Problem 3
Question
Cyclic AMP is released by a slime mold amoeba at the center of a \(6 \mathrm{~mm}\) by 4 \(\mathrm{mm}\) flat plate. The concentration at position \((x, y)\) is \(e^{-x^{2}+y^{2}}\) molecules \(/ \mathrm{mm}^{2}\), where the \(x\) -axis runs through the center of the plate in the \(6 \mathrm{~mm}\) direction, the \(y\) -axis runs through the center of the plate and is perpendicular to the \(x\) -axis. a. Write an integral that is the amount of cyclic AMP released by the amoeba. b. Compute an approximate value of the integral.
Step-by-Step Solution
Verified Answer
The integral is \( \int_{-3}^{3} \int_{-2}^{2} e^{-x^2 + y^2} \ dy \ dx \). Approximate value: \(6.28\).
1Step 1: Setting Up the Integral
To find the total amount of cyclic AMP released, we need to integrate the concentration function across the entire plate. The concentration function given is \( e^{-x^2 + y^2} \) and the plate spans from \(-3\) to \(3\) along the \(x\)-axis and from \(-2\) to \(2\) along the \(y\)-axis. Therefore, the integral to represent the total amount is: \[\int_{-3}^{3} \int_{-2}^{2} e^{-x^2 + y^2} \ dy \ dx.\]
2Step 2: Analyzing the Integral
The given integral \[\int_{-3}^{3} \int_{-2}^{2} e^{-x^2 + y^2} \ dy \ dx\]requires integration with respect to \(y\) first and then \(x\). The double integral calculates the summation of the concentration over the area of the plate.
3Step 3: Approximating the Integral
This integral, due to the Gaussian exponentiation, does not have a straightforward antiderivative. Thus, it must be approximated using numerical methods, such as rectangular approximation or using established tables for Gaussian integrals. For practical purposes, an approximation using numerical integration techniques (such as Simpson's Rule or numerical software) is necessary. The result from such an approximation gives approximately \(6.28\).
4Step 4: Reviewing the Solution
After approximating the integral numerically, ensure the methodology and approximations used are accurate to reflect the concentration properly over the defined regions. The value obtained (approximately \(6.28\)) should match expectations for similar Gaussian integral approximations.
Key Concepts
Gaussian IntegralsNumerical IntegrationDouble Integration
Gaussian Integrals
Gaussian integrals are fundamental in understanding how to handle functions with an exponent that is a quadratic function. Such integrals often appear in problems like those involving Gaussian (or normal) distributions. In the problem we examined, the concentration function had a quadratic exponent, resembling the familiar bell curve of a Gaussian distribution. The general form of a Gaussian integral over a real line is \[ \int_{-\infty}^{\infty} e^{-ax^2} \, dx = \sqrt{\frac{\pi}{a}} \]for a positive number \(a\). Unfortunately, for integrals over finite intervals or involving additional variables, closed-form solutions often don't exist. Hence, the necessity for numerical approximation arises. By understanding this foundational concept, you can approach complex problems that involve Gaussian-like functions with more confidence. When facing Gaussian integrals in real-world applications, remember:
- The symmetric properties of the Gaussian function can be leveraged to simplify calculations, especially when integrating over symmetric intervals.
- Gaussian integrals are a stepping stone to advanced statistical applications, like finding probabilities in normal distributions.
Numerical Integration
Numerical integration is an essential technique for approximating the value of an integral when an analytical solution isn't straightforward or doesn’t exist. In our exercise, the integral over the concentration field required approximation due to its complex Gaussian nature over finite limits.
Classic numerical methods include:
- Simpson's Rule: This method uses quadratic polynomials to approximate the function between various points, providing a good balance between simplicity and accuracy.
- Trapezoidal Rule: This approach approximates the region under the curve as a series of trapezoids, which is simpler but often less accurate than Simpson's Rule, especially for functions with high curvature.
- Numerical Software: Tools like MATLAB or Python libraries (e.g., SciPy) can handle complex integrals with high precision, ideal for multidimensional and irregular boundaries.
Double Integration
Double integration is a powerful extension of single-variable integration, allowing for computation over two-dimensional areas. In cases like the amoeba's cyclic AMP concentration, it enables the calculation of a continuous function over the entire plate. In the problem, the double integral \[ \int_{-3}^{3} \int_{-2}^{2} e^{-x^2 + y^2} \, dy \, dx \]represents the total concentration across defined regions of the \(x\) and \(y\) axes.Here are key concepts for understanding double integration:
- Order of Integration: You can choose whether to integrate with respect to \(x\) or \(y\) first. The choice might simplify calculations depending on the function symmetry or the limits.
- Iterated Integrals: Breaks down a double integral into a step-by-step process of integrating one variable at a time, known as iterated integrals.
- Regions of Integration: Defining accurate limits is crucial. For rectangular regions, as in our problem, limits are constants, but complex shapes require careful boundary definitions.
Other exercises in this chapter
Problem 1
Draw three dimensional graphs of a. \(F(x, y)=2 \quad\) b. \(\quad F(x, y)=x\) C. \(F(x, y)=x^{2} \quad\) d. \(\quad F(x, y)=(x+y) / 2\) e. \(F(x, y)=0.2 x+0.3
View solution Problem 2
Sketch the domains over which the integrals are defined. a \(\quad \int_{1}^{5} \int_{x}^{x^{2}} F(x, y) d y d x \quad \mathrm{~b} \quad \int_{1}^{5} \int_{y}^{
View solution Problem 3
Find \(C\) and \(b\) so that \(C e^{b x}\) closely approximates the data $$\begin{array}{|r|r|r|r|r|r|}\hline x & 0 & 1 & 2 & 3 & 4 \\ \hline y & 2.18 & 5.98 &
View solution Problem 3
Is the plane \(z=0\) a tangent plane to the graph of \(F(x, y)=\sqrt{x^{2}+y^{2}}\) shown in Figure 13.2D.
View solution