Problem 3
Question
Find the exact value. \(\arcsin \left(-\frac{\sqrt{2}}{2}\right)\)
Step-by-Step Solution
Verified Answer
The exact value is \\(-\frac{\pi}{4}\\).
1Step 1: Understand the Problem
We need to find the angle whose sine value is \(-\frac{\sqrt{2}}{2}\). This is essentially the definition of the arcsin function, which returns the angle whose sine is the given value.
2Step 2: Identify the Range for Arcsin
The inverse sine function, \(\arcsin(x)\), returns angles in the interval \([-\frac{\pi}{2}, \frac{\pi}{2}]\) (or \([-90^\circ, 90^\circ]\)). Therefore, the answer must lie within this range.
3Step 3: Recognize Known Values of Sine
Recall that \(\sin\left(-\frac{\pi}{4}\right) = -\frac{\sqrt{2}}{2}\). This means \(-\frac{\pi}{4}\) radians (or \(-45^\circ\)) is an angle in the desired range with the correct sine value.
4Step 4: Verify the Angle
Confirm that \(-\frac{\pi}{4}\) is indeed within the specified range \([-\frac{\pi}{2}, \frac{\pi}{2}]\), which it is. Thus, the correct value for \(\arcsin\left(-\frac{\sqrt{2}}{2}\right)\) is \(-\frac{\pi}{4}\).
Key Concepts
Inverse Trigonometric FunctionsAngle MeasurementSine ValuesUnit Circle
Inverse Trigonometric Functions
Inverse trigonometric functions are essential tools in mathematics. They help us find angles when we know the value of the sine, cosine, or other trigonometric ratios.
In the world of trigonometry, these inverse functions reverse the original trigonometric functions. This is key when solving equations involving angles and sides of right triangles.
For example:
These inverse functions are restricted to specific ranges to ensure they behave consistently and give unique outputs, which is crucial for solving mathematical problems.
In the world of trigonometry, these inverse functions reverse the original trigonometric functions. This is key when solving equations involving angles and sides of right triangles.
For example:
- The inverse of the sine function is called arcsin, often denoted as \(\arcsin(x)\).
- The inverse of the cosine function is arccos, denoted by \(\arccos(x)\).
- Similarly, arctan is the inverse of the tangent function, written as \(\arctan(x)\).
These inverse functions are restricted to specific ranges to ensure they behave consistently and give unique outputs, which is crucial for solving mathematical problems.
Angle Measurement
Angles can be measured in different units, with degrees and radians being the most common. Understanding these measurement systems is crucial when working with trigonometric functions.
Degrees are more familiar to most people:
Degrees are more familiar to most people:
- A full circle is 360 degrees.
- 90 degrees is a right angle.
- 45 degrees is half of a right angle.
- A full circle is \(2\pi\) radians.
- 90 degrees equals \(\frac{\pi}{2}\) radians.
- 45 degrees equals \(\frac{\pi}{4}\) radians.
Sine Values
Sine values represent the y-coordinate of a point on the unit circle. They range between -1 and 1, reflecting the maximum stretch of the unit circle vertically.
Some sine values are easily recognizable and very significant in trigonometry:
Some sine values are easily recognizable and very significant in trigonometry:
- \(\sin(0) = 0\)
- \(\sin(\frac{\pi}{6}) = \frac{1}{2}\)
- \(\sin(\frac{\pi}{4}) = \frac{\sqrt{2}}{2}\)
- \(\sin(\frac{\pi}{3}) = \frac{\sqrt{3}}{2}\)
- \(\sin(\frac{\pi}{2}) = 1\)
Unit Circle
The unit circle is a vital concept in trigonometry that greatly simplifies the understanding of angles and their sine values. It is a circle with a radius of 1, centered at the origin of a coordinate plane.
Each point on the unit circle corresponds to
Each point on the unit circle corresponds to
- A specific angle measure from the positive x-axis.
- A set of coordinates \((x, y)\). The x-coordinate represents the cosine, and the y-coordinate represents the sine of the angle.
- At \(45^\circ\) or \(\frac{\pi}{4}\) radians, the coordinates are \(\left(\frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2}\right)\).
- Its reflection in the third quadrant, \(-\frac{\pi}{4}\), gives the coordinates \(\left(-\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2}\right)\).
- This helps us pinpoint the angle with sine value \(-\frac{\sqrt{2}}{2}\) while considering the range of the inverse sine function.
Other exercises in this chapter
Problem 2
Find the exact value of the cosine and sine of the given angle. $$ \theta=\frac{\pi}{4} $$
View solution Problem 2
Convert the angles into the DMS system. Round each of your answers to the nearest second. $$ 200.325^{\circ} $$
View solution Problem 3
In Exercises \(1-18,\) find all of the exact solutions of the equation and then list those solutions which are in the interval \([0,2 \pi)\). $$ \sin (-2 x)=\fr
View solution Problem 3
Graph one cycle of the given function. State the period, amplitude, phase shift and vertical shift of the function. \(y=-2 \cos (x)\)
View solution