Problem 3
Question
a parametric representation of a curve is given. $$ x=3 t-1, y=t ; 0 \leq t \leq 4 $$
Step-by-Step Solution
Verified Answer
The Cartesian equation is \( x = 3y - 1 \) with \( 0 \leq y \leq 4 \).
1Step 1: Identify the Parametric Equations
The given parametric equations are:\[ x = 3t - 1 \] and \[ y = t \] with the parameter \( t \) in the range \( 0 \leq t \leq 4 \). These equations describe the \( x \) and \( y \) components of the curve in relation to the parameter \( t \).
2Step 2: Eliminate the Parameter
To find a Cartesian equation, we eliminate the parameter \( t \). From the equation \( y = t \), we clearly have \( t = y \). Substitute \( t = y \) into the equation for \( x \):\[ x = 3t - 1 \Rightarrow x = 3y - 1 \].
3Step 3: Determine the Range of \( y \)
Since \( t \) ranges from \( 0 \) to \( 4 \), and \( y = t \), it follows that \( y \) also ranges from \( 0 \) to \( 4 \).
4Step 4: Write the Cartesian Equation and Its Domain
The Cartesian equation for the curve is \( x = 3y - 1 \). The range of \( y \) provides the domain for the graph: \( 0 \leq y \leq 4 \).
5Step 5: Verify the Parametric to Cartesian Conversion
Substitute various values of \( y \) within the range (e.g., \( y = 0, 2, 4 \)) into the Cartesian equation \( x = 3y - 1 \) to ensure they correspond to values obtained by substituting \( t \) in parametric equations. The points (\( x, y \)) such as \( (-1, 0), (5, 2), (11, 4) \) should lie on the line.
Key Concepts
Cartesian equationeliminate the parametercurve representation
Cartesian equation
A Cartesian equation is an equation that describes a curve or a surface in a plane using Cartesian coordinates, which are typically represented by the variables \( x \) and \( y \). These equations are crucial for understanding relationships between variables without needing a parameter. In parametric equations like the one given \( x = 3t - 1 \) and \( y = t \), each variable depends on a third variable, \( t \), known as the parameter.
By converting parametric equations into a Cartesian form (\( x = 3y - 1 \), in this case), we translate the curve's dependence from the parameter \( t \) directly into relationships between \( x \) and \( y \). This removal of the parameter offers a simplified and often linear representation of the curve. It's a more familiar representation that can be easily plotted and analyzed in two-dimensional space.
By converting parametric equations into a Cartesian form (\( x = 3y - 1 \), in this case), we translate the curve's dependence from the parameter \( t \) directly into relationships between \( x \) and \( y \). This removal of the parameter offers a simplified and often linear representation of the curve. It's a more familiar representation that can be easily plotted and analyzed in two-dimensional space.
- The Cartesian form provides a direct relation between \( x \) and \( y \).
- It omits the parameter, aiding in easier graphing and comprehensive problem solving.
eliminate the parameter
Eliminating the parameter in a set of parametric equations is a technique used to find the Cartesian equation. This involves removing the parameter \( t \), the independent variable in the pair of parametric equations.
For instance, we start with the given parametric equations \( x = 3t - 1 \) and \( y = t \). To eliminate \( t \), first express \( t \) in terms of one of the variables. Since \( y = t \), we have \( t = y \).
Substituting this expression for \( t \) into the equation for \( x \) gives us:
This elimination helps:
For instance, we start with the given parametric equations \( x = 3t - 1 \) and \( y = t \). To eliminate \( t \), first express \( t \) in terms of one of the variables. Since \( y = t \), we have \( t = y \).
Substituting this expression for \( t \) into the equation for \( x \) gives us:
- Substitute \( t = y \) into \( x = 3t - 1 \) \[ x = 3(y) - 1 \]
This elimination helps:
- Transform parametric equations into a single, cohesive Cartesian equation.
- Simplify analysis by reducing reliance on the parameter.
curve representation
Curve representation discusses how a curve can be described mathematically using equations. In parametric form, a curve is represented using equations that express the coordinates \( x \) and \( y \) as functions of a parameter \( t \). This approach provides a dynamic way of describing points along the curve based on varying values of \( t \).
However, for easier visualization and understanding, we often prefer the Cartesian representation, which relates \( x \) directly to \( y \). The exercise showcases this transformation. By converting the parametric curve \( x = 3t - 1 \) and \( y = t \) into the Cartesian equation \( x = 3y - 1 \), the essence of the curve is retained in a more straightforward form.
Understanding curve representation helps with:
However, for easier visualization and understanding, we often prefer the Cartesian representation, which relates \( x \) directly to \( y \). The exercise showcases this transformation. By converting the parametric curve \( x = 3t - 1 \) and \( y = t \) into the Cartesian equation \( x = 3y - 1 \), the essence of the curve is retained in a more straightforward form.
Understanding curve representation helps with:
- Providing a clear mathematical description of a geometric shape.
- Facilitating easier graphing on a 2D plane.
- Allowing for greater mathematical manipulations and calculations.
Other exercises in this chapter
Problem 3
Name the conic or limiting form represented by the given equation. Usually you will need to use the process of completing the square (see Examples \(3-5) .\) 9
View solution Problem 3
Plot the points whose polar coordinates are \((3,2 \pi)\), \(\left(-2, \frac{1}{3} \pi\right),\left(-2,-\frac{1}{4} \pi\right),(-1,1),(1,-4 \pi),\left(\sqrt{3},
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Name the conic (horizontal ellipse, vertical hyperbola, and so on) corresponding to the given equation. $$ \frac{-x^{2}}{9}+\frac{y^{2}}{4}=1 $$
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Find the coordinates of the focus and the equation of the directrix for each parabola. Make a sketch showing the parabola, its focus, and its directrix. $$ x^{2
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