Problem 3
Question
\(3-6\) . State whether the equation or system of equations is linear. $$ 6 x-\sqrt{3} y+\frac{1}{2} z=0 $$
Step-by-Step Solution
Verified Answer
Yes, the equation is linear.
1Step 1: Identify Linear Equations
Determine whether the given equation is linear by examining its terms. A linear equation only includes variables raised to the first power with no multiplication or division between variables, and no variables inside functions like sine, cosine, square roots, etc.
2Step 2: Analyze Each Term
The given equation is \[6x - \sqrt{3}y + \frac{1}{2}z = 0.\]Analyzing the equation term by term:- The variable x is raised to the first power.- The variable y is outside the square root, which is acceptable as long as the square root does not include y.- The variable z is raised to the first power.None of the terms involve any non-linear functions acting on the variables themselves.
3Step 3: Conclude Linearity
Since all variables (x, y, z) are to the first power and are not inside any non-linear functions, we can conclude the equation is linear. Non-linear functions of variables like powers greater than one, products of variables, or functions such as trigonometric, exponential, and roots directly applied to variables would make them non-linear. Here, the coefficient \(\sqrt{3}\) is simply a constant multiple of the variable y.
Key Concepts
VariablesNon-linear FunctionsConstant MultiplesFirst Power
Variables
In the context of linear equations, a variable is a symbol—typically a letter like \( x \), \( y \), or \( z \)—that represents a number. The value of a variable is not fixed and can change. These are crucial elements in forming linear equations as they help represent unknown values that we aim to find.
- Variables are to the first power in a linear equation.
- They are not multiplied together or divided by other variables.
Non-linear Functions
Linear equations are defined by the absence of non-linear functions acting on their variables. Non-linear functions involve operations that curve the graph of the equation when plotted, such as:
- Raising variables to powers greater than one
- Taking the square root, logarithm, sine, cosine, or any other non-linear mathematical operation directly on variables
Constant Multiples
In linear equations, variables can be multiplied by constants. A constant is a fixed number, not a variable. This multiplication is known as a constant multiple. For instance, in the equation \(6x - \sqrt{3}y + \frac{1}{2}z = 0\):
- The constant 6 is multiplied by \(x\).
- The constant \(\sqrt{3}\) is multiplied by \(y\).
- The constant \(\frac{1}{2}\) is multiplied by \(z\).
First Power
When we say that variables in a linear equation are raised to the 'first power', we mean that the exponent of the variable is one. This is a critical feature of linear equations. If a variable had an exponent other than one, the equation would be non-linear.
Using our example, the variables \(x\), \(y\), and \(z\) are all raised to the first power in the equation \(6x - \sqrt{3}y + \frac{1}{2}z = 0\). This simplicity ensures that the relationship represented by the equation is straightforward, leading to a straight line when graphed, which is the hallmark of linearity.
Using our example, the variables \(x\), \(y\), and \(z\) are all raised to the first power in the equation \(6x - \sqrt{3}y + \frac{1}{2}z = 0\). This simplicity ensures that the relationship represented by the equation is straightforward, leading to a straight line when graphed, which is the hallmark of linearity.
Other exercises in this chapter
Problem 3
Calculate the products \(A B\) and \(B A\) to verify that \(B\) is the inverse of \(A .\) $$ A=\left[\begin{array}{ll}{4} & {1} \\ {7} & {2}\end{array}\right] \
View solution Problem 3
Which of the following operations can we perform for a matrix \(A\) of any dimension? \(\begin{array}{llll}{\text { (i) } A+A} & {\text { (ii) } 2 A} & {\text {
View solution Problem 3
The following matrix is the augmented matrix of a system of linear equations in the variables \(x, y,\) and \(z .\) (It is given in reduced row-echelon form.) $
View solution Problem 4
Fill in the blanks with appropriate numbers to calculate the determinant. Where there is " " , choose the appropriate sign \((+\text { or }-) .\) (a) \(\left|\b
View solution