Problem 3
Question
Find, if possible, \(A+B, A-B, 2 A,\) and \(-3 B\). $$A=\left[\begin{array}{rr} 6 & -1 \\ 2 & 0 \\ -3 & 4 \end{array}\right], \quad B=\left[\begin{array}{rr} 3 & 1 \\ -1 & 5 \\ 6 & 0 \end{array}\right]$$
Step-by-Step Solution
Verified Answer
\(A + B = \left[\begin{array}{rr} 9 & 0 \\ 1 & 5 \\ 3 & 4 \end{array}\right], A - B = \left[\begin{array}{rr} 3 & -2 \\ 3 & -5 \\ -9 & 4 \end{array}\right], 2A = \left[\begin{array}{rr} 12 & -2 \\ 4 & 0 \\ -6 & 8 \end{array}\right], -3B = \left[\begin{array}{rr} -9 & -3 \\ 3 & -15 \\ -18 & 0 \end{array}\right]."
1Step 1: Determine if A and B can be added or subtracted
To add or subtract matrices, they must have the same dimensions. Matrix \(A\) is a \(3 \times 2\) matrix, and matrix \(B\) is also \(3 \times 2\), so they can be added or subtracted.
2Step 2: Calculate A + B
The sum of matrices \(A\) and \(B\) is found by adding corresponding elements.\[A + B = \left[\begin{array}{rr}6 + 3 & -1 + 1 \2 - 1 & 0 + 5 \-3 + 6 & 4 + 0\end{array}\right] = \left[\begin{array}{rr}9 & 0 \1 & 5 \3 & 4\end{array}\right]\]
3Step 3: Calculate A - B
The difference of matrices \(A\) and \(B\) is found by subtracting corresponding elements.\[A - B = \left[\begin{array}{rr}6 - 3 & -1 - 1 \2 + 1 & 0 - 5 \-3 - 6 & 4 - 0\end{array}\right] = \left[\begin{array}{rr}3 & -2 \3 & -5 \-9 & 4\end{array}\right]\]
4Step 4: Calculate 2A
To find \(2A\), multiply every element of \(A\) by 2.\[2A = 2 \times \left[\begin{array}{rr}6 & -1 \2 & 0 \-3 & 4\end{array}\right] = \left[\begin{array}{rr}12 & -2 \4 & 0 \-6 & 8\end{array}\right]\]
5Step 5: Calculate -3B
To find \(-3B\), multiply every element of \(B\) by -3.\[-3B = -3 \times \left[\begin{array}{rr}3 & 1 \-1 & 5 \6 & 0\end{array}\right] = \left[\begin{array}{rr}-9 & -3 \3 & -15 \-18 & 0\end{array}\right]\]
Key Concepts
Matrix AdditionMatrix SubtractionScalar MultiplicationMatrix Dimensions
Matrix Addition
In matrix addition, we combine two matrices by adding their corresponding elements. For this operation to be possible, the matrices involved must have the same dimensions. This means that both should have the same number of rows and columns.
For instance, if matrix \(A\) and matrix \(B\) are both \(3 \times 2\) matrices, you can add them together because they have the same shape.
For instance, if matrix \(A\) and matrix \(B\) are both \(3 \times 2\) matrices, you can add them together because they have the same shape.
- The first element of \(A+B\) is the sum of the first elements of \(A\) and \(B\).
- Continue this process for every element in the matrices.
Matrix Subtraction
Matrix subtraction is the process of subtracting corresponding elements of one matrix from another. Like matrix addition, this operation can only be performed on matrices of the same dimensions.
To subtract matrix \(B\) from \(A\), represented as \(A-B\), follow these steps:
To subtract matrix \(B\) from \(A\), represented as \(A-B\), follow these steps:
- Subtract each element of \(B\) from the corresponding element in \(A\), so the top left element of \(B\) is subtracted from the top left element of \(A\), and so forth.
- Continue until all corresponding elements have been subtracted.
Scalar Multiplication
Scalar multiplication in matrices involves multiplying every element of a matrix by a given scalar, which is simply a regular number. This operation is versatile and does not require matrices of any specific size.
When performing scalar multiplication:
When performing scalar multiplication:
- Multiply each element in the matrix by the scalar number.
- The matrix's dimensions remain the same.
Matrix Dimensions
Matrix dimensions are crucial when performing matrix operations. The dimensions of a matrix are defined by the number of its rows and columns, noted as "rows \(\times\) columns".
- A \(3 \times 2\) matrix has 3 rows and 2 columns. Each position in this array holds a specific numerical value.
- When adding or subtracting matrices, their dimensions must match exactly.
- For scalar multiplication, the matrix dimensions can be of any size, as the operation impacts individual elements without concerning the matrix structure.
Other exercises in this chapter
Problem 2
Use the method of substitution to solve the system. $$\left\\{\begin{aligned} y &=x^{2}+1 \\ x+y &=3 \end{aligned}\right.$$
View solution Problem 3
Find the partial fraction decomposition. \(\frac{x+34}{x^{2}-4 x-12}\)
View solution Problem 3
Find all the minors and cofactors of the elements in the matrix. $$\left[\begin{array}{rrr} 2 & 4 & -1 \\ 0 & 3 & 2 \\ -5 & 7 & 0 \end{array}\right]$$
View solution Problem 3
Use matrices to solve the system. $$\left\\{\begin{array}{rr} 5 x+2 y-z= & -7 \\ x-2 y+2 z= & 0 \\ 3 y+z= & 17 \end{array}\right.$$
View solution