Problem 3
Question
Explain the meaning of each of the following. $${ (a) }\lim _{x \rightarrow-3} f(x)=\infty \quad \text { (b) } \lim _{x \rightarrow 4^{+}} f(x)=-\infty$$
Step-by-Step Solution
Verified Answer
(a) \( f(x) \) increases without bound as \( x \to -3 \). (b) \( f(x) \) decreases without bound as \( x \to 4^+ \).
1Step 1: Introduction to Limits
A limit describes the behavior of a function as the input approaches a certain value. The notation \( \lim_{x \to c} f(x) \) indicates what \( f(x) \) is approaching as \( x \) gets closer to \( c \).
2Step 2: Understanding Infinite Limits
When the limit of a function is \( \infty \) or \( -\infty \), it suggests that the function values grow larger and larger without bound (positively or negatively) as \( x \) approaches the specified point.
3Step 3: Interpreting (a) \( \lim_{x \to -3} f(x) = \infty \)
This means as \( x \) gets closer to \(-3\) from any direction, the function \( f(x) \) increases without bound. The graph of \( f(x) \) likely rises indefinitely as it nears \( x = -3 \).
4Step 4: Explaining (b) \( \lim_{x \to 4^+} f(x) = -\infty \)
Here, \( x \to 4^+ \) means \( x \) approaches 4 from values greater than 4. As \( x \) gets closer to 4 from the right side, \( f(x) \) decreases without bound, suggesting a vertical asymptote or sharp drop on the graph near \( x = 4 \).
Key Concepts
Understanding LimitsExploring Vertical AsymptotesAnalyzing Function Behavior
Understanding Limits
Limits are fundamental concepts in calculus that help us understand how functions behave as they approach a particular point. In simpler terms, a limit describes the value that a function, denoted as \( f(x) \), is approaching as the input \( x \) moves closer and closer to a specific number, \( c \). When we write \( \lim_{x \to c} f(x) \), we are essentially expressing the behavior or trend of \( f(x) \) as \( x \) gets infinitely close to \( c \). This can provide valuable insights, especially when the function value isn't immediately obvious—such as at points where a function might have a hole, a jump, or even when it heads towards infinity.
- Limits help in calculating derivatives, which measure rates of change, and integrals, which calculate area under curves.
- The study of limits serves as a stepping stone toward understanding more complex calculus concepts.
Exploring Vertical Asymptotes
A vertical asymptote is an essential feature of many functions, particularly rational ones. These occur where the function heads towards infinity or negative infinity as \( x \) gets closer to a certain value but never actually reaches it. As depicted in our example, \( \lim_{x \to -3} f(x) = \infty \), it suggests that as \( x \) nears \(-3\), the values of \( f(x) \) increase without bound, indicating a vertical asymptote at \( x = -3 \).
- Vertical asymptotes are represented by vertical lines on a graph, where the function does not exist in a finite range.
- In our second example, \( \lim_{x \to 4^+} f(x) = -\infty \), it implies that as \( x \) approaches 4 from the right, \( f(x) \) drops toward negative infinity, suggesting another vertical asymptote.
Analyzing Function Behavior
Function behavior is particularly interesting when approaching a point of infinity, such as those involving vertical asymptotes. When we analyze a function like in our exercise examples, we focus on how the function behaves near certain critical points. For instance, a statement like \( \lim_{x \to -3} f(x) = \infty \) tells us that as \( x \) nears \(-3\), the values shoot upwards dramatically.
- Function behavior describes what happens to \( f(x) \) as \( x \) approaches a particular value, influencing how the graph is shaped near vertical asymptotes.
- If \( \lim_{x \to 4^+} f(x) = -\infty \), the function \( f(x) \) decreases without bound when nearing \( x = 4 \) from the right, reflecting a plummeting graph.
Other exercises in this chapter
Problem 2
$$ \begin{array}{l}{\text { (a) Can the graph of } y=f(x) \text { intersect a vertical asymptote? }} \\ {\text { Can it intersect a horizontal asymptote? Illust
View solution Problem 3
The point \(\mathrm{P}\left(1, \frac{1}{2}\right)\) lies on the curve \(y=x /(1+x)\). $$\begin{array}{l}{\text { (a) If } \mathrm{O} \text { is the point }(\mat
View solution Problem 3
Evaluate the limit and justify each step by indicating the appropriate Limit Law(s). $$\lim _{x \rightarrow-2}\left(3 x^{4}+2 x^{2}-x+1\right)$$
View solution Problem 4
Evaluate the limit and justify each step by indicating the appropriate Limit Law(s). $$\lim _{x \rightarrow 2} \frac{2 x^{2}+1}{x^{2}+6 x-4}$$
View solution