Problem 3
Question
1-8 Find \(\sin 2 x, \cos 2 x,\) and \(\tan 2 x\) from the given information. \(\cos x=\frac{4}{5}, \quad \csc x<0\)
Step-by-Step Solution
Verified Answer
\( \sin 2x = -\frac{24}{25}, \cos 2x = \frac{7}{25}, \tan 2x = -\frac{24}{7} \).
1Step 1: Determine sin x using cosine
Given that \( \cos x = \frac{4}{5} \), we need to find \( \sin x \). Since \( \cos^2 x + \sin^2 x = 1 \), we have: \[ \sin^2 x = 1 - \cos^2 x = 1 - \left(\frac{4}{5}\right)^2 = 1 - \frac{16}{25} = \frac{9}{25} \]\[ \sin x = \pm \frac{3}{5} \]. Since \( \csc x < 0 \) and \( \csc x = \frac{1}{\sin x} \), \( \sin x < 0 \). Thus, \( \sin x = -\frac{3}{5} \).
2Step 2: Use sin and cos to find sin 2x
The formula for \( \sin 2x \) is \( 2 \sin x \cos x \). Substituting the values: \[ \sin 2x = 2 \left(-\frac{3}{5}\right)\left(\frac{4}{5}\right) = -\frac{24}{25} \].
3Step 3: Use sin and cos to find cos 2x
The formula for \( \cos 2x \) is \( \cos^2 x - \sin^2 x \). Using the calculated values: \[ \cos 2x = \left(\frac{4}{5}\right)^2 - \left(-\frac{3}{5}\right)^2 = \frac{16}{25} - \frac{9}{25} = \frac{7}{25} \].
4Step 4: Use sin and cos to find tan 2x
The formula for \( \tan 2x \) is \( \frac{\sin 2x}{\cos 2x} \). Using the calculated \( \sin 2x \) and \( \cos 2x \): \[ \tan 2x = \frac{-\frac{24}{25}}{\frac{7}{25}} = -\frac{24}{7} \].
Key Concepts
Trigonometric IdentitiesSine Double AngleCosine Double AngleTangent Double Angle
Trigonometric Identities
Trigonometric identities are fundamental tools in mathematics that relate the angles and sides of triangles. They enable us to simplify complex mathematical problems by expressing one trigonometric function in terms of others. A key identity used in many calculations is the Pythagorean identity:
- \( \cos^2 x + \sin^2 x = 1 \)
- \( \sin^2 x = 1 - \cos^2 x \)
- \( \sin x = \pm \frac{3}{5} \)
Sine Double Angle
The sine double angle formula is a powerful trigonometric identity that expresses \( \sin 2x \) in terms of \( \sin x \) and \( \cos x \). The formula is given by:
- \( \sin 2x = 2 \sin x \cos x \)
- \( \sin 2x = 2(-\frac{3}{5})(\frac{4}{5}) = -\frac{24}{25} \)
Cosine Double Angle
The cosine double angle formula provides a way to calculate \( \cos 2x \) using \( \sin x \) and \( \cos x \). The formula is expressed as:
- \( \cos 2x = \cos^2 x - \sin^2 x \)
- \( \cos 2x = 2\cos^2 x - 1 \)
- \( \cos 2x = 1 - 2\sin^2 x \)
- \( \cos 2x = \frac{16}{25} - \frac{9}{25} = \frac{7}{25} \)
Tangent Double Angle
The tangent double angle formula helps in determining \( \tan 2x \) from known sine and cosine values. The formula is as follows:
- \( \tan 2x = \frac{\sin 2x}{\cos 2x} \)
- \( \tan 2x = \frac{-\frac{24}{25}}{\frac{7}{25}} = -\frac{24}{7} \)
Other exercises in this chapter
Problem 3
Find the exact value of each expression, if it is defined. (a) \(\sin ^{-1} \frac{\sqrt{2}}{2}\) (b) \(\cos ^{-1} \frac{\sqrt{3}}{2}\) (c) \(\sin ^{-1}\left(-\f
View solution Problem 3
\(1-12\) : Use an addition or subtraction formula to find the exact value of the expression, as demonstrated in Example \(1 .\) $$ \cos 105^{\circ} $$
View solution Problem 4
Write the trigonometric expression in terms of sine and cosine, and then simplify. $$ \tan \theta \csc \theta $$
View solution Problem 4
Find all solutions of the equation. $$\sqrt{2} \cos x-1=0$$
View solution