Problem 3
Question
A certain cell culture has a doubling time of 4 hours. Initially there were 2000 cells present. Assuming an exponential growth law, determine the time it takes for the culture to contain \(10^{6}\) cells.
Step-by-Step Solution
Verified Answer
The time it takes for the cell culture to contain \(10^6\) cells, given a doubling time of 4 hours and an initial cell count of 2000, can be calculated using the exponential growth formula. Plugging in the known values and solving for \(t\), we find that it takes approximately 36.46 hours for the cell culture to reach \(10^6\) cells.
1Step 1: Identify the exponential growth formula
The exponential growth formula is given by:
\[N(t) = N_0 \cdot 2^{(\frac{t}{T})}\]
where
- \(N(t)\) is the number of cells at time \(t\),
- \(N_0\) is the initial number of cells,
- \(T\) is the doubling time, and
- \(t\) is the time at which the cell count is measured.
In our case, we know the value of \(N_0\) (2000 cells) and \(T\) (4 hours). We want to find the time \(t\) at which the number of cells, \(N(t)\), reaches \(10^6\).
2Step 2: Plug in the known values to the exponential growth formula
To find the time \(t\), we need to plug the given values of \(N_0\), \(T\) and \(N(t)\) into the exponential growth formula:
\[10^6 = 2000 \cdot 2^{(\frac{t}{4})}\]
3Step 3: Solve for the time t
Now, we will solve the equation for \(t\). To do this, we will first divide both sides of the equation by 2000:
\[500 = 2^{(\frac{t}{4})}\]
Next, we will take the logarithm (base 2) of both sides, which allows us to bring down the exponent on the right-hand side:
\[\log_2{500} = \log_2{2^{(\frac{t}{4})}} \Rightarrow \log_2{500} = \frac{t}{4}\]
Finally, we will multiply both sides of the equation by 4 to find the time \(t\):
\[t = 4 \cdot \log_2{500}\]
4Step 4: Calculate the time t
Now we can calculate the time \(t\) required for the cell culture to reach \(10^6\) cells:
\[t = 4 \cdot \log_2{500} \approx 36.46 \text{ hours}\]
So, it takes approximately 36.46 hours for the cell culture to contain \(10^6\) cells.
Key Concepts
Doubling TimeLogarithmsCell Culture Growth
Doubling Time
Doubling time is the period it takes for a quantity growing exponentially to double in size or value. In the context of cell cultures, it refers to the time required for a population of cells to increase twofold. The shorter the doubling time, the faster the growth rate.
Here's how it works:
- Exponential growth means that the population size multiplies over fixed intervals.
- Doubling time helps predict how quickly the population will grow over time, providing a simple metric for comparing growth rates.
Logarithms
Logarithms are the inverse operations of exponentiation. They help in calculations involving exponential growth by transforming multiplication into addition, which simplifies solving equations. In the context of growth, logarithms are essential for determining the time required for growth to reach a certain level.Key points about logarithms in exponential growth:
- They are used to solve equations where the unknown variable is an exponent.
- The logarithm to base 2, commonly written as \( \log_2 \), is frequently used because exponential growth often involves doubling (base 2).
Cell Culture Growth
Cell culture growth refers to the process where cells multiply within a controlled environment. It is a crucial concept in biotechnology, medicine, and biological research. Modeling cell culture growth typically involves exponential functions because cell populations often grow by doubling at constant time intervals, given adequate resources and space.Important aspects of cell culture growth:
- It starts with an initial number of cells, such as 2000 in our example.
- The growth follows the exponential model \( N(t) = N_0 \cdot 2^{(t/T)} \), where \( N(t) \) is the number of cells at time \( t \), \( N_0 \) is the initial cell count, and \( T \) is the doubling time.
- Growth can be influenced by factors like nutrient availability, temperature, and space.
Other exercises in this chapter
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