \quad f'(0) = 2\cos(0) = 2, \quad f''(0) = -4\sin(0) = 0, \quad f'''(0) = -8\cos(0) = -8, \quad f^{(4)}(0) = 16\sin(0) = 0 \]
4Step 4: Construct the Maclaurin Polynomial
Using the derivatives evaluated at 0, construct the polynomial:\[ P_4(x) = 0 + 2\cdot x + 0\cdot \frac{x^2}{2} + (-8)\cdot \frac{x^3}{6} + 0\cdot \frac{x^4}{24} \]Simplify: \[ P_4(x) = 2x - \frac{4x^3}{3} \]
5Step 5: Approximate f(0.12)
Substitute \(x = 0.12\) into the polynomial:\[ P_4(0.12) = 2(0.12) - \frac{4(0.12)^3}{3} \]Calculate each term:\[ = 0.24 - \frac{4 \times 0.001728}{3} \]\[ = 0.24 - 0.002304 \]\[ = 0.237696 \]

Key Concepts

Taylor seriesPolynomial approximationTrigonometric functionsDifferentiation
Taylor series
The Taylor series is a mathematical tool that represents a function as an infinite sum of terms. Each term is derived from the derivatives of the function at a single point. For a function centered at zero, this series is known as the Maclaurin series.
This series allows us to approximate complex functions using simpler polynomial expressions. Taylor series can transform intricate function behaviors into a straightforward summation of polynomial terms:
  • It is versatile and can approximate any smooth and continuous function.
  • The convergence of the series depends on the function itself.
  • This method calculates each term using derivatives of increasing order.
For practical calculations, only a finite number of terms are used. By choosing an appropriate number of terms, the approximation becomes increasingly accurate.
Polynomial approximation
Polynomial approximation involves using a polynomial to estimate a function. This approximation is beneficial, especially when dealing with functions that are difficult to analyze or compute directly.
Through polynomial approximation, complex functions, such as trigonometric or exponential ones, become more manageable. This is achieved by using truncated versions of Taylor or Maclaurin series, which can be calculated by considering only a finite number of terms from these series. Specifically for this exercise:
  • An order 4 Maclaurin polynomial provides a balance between simplicity and accuracy.
  • Higher order polynomials yield better approximations over a wider range.
  • For small input values, lower order terms significantly contribute to the approximation.
This method allows us to handle and solve real-life problems with a higher computational efficiency.
Trigonometric functions
Trigonometric functions, like sine and cosine, are fundamental in various fields of mathematics and science due to their periodic nature.
In this scenario, we have the function \(f(x) = \sin 2x\), which is a sine function with altered frequency. To apply polynomial approximations effectively:
  • Trigonometric functions often require polynomial representation for ease of calculation.
  • Derivatives of these functions are cyclic and follow specific patterns.
  • As derivatives of sine functions are linear combinations of sine and cosine, they simplify the process of generating polynomial terms.
These approximations are crucial when working with trigonometric identities or solving differential equations analytically. As these functions inherently repeat values, polynomial approximations can represent them accurately within specific intervals.
Differentiation
Differentiation refers to the process of finding a derivative, signifying how a function changes at any given point.
In constructing a Maclaurin series, derivatives of the function at the point of interest are paramount. For the function \(f(x) = \sin 2x\), the process involves computing up to the fourth derivative:
  • The first derivative, \(f'(x) = 2\cos(2x)\), indicates the rate of change of the sine function.
  • Subsequent derivatives exhibit alternating patterns, reflecting the inherent properties of trigonometric functions.
  • Evaluating these derivatives at \(x = 0\) simplifies calculations as many terms tend to zero.
Comprehending differentiation extends beyond just processing derivatives. It also involves understanding the behavior and characteristics of the original function. This foundation is essential in determining precise polynomial coefficients that make the series meaningful and accurate.