Problem 3
Question
Find the indefinite integral, and check your answer by differentiation. $$ \int\left(3-2 x+x^{2}\right) d x $$
Step-by-Step Solution
Verified Answer
The indefinite integral of the given function is:
\[
\int(3-2x+x^{2})\, dx = \frac{x^3}{3} - x^2 + 3x + C
\]
1Step 1: Integrate each term separately
We will integrate each term in the polynomial separately: \(3\), \(-2x\), and \(x^2\).
2Step 2: Integrate the constant term \(3\)
The indefinite integral of a constant is simply the constant multiplied by the independent variable:
\[
\int 3 \, dx = 3x + C_1
\]
where \(C_1\) is the constant of integration for this term.
3Step 3: Integrate the linear term \(-2x\)
For this term, we will apply the power rule of integration, which states that \(\int x^n \, dx = \frac{x^{n+1}}{n+1} + C_2\), where \(n \neq -1\). In this case, \(n = 1\):
\[
\int (-2x) \, dx = -2\int x^1 \, dx = -2\frac{x^{1+1}}{1+1} + C_2 = -x^2 + C_2
\]
where \(C_2\) is the constant of integration for this term.
4Step 4: Integrate the quadratic term \(x^2\)
Again, applying the power rule of integration with \(n = 2\):
\[
\int x^2 \, dx = \frac{x^{2+1}}{2+1} + C_3 = \frac{x^3}{3} + C_3
\]
where \(C_3\) is the constant of integration for this term.
5Step 5: Combine the integrals
We will now combine the results from Steps 2, 3, and 4 to find the indefinite integral of the given polynomial function:
\[
\int (3 -2x + x^2) \, dx = (3x + C_1) + (-x^2 + C_2) + \left(\frac{x^3}{3} + C_3\right) = \frac{x^3}{3} - x^2 + 3x + C
\]
where \(C = C_1 + C_2 + C_3\) is the constant of integration for the entire polynomial.
6Step 6: Differentiate the indefinite integral
Now we will differentiate the indefinite integral we just found to check our answer:
\[
\frac{d}{dx}\left(\frac{x^3}{3} - x^2 + 3x + C\right) = \frac{3x^2}{3} -2x + 3 = x^2 - 2x + 3
\]
Our differentiated result is the same as the original function, confirming that our integration is correct.
Therefore, the indefinite integral of the given function is:
\[
\int(3-2x+x^{2})\, dx = \frac{x^3}{3} - x^2 + 3x + C
\]
Key Concepts
Power Rule of IntegrationConstant of IntegrationDifferentiation Check
Power Rule of Integration
The power rule of integration is one of the most fundamental tools for finding indefinite integrals of polynomial functions. This rule helps us integrate expressions of the form \(x^n\), where \(n\) is a real number. The power rule states:
To apply this rule, simply increase the exponent by one, then divide by the newly increased exponent. For example, applying this to \(x^2\), we increase the exponent to 3 and then divide by 3:
- \(\int x^n \, dx = \frac{x^{n+1}}{n+1} + C\)
To apply this rule, simply increase the exponent by one, then divide by the newly increased exponent. For example, applying this to \(x^2\), we increase the exponent to 3 and then divide by 3:
- \(\int x^2 \, dx = \frac{x^3}{3} + C\)
Constant of Integration
In indefinite integrals, the constant of integration \(C\) is a crucial component that arises because there are infinitely many antiderivatives for a given function. When you integrate a function, the result can have a variety of forms shifted vertically by different constants.
Each time we integrate a term separately, we add a constant of integration, like \(C_1, C_2, C_3\), to every distinct term. This reflects the fact that the indefinite integral includes all possible antiderivatives. In practice, we only need one constant after combining all terms:
Each time we integrate a term separately, we add a constant of integration, like \(C_1, C_2, C_3\), to every distinct term. This reflects the fact that the indefinite integral includes all possible antiderivatives. In practice, we only need one constant after combining all terms:
- When we combine them: \(C = C_1 + C_2 + C_3\)
Differentiation Check
Performing a differentiation check is a smart way to verify that your calculated indefinite integral is correct. You simply differentiate your result and see if you arrive back at the original function you intended to integrate. For instance, we worked through the integral \(\int (3 - 2x + x^2) \, dx\). After calculating:
- \(\frac{x^3}{3} - x^2 + 3x + C\)
- \(\frac{d}{dx}\left(\frac{x^3}{3} - x^2 + 3x + C\right) = x^2 - 2x + 3\)
Other exercises in this chapter
Problem 3
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