Problem 3
Question
Consider the polynomial \(p=\left(x_{1}-x_{2}\right)^{2}+\left(x_{3}-x_{4}\right)^{2}\). It is unaltered when the subscripts undergo any of the following permutations: $$ \begin{array}{lll} \left(\begin{array}{llll} 1 & 2 & 3 & 4 \\ 2 & 1 & 3 & 4 \end{array}\right) & \left(\begin{array}{llll} 1 & 2 & 3 & 4 \\ 1 & 2 & 4 & 3 \end{array}\right) & \left(\begin{array}{llll} 1 & 2 & 3 & 4 \\ 2 & 1 & 4 & 3 \end{array}\right) & \left(\begin{array}{llll} 1 & 2 & 3 & 4 \\ 3 & 4 & 1 & 2 \end{array}\right) \\ \left(\begin{array}{llll} 1 & 2 & 3 & 4 \\ 4 & 3 & 1 & 2 \end{array}\right) & \left(\begin{array}{llll} 1 & 2 & 3 & 4 \\ 3 & 4 & 2 & 1 \end{array}\right) & \left(\begin{array}{llll} 1 & 2 & 3 & 4 \\ 4 & 3 & 2 & 1 \end{array}\right) & \left(\begin{array}{llll} 1 & 2 & 3 & 4 \\ 1 & 2 & 3 & 4 \end{array}\right) \end{array} $$For example, the first of these permutations replaces \(p\) by $$ \left(x_{2}-x_{1}\right)^{2}+\left(x_{3}-x_{4}\right)^{2} $$ the second permutation replaces \(p\) by \(\left(x_{1}-x_{2}\right)^{2}+\left(x_{4}-x_{3}\right)^{2} ;\) and so on. The symmetries of a polynomial \(p\) are all the permutations of the subscripts which leave \(p\) unchanged. They form a group of permutations. List the symmetries of each of the following polynomials, and write their group table. $$ p=x_{1} x_{2}+x_{2} x_{3}+x_{1} x_{3} $$
Step-by-Step Solution
VerifiedKey Concepts
Polynomial Symmetries
The symmetries of such polynomials can be thought of as manipulating the subscripts while keeping the overall structure of the polynomial preserved. This means swapping certain indices does not alter the polynomial's value. These unchanged forms pinpoint the symmetrical nature of the polynomial, reflecting on the inherent balance and repeated pattern within its terms.Permutations leading to these symmetries can be grouped into mathematical entities known as symmetric groups. The purpose is to identify all permutations that maximize the preservation of polynomial form.
Permutations
To explore this further, consider how you might rearrange the subscripts of the variables \(x_1, x_2, x_3\) while ensuring the polynomial's expression remains equivalent. Here:
- The identity permutation (1, 2, 3) involves no change, naturally preserving symmetry.
- Swapping \(x_1\) and \(x_2\) gives the permutation (2, 1, 3).
- Switching \(x_2\) and \(x_3\) results in (1, 3, 2).
- Changing \(x_1\) and \(x_3\) leads to the sequence (3, 2, 1).
- The circular and reverse circular shifts create permutations (2, 3, 1) and (3, 1, 2) respectively.
Group Table
For the polynomial \[ p = x_1x_2 + x_2x_3 + x_1x_3 \], permutations like (1, 2, 3), (2, 1, 3), along with their others, can be arranged into a table to highlight their interactions. This table captures the closure property characteristic of groups, where combining any two permutations within the group results in another permutation from the same group.
- Start by listing permutations across the top and side headers of the table.
- Fill in the intersection cells with the resulting permutation from composing the row and column permutations.