Problem 3
Question
Evaluate the partial integral. $$ \int_{1}^{2 y} \frac{y}{x} d x $$
Step-by-Step Solution
Verified Answer
The result after evaluating the partial integral is \( y*\ln|2y| \).
1Step 1: Simplify the Integral with Substitution
Let's simplify the problem by substitution a new variable, u, where \(u = x/y\). This gives us the differential of u, \(du = dx/y\), or equivalently \(dx = y du\). Now we substitute those relations into the integral, so \( \int_{1/y}^{2} \frac{1}{u} * y du \). Note that we also change the limits of the integral according to the new variable u.
2Step 2: Evaluate the Simplified Integral
The integral we have now is much simpler to handle. Since the y-term is constant concerning the integration variable we can move it in front of the integral sign. So it transforms into \( y \int_{1/y}^{2} \frac{1}{u} du \), which is a basic form of a logarithm integral. Therefore, we can evaluate it directly to \( y[ \ln|2|- \ln|1/y|\)].
3Step 3: Simplify the Result
Now we can simplify the expressions in the square brackets: \( \ln|2|- \ln|1/y|\) can be combined into \( \ln|2y|\) using the properties of a logarithm. Hence we end up with the result \( y*\ln|2y|\).
Other exercises in this chapter
Problem 2
Plot the points on the same threedimensional coordinate system. (a) \((3,-2,5)\) (b) \(\left(\frac{3}{2}, 4,-2\right)\)
View solution Problem 3
Sketch the region of integration and evaluate the double integral. $$ \int_{0}^{1} \int_{y}^{\sqrt{y}} x^{2} y^{2} d x d y $$
View solution Problem 3
Use Lagrange multipliers to find the given extremum. In each case, assume that \(x\) and \(y\) are positive. $$ \text { Minimize } f(x, y)=x^{2}+y^{2} \quad x+y
View solution Problem 3
Find any critical points and relative extrema of the function. $$ f(x, y)=\sqrt{x^{2}+y^{2}+1} $$
View solution