Problem 3
Question
Explain how to use the quotient property of radicals to simplify \(\sqrt{\frac{4}{25}}\)
Step-by-Step Solution
Verified Answer
The simplified expression of \(\sqrt{\frac{4}{25}}\) is \(\frac{2}{5}\).
1Step 1: Identify the Numerator and Denominator
In the radical expression \(\sqrt{\frac{4}{25}}\), the number '4' is the numerator and '25' is the denominator.
2Step 2: Apply the Quotient Property of Radicals
Next, apply the quotient property of radicals to the expression. This changes the expression from \(\sqrt{\frac{4}{25}}\) to \(\frac{\sqrt{4}}{\sqrt{25}}\).
3Step 3: Simplify the Radicals
The square root of '4' is '2' and the square root of '25' is '5'. Substituting these values into the expression results in \(\frac{2}{5}\).
Key Concepts
Simplifying RadicalsRadical ExpressionsSquare Roots
Simplifying Radicals
Simplifying radicals is an essential step in making complex mathematical expressions easier to work with. Imagine you have a radical expression like \( \sqrt{\frac{4}{25}} \). Rather than trying to deal with this intimidating fraction under a single square root, our goal is to turn it into a simpler form.
- This is where the quotient property of radicals comes into play.
- The property lets you "split" radicals into separate easier parts.
- Specifically, \( \sqrt{\frac{a}{b}} = \frac{\sqrt{a}}{\sqrt{b}} \).
Radical Expressions
A radical expression is any mathematical expression that includes a square root, cube root, or any higher order root. Understanding how to manipulate these expressions is crucial for solving various mathematical problems.
- In the radical expression \( \sqrt{\frac{4}{25}} \), both the numerator '4' and the denominator '25' are perfect squares.
- This allows us to simplify them separately using their square roots.
Square Roots
The concept of square roots is fundamental when simplifying radicals and working with radical expressions.
- The square root of a number is one of its two equal factors, essentially the number multiplied by itself.
- For instance, the square root of '4' is '2' because \( 2 \times 2 = 4 \).
- Similarly, the square root of '25' is '5', as \( 5 \times 5 = 25 \).
Other exercises in this chapter
Problem 3
Is \((0,3)\) inside or outside the graph of \(y=x^{2}+3 x+2 ?\)
View solution Problem 3
Explain how you can decide whether the graph of \(y=3 x^{2}+2 x-4\) opens up or down.
View solution Problem 4
Find the discriminant for the equation. Then tell if the equation has two solutions, one solution, or no real solution. $$-3 x^{2}+6 x-3=0$$
View solution Problem 4
Use the quadratic formula to solve the equation. $$x^{2}+6 x-7=0$$
View solution