Problem 3
Question
Estimate how many electrons there are in your body. Make any assumptions you feel are necessary, but clearly state what they are. (Hint: Most of the atoms in your body have equal numbers of electrons, protons, and neutrons.) What is the combined charge of all these electrons?
Step-by-Step Solution
Verified Answer
There are approximately \(1.4 \times 10^{28}\) electrons in the body, with a total charge of \(-2.24 \times 10^{9}\) coulombs.
1Step 1: Estimating the number of atoms in the body
Assume the average mass of a human body is 70 kg. A large portion of the human body mass consists of water, and water (H2O) molecules contain two hydrogen atoms and one oxygen atom. Hydrogen and oxygen together are about 99% of the atoms in the body. Assuming roughly 10% of body composition is carbon, nitrogen, etc., estimate the total number of atoms by approximating the body composition as 70% water. The molecular weight of water is 18 g/mol, so the number of moles in the body is \( \frac{70,000 \text{ g}}{18 \text{ g/mol}} \approx 3889 \text{ moles} \). Using Avogadro's number (\( 6.022 \times 10^{23} \text{ atoms/mol} \)), calculate the total number of water molecules/atoms: \( 3889 \times 6.022 \times 10^{23} \approx 2.34 \times 10^{27} \) atoms.
2Step 2: Estimating the number of electrons per atom
Assume all atoms in the body have approximately the same number of electrons as protons and assume they are electrically neutral. The most common elements (hydrogen, oxygen, carbon, nitrogen) have atomic numbers corresponding to the number of electrons: Hydrogen (1 electron), Oxygen (8 electrons), Carbon (6 electrons), and Nitrogen (7 electrons). Averaging these, the estimated electrons per atom can be around 5-7 electrons/atom. Take an average of approximately 6 electrons/atom.
3Step 3: Calculating total number of electrons
Multiply the number of atoms by the average number of electrons per atom to estimate total electrons: \( 2.34 \times 10^{27} \text{ atoms} \times 6 \text{ electrons/atom} \approx 1.4 \times 10^{28} \text{ electrons} \).
4Step 4: Calculating the total charge of these electrons
Each electron has a charge of \(-1.6 \times 10^{-19} \text{ Coulombs }\). Multiply the total number of electrons by the charge per electron to find the total charge: \( 1.4 \times 10^{28} \times (-1.6 \times 10^{-19}) = -2.24 \times 10^{9} \text{ Coulombs} \). This is the total charge, considering all electrons carry a negative charge.
Key Concepts
Electron CountMolecular CompositionAvogadro's NumberCharge Calculation
Electron Count
The concept of electron count is fundamental in understanding atomic structure. Electrons are negatively charged particles surrounding the nucleus of an atom. They are important in chemical reactions and determine the atom's properties. To estimate how many electrons are in your body, it's helpful to know about the common elements and atoms it contains.
Consider that elements like hydrogen, oxygen, carbon, and nitrogen make up most of the body. Each of these elements has a certain number of electrons:
Consider that elements like hydrogen, oxygen, carbon, and nitrogen make up most of the body. Each of these elements has a certain number of electrons:
- Hydrogen has 1 electron.
- Oxygen has 8 electrons.
- Carbon has 6 electrons.
- Nitrogen has 7 electrons.
Molecular Composition
Molecular composition involves understanding which molecules primarily make up a substance—in this case, the human body. Water (H₂O), with its two hydrogen atoms and one oxygen atom, comprises about 70% of the human body's composition.
To estimate the molecules in the body, think about water being a significant portion. The molecular weight of water is 18 grams per mole. When you know the body's approximate mass (say, 70 kg), you can calculate the moles of water it contains:
To estimate the molecules in the body, think about water being a significant portion. The molecular weight of water is 18 grams per mole. When you know the body's approximate mass (say, 70 kg), you can calculate the moles of water it contains:
- Convert the body mass to grams: 70,000 grams.
- Divide by the molecular weight: \(\frac{70,000}{18} \approx 3889 ext{ moles of water}\)
Avogadro's Number
Avogadro's Number is a cornerstone of chemistry, providing the link between macroscopic and microscopic scales. Defined as \(6.022 \times 10^{23} \text{ atoms/mol} \), it tells us how many atoms or molecules are in one mole of a substance.
When estimating the number of atoms in the human body, Avogadro's Number becomes crucial. Given a certain number of moles (like the estimated 3889 moles of water in a 70 kg body), multiplying this by Avogadro's Number gives the total number of molecules:
When estimating the number of atoms in the human body, Avogadro's Number becomes crucial. Given a certain number of moles (like the estimated 3889 moles of water in a 70 kg body), multiplying this by Avogadro's Number gives the total number of molecules:
- \(3889 \times 6.022 \times 10^{23} \approx 2.34 \times 10^{27} \text{ atoms}\)
Charge Calculation
Charge calculation involves determining the total charge carried by electrons. Since each electron carries a charge of \(-1.6 \times 10^{-19} \text{ Coulombs} \), knowing the total number of electrons means you can calculate the total charge they produce.
For example, if you estimate around \(1.4 \times 10^{28} \text{ electrons}\) in your body (found by multiplying the number of atoms by the average number of electrons per atom), then the total charge is:
For example, if you estimate around \(1.4 \times 10^{28} \text{ electrons}\) in your body (found by multiplying the number of atoms by the average number of electrons per atom), then the total charge is:
- Multiply the number of electrons by the electron's charge:\(1.4 \times 10^{28} \times (-1.6 \times 10^{-19}) = -2.24 \times 10^{9} \text{ Coulombs}\)
Other exercises in this chapter
Problem 1
Excess electrons are placed on a small lead sphere with mass 8.00 g so that its net charge is \(-3.20 \times 10^{-9} \mathrm{C}\) (a) Find the number of excess
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Lightning occurs when there is a flow of electric charge (principally electrons) between the ground and a thundercloud. The maximum rate of charge flow in a lig
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Particles in a Gold Ring. You have a pure ( 24 karal) gold ring with mass 17.7 \(\mathrm{g}\) . Gold has an atomic mass of 197 \(\mathrm{g} / \mathrm{mol}\) and
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An average human weighs about 650 \(\mathrm{N}\) . If two such generic humans each carried 1.0 coulomb of excess charge, one positive and one negative, how far
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