Problem 3
Question
Find the amplitude and the period and sketch the graph of the equation: A. \(y=3 \cos x\) B. \(y=\cos 3 x\) C. \(y=\frac{1}{3} \cos x\) D. \(y=\cos \frac{1}{3} x\) E. \(y=2 \cos \frac{1}{3} x\) F. \(y=\frac{1}{2} \cos 3 x\) G. \(y=-3 \cos x\) H. \(y=\cos (-3 x)\)
Step-by-Step Solution
Verified Answer
Amplitude and period are: A: 3, \(2\pi\); B: 1, \(\frac{2\pi}{3}\); C: \(\frac{1}{3}\), \(2\pi\); D: 1, \(6\pi\); E: 2, \(6\pi\); F: \(\frac{1}{2}\), \(\frac{2\pi}{3}\); G: 3, \(2\pi\); H: 1, \(\frac{2\pi}{3}\).
1Step 1: Identify the standard cosine function properties
The standard cosine function is given by \(y = \cos x\), where the amplitude is 1 and the period is \(2\pi\). We'll use this information to determine the amplitude and period of each function listed in the exercise.
2Step 2: Calculate amplitude and period for A. \(y = 3 \cos x\)
The amplitude is the coefficient in front of the cosine, which is 3. The period remains \(2\pi\) since there is no horizontal stretching or compressing factor inside the cosine function.
3Step 3: Calculate amplitude and period for B. \(y = \cos 3x\)
The amplitude is 1 since there is no coefficient in front of the cosine. The period is \(\frac{2\pi}{3}\) because the function is \(\cos (bx)\) with \(b=3\), and the period formula is \(\frac{2\pi}{b}\).
4Step 4: Calculate amplitude and period for C. \(y = \frac{1}{3} \cos x\)
The amplitude is \(\frac{1}{3}\). The period is \(2\pi\), as the coefficient of \(x\) inside \(\cos\) is 1, resulting in no change in the period.
5Step 5: Calculate amplitude and period for D. \(y = \cos \frac{1}{3} x\)
The amplitude is 1, as there is no coefficient in front of \(\cos\). The period is \(6\pi\) since the coefficient \(b\) is \(\frac{1}{3}\) and the period is given by \(\frac{2\pi}{b}\).
6Step 6: Calculate amplitude and period for E. \(y = 2 \cos \frac{1}{3} x\)
The amplitude is 2. The period is \(6\pi\), calculated from \(\frac{2\pi}{b}\) with \(b = \frac{1}{3}\).
7Step 7: Calculate amplitude and period for F. \(y = \frac{1}{2} \cos 3x\)
The amplitude is \(\frac{1}{2}\). The period is \(\frac{2\pi}{3}\).
8Step 8: Calculate amplitude and period for G. \(y = -3 \cos x\)
The amplitude is the absolute value of the coefficient, which is 3. The period is \(2\pi\), as the negative sign only affects the direction, not the period.
9Step 9: Calculate amplitude and period for H. \(y = \cos (-3x)\)
The amplitude is 1, and the period remains \(\frac{2\pi}{3}\). The negative sign inside the cosine argument only reflects the graph across the y-axis, not affecting the period.
Key Concepts
Cosine Function PropertiesGraphing Trigonometric FunctionsAmplitude and Period Calculation
Cosine Function Properties
The cosine function is an essential trigonometric function characterized by a wave-like pattern. At its core, the standard cosine function is expressed mathematically as \(y = \cos x\). Here are some key properties:
- **Amplitude:** The amplitude is the maximum distance of the wave from the central axis, essentially the "height" of the wave. In \(y = \cos x\), the amplitude is 1.
- **Period:** The period is the distance the function travels along the x-axis before repeating. For \(y = \cos x\), it is \(2\pi\).
- **Symmetry:** The cosine function is even, meaning \(\cos(-x) = \cos x\), keeping it symmetrical about the y-axis.
Graphing Trigonometric Functions
Graphing trigonometric functions like the cosine function starts with identifying its basic properties—amplitude, period, phase shift, and vertical shift. The graph of \(y = \cos x\) is a continuous wave that repeats every \(2\pi\). Here's how we can graph it:
- **Begin with the basic curve**: Start plotting from point (0,1), moving through key points like \((\pi/2, 0)\), \((\pi, -1)\), \((3\pi/2, 0)\), and back to \((2\pi, 1)\).
- **Amplitude Scaling**: If there is a coefficient, like in \(y = 3\cos x\), multiply the y-values by the amplitude (3 in this case).
- **Period Adjustment**: Changing the coefficient of \(x\) affects the period. For instance, \(y = \cos 3x\) compresses the period to \(\frac{2\pi}{3}\). Calculate this new period and adjust your x-axis scale accordingly.
Amplitude and Period Calculation
To calculate the amplitude and period of trigonometric functions, such as those in the given exercise, follow these steps:
- **Amplitude Calculation**: Identify the coefficient in front of the cosine (or sine). The amplitude is the absolute value of this coefficient. For example, in \(y = -3 \cos x\), the amplitude is \(|-3| = 3\).
- **Period Calculation**: Look inside the argument of the cosine or sine function. If it's \(\cos(bx)\), the period is given by \(\frac{2\pi}{b}\). Therefore, \(y = \cos 3x\) has a period of \(\frac{2\pi}{3}\).
Other exercises in this chapter
Problem 3
Given the indicated parts of triangle \(A B C\) with \(\gamma=90^{\circ},\) find the exact values of the remaining parts. $$\beta=45^{\circ}, \quad c=30$$
View solution Problem 3
Find the period and sketch the graph of the equation. Show the asymptotes. $$y=3 \cot x$$
View solution Problem 3
Find the reference angle \(\theta_{R}\) if \(\theta\) has the given measure. (a) \(3 \pi / 4\) (b) \(4 \pi / 3\) \((c)-\pi / 6\) \((d) 9 \pi / 4\)
View solution Problem 3
Exer. 1-4: If the given angle is in standard position, find two positive coterminal angles and two negative coterminal angles. (a) \(620^{\circ}\) (b) \(\frac{5
View solution