Problem 3
Question
a point on the terminal side of angle \(\theta\) is given. Find the exact value of each of the six trigonometric functions of \(\theta .\) $$ (2,3) $$
Step-by-Step Solution
Verified Answer
The exact values of the six trigonometric functions for \(\theta\) based on the terminal point (2,3) are as follow: \n for \(\sin \theta\), \(\cos \theta\), \(\tan \theta\), \(\csc \theta\), \(\sec \theta\), and \(\cot \theta\), respectively, we have \(\frac{3}{\sqrt{13}}\), \(\frac{2}{\sqrt{13}}\), \(\frac{3}{2}\), \(\frac{\sqrt{13}}{3}\), \(\frac{\sqrt{13}}{2}\), and \(\frac{2}{3}\).
1Step 1: Calculating the hypotenuse (r)
To calculate the hypotenuse, let's use the Pythagorean Theorem with the given points (2,3), i.e. \(r = \sqrt{2^{2}+3^{2}}\). Calculate \(r\) to find the length of hypotenuse.
2Step 2: Identifying coordinates
Let's identify the coordinates 'x' and 'y'. In this exercise, x = 2 and y = 3 are already given.
3Step 3: Calculating six trigonometric functions
Let's calculate six trigonometric functions: \n1. For sine: \(\sin \theta = \frac{y}{r} \).2. For cosine: \(\cos \theta = \frac{x}{r} \).3. For tangent: \(\tan \theta = \frac{y}{x} \).4. For cosecant (the reciprocal of sine): \(\csc \theta = \frac{1}{\sin \theta} \).5. For secant (the reciprocal of cosine): \(\sec \theta = \frac{1}{\cos \theta} \).6. For cotangent (the reciprocal of tangent): \(\cot \theta = \frac{1}{\tan \theta} \). Substituting the values of \(x\), \(y\), and \(r\) into these formulas will yield the values of the trigonometric functions.
Key Concepts
Pythagorean theoremright trianglesine and cosinereciprocal identities
Pythagorean theorem
The Pythagorean theorem is a fundamental concept in mathematics, particularly in geometry and trigonometry. It relates the lengths of the sides of a right triangle. According to the theorem, the square of the hypotenuse is equal to the sum of the squares of the other two sides.
For any right triangle, we can express this relationship with the equation:
This forms the basis for further calculations of trigonometric functions.
For any right triangle, we can express this relationship with the equation:
- The hypotenuse (c) is the side opposite the right angle and is always the longest side.
- The other sides are known as the legs (a and b).
- The equation is: \( c^2 = a^2 + b^2 \).
This forms the basis for further calculations of trigonometric functions.
right triangle
A right triangle is a type of triangle that has one angle measuring exactly 90 degrees. This special property sets it apart and makes it important in trigonometry. Each right triangle consists of three sides: the hypotenuse, and two legs.
Visualizing this triangle helps in understanding how the sides relate to each other through trigonometric functions. It is a key step in solving problems involving angles and distances in trigonometry.
- The hypotenuse is the longest side and opposite the right angle.
- The legs are the other two sides.
Visualizing this triangle helps in understanding how the sides relate to each other through trigonometric functions. It is a key step in solving problems involving angles and distances in trigonometry.
sine and cosine
Sine and cosine are fundamental trigonometric functions that relate the angles of a right triangle to the ratios of its sides.
- Sine of an angle (\( \sin \theta \)) is defined as the ratio of the length of the opposite side to the hypotenuse.
- Cosine of an angle (\( \cos \theta \)) is the ratio of the length of the adjacent side to the hypotenuse.
- \( \sin \theta = \frac{3}{\sqrt{13}} \)
- \( \cos \theta = \frac{2}{\sqrt{13}} \)
reciprocal identities
Reciprocal identities are important relationships in trigonometry that involve taking the reciprocal of basic functions. They help in expressing sin, cos, and tan in different forms. Here are the three main reciprocal identities:
- Cosecant (\( \csc \theta \)) is the reciprocal of sine: \( \csc \theta = \frac{1}{\sin \theta} \).
- Secant (\( \sec \theta \)) is the reciprocal of cosine: \( \sec \theta = \frac{1}{\cos \theta} \).
- Cotangent (\( \cot \theta \)) is the reciprocal of tangent: \( \cot \theta = \frac{1}{\tan \theta} \).
Other exercises in this chapter
Problem 3
Solve the right triangle shown in the figure. Round lengths to two decimal places and express angles to the nearest tenth of a degree. $$A=52.6^{\circ}, c=54$$
View solution Problem 3
Determine the amplitude of each function. Then graph the function and \(y=\sin x\) in the same rectangular coordinate system for \(0 \leq x \leq 2 \pi\) $$y=\fr
View solution Problem 3
In Exercises \(1-6,\) the measure of an angle is given. Classify the angle as acute, right, obtuse, or straight. $$ 83.135^{\circ} $$
View solution Problem 4
Find the exact value of each expression. $$ \sin ^{-1} \frac{\sqrt{3}}{2} $$
View solution