Problem 3
Question
Compute the NAND gate output from inputing each pair of bits. $$0,0$$
Step-by-Step Solution
Verified Answer
The NAND gate output for the input pair (0,0) is 1.
1Step 1: NAND gate truth table
Create a truth table for the NAND gate with all possible input pairs. The two input bits will be represented as A and B, and the output will be represented as Y (Y = A NAND B).
```
A | B | Y
---------
0 | 0 | ?
0 | 1 | ?
1 | 0 | ?
1 | 1 | ?
```
2Step 2: Compute the output for each input pair
Use the NAND operation to compute the output (Y) for each input pair (A, B) in the truth table.
```
A | B | Y
---------
0 | 0 | 1
0 | 1 | 1
1 | 0 | 1
1 | 1 | 0
```
The NAND outputs are calculated as follows:
1. \((0 \: AND \: 0) = 0 \rightarrow NOT \: 0 = 1\)
2. \((0 \: AND \: 1) = 0 \rightarrow NOT \: 0 = 1\)
3. \((1 \: AND \: 0) = 0 \rightarrow NOT \: 0 = 1\)
4. \((1 \: AND \: 1) = 1 \rightarrow NOT \: 1 = 0\)
So, the NAND gate output for each input pair of bits is:
- For input pair (0,0), the output is 1.
- For input pair (0,1), the output is 1.
- For input pair (1,0), the output is 1.
- For input pair (1,1), the output is 0.
Key Concepts
Truth TableLogic GatesBinary Operations
Truth Table
A truth table is a simple yet powerful way to visualize how a logic operation, like the NAND gate, works among various input combinations. It outlines every possible input scenario, helping you quickly understand the resulting outputs. For a NAND gate, this involves two inputs referred to as A and B, and a single output called Y, which is calculated as \(Y = A \text{ NAND } B\).
The truth table effectively lists all combinations of binary inputs—0 and 1. By doing so, it provides insight into how the NAND gate processes and produces these logical outputs. For example:
The truth table effectively lists all combinations of binary inputs—0 and 1. By doing so, it provides insight into how the NAND gate processes and produces these logical outputs. For example:
- A and B each take values of either 0 or 1.
- Through the truth table, you sum up possibilities: A 0 and B 0, A 0 and B 1, A 1 and B 0, and A 1 and B 1.
Logic Gates
Logic gates are the building blocks of digital circuits and perform basic logical functions on binary inputs. Each gate has its specific task, feeding the output that helps construct the system of operations in computers and digital devices.
The NAND gate, for instance, is crucial because it can create any other logic gate type in digital electronics with combinations and connectivities of NAND circuits. The name 'NAND' stems from 'Not AND'—indicating it inverts the result of an AND gate.
The NAND gate, for instance, is crucial because it can create any other logic gate type in digital electronics with combinations and connectivities of NAND circuits. The name 'NAND' stems from 'Not AND'—indicating it inverts the result of an AND gate.
- An AND gate returns a 1 only when both inputs are 1.
- A NAND gate reverses the AND result, producing a 0 only when both inputs are 1, and a 1 otherwise.
Binary Operations
Binary operations are fundamental in the realm of digital electronics, allowing us to work with bits—0s and 1s. Each operation manipulates these bits based on a specific logic rule to produce outputs. In context, the NAND gate executes this by performing operations on binary inputs following a defined rule: it outputs the negation of the AND operation's result.
To thoroughly understand a NAND operation:
To thoroughly understand a NAND operation:
- First, apply the AND operation on inputs: If A and B are both 1, the result is 1; otherwise, it's 0.
- Next, negate the result: 1 becomes 0, and 0 becomes 1.
Other exercises in this chapter
Problem 3
Simplify each boolean expression using the laws of boolean algebra. $$(x+y) x y^{\prime}$$
View solution Problem 3
How many constant boolean functions can be defined from \(B^{n}\) to \(B\) with \(B\) a two-element boolean algebra?
View solution Problem 3
When will the combinatorial circuit for each boolean expression produce 1 as the output? $$x y$$
View solution Problem 3
Simplify the boolean expression represented by each Karnaugh map. $$\begin{aligned}&\begin{array}{lllll}\qquad yz \quad y z^{\prime} \quad y^{\prime} z^{\prime}
View solution