Problem 29
Question
Write a system of linear equations with two variables whose solution satisfies the problem. State what each variable represents. Then solve the system. Admission prices to a movie are \(\$ 4\) for children and \(\$ 7\) for adults. If 75 tickets were sold for \(\$ 456\) how many of each type of ticket were sold?
Step-by-Step Solution
Verified Answer
23 children's tickets and 52 adult tickets were sold.
1Step 1: Define the Variables
Let's let \( x \) represent the number of children's tickets sold and \( y \) represent the number of adult tickets sold. Our goal is to find the values of \( x \) and \( y \) that satisfy the given conditions.
2Step 2: Set Up the Equations
We have two conditions: the total number of tickets sold and the total sales amount. From these, we can make two equations.1. The sum of the number of children's and adult tickets sold is 75: \[x + y = 75\]2. The sum of money from tickets sold should be \\(456. Children's tickets are \\)4 and adults' tickets are \$7: \[4x + 7y = 456\]
3Step 3: Solve the System of Equations by Substitution
Solve the first equation for \( x \):\[x = 75 - y\]Substitute \( x = 75 - y \) into the second equation:\[4(75 - y) + 7y = 456\]This simplifies to:\[300 - 4y + 7y = 456\]Combine like terms:\[3y = 156\]Divide both sides by 3:\[y = 52\]
4Step 4: Solve for the Other Variable
Now that we know \( y = 52 \), substitute it back into the equation \( x = 75 - y \):\[x = 75 - 52\]This gives:\[x = 23\]
5Step 5: Verify the Solution
Substitute \( x = 23 \) and \( y = 52 \) into both original equations to verify:For the first equation:\[23 + 52 = 75\] which is true.For the second equation:\[4(23) + 7(52) = 92 + 364 = 456\] which is also true.The solution satisfies both equations.
Key Concepts
Understanding Systems of EquationsThe Substitution Method ExplainedVariable Representation in EquationsSolving the Equations
Understanding Systems of Equations
In algebra, a system of equations refers to a set of equations with multiple variables. These equations are solved together because they describe relationships between the same set of variables.
For instance, in the given problem, we have two variables: the number of children's tickets (\(x\)) and the number of adult tickets (\(y\)). Each equation in the system provides different insights into these variables:
For instance, in the given problem, we have two variables: the number of children's tickets (\(x\)) and the number of adult tickets (\(y\)). Each equation in the system provides different insights into these variables:
- The first equation deals with the total number of tickets sold.
- The second equation is about the total amount of money from selling the tickets.
The Substitution Method Explained
The substitution method is a powerful technique to solve systems of equations. It involves substituting one variable's expression in terms of another to simplify the problem.
Here’s a step-by-step guide of how it worked in the problem:
Here’s a step-by-step guide of how it worked in the problem:
- First, we solved one of the equations for a single variable. In this case, the first equation \(x + y = 75\) was rearranged to \(x = 75 - y\).
- This expression, \(75 - y\), replaces \(x\) in the second equation, reducing it to an equation with only one variable.
- After substitution, solving the resultant equation yields the value of one variable.
Variable Representation in Equations
Variable representation is crucial to understanding the problem context and translating it into mathematical language. Defining what each variable stands for sets the stage for solving an equation system.
In this exercise:
In this exercise:
- \(x\) represents the number of children's tickets sold.
- \(y\) represents the number of adult tickets sold.
Solving the Equations
The ultimate goal of dealing with systems of equations is to find values for variables that meet all conditions specified in the equations.
In this task:
In this task:
- Once \(y\) was found to be 52 from the substitution, we used this value to find \(x\) by substituting back into \(x = 75 - y\). This gave \(x = 23\).
- Verification was performed by substituting \(x = 23\) and \(y = 52\) back into both original equations.
- The first equation checked the total count of tickets: \(23 + 52 = 75\).
- The second equation confirmed the financial tally: \(4(23) + 7(52) = 456\).
Other exercises in this chapter
Problem 29
Use Cramer's rule to solve the system of linear equations. $$ \begin{array}{r} 7 x+4 y=23 \\ 11 x-5 y=70 \end{array} $$
View solution Problem 29
Use Gaussian elimination with backward substitution to solve the system of linear equations. Write the solution as an ordered pair or an ordered triple whenever
View solution Problem 29
If possible, solve the system. $$ \begin{aligned} \frac{1}{2} x-y+\frac{1}{2} z &=-4 \\ x+2 y-3 z &=20 \\ -\frac{1}{2} x+3 y+2 z &=0 \end{aligned} $$
View solution Problem 30
Graph the solution set to the system of inequalities. $$ \begin{aligned} &x^{2}-y \leq 0\\\ &x^{2}+y^{2} \leq 6 \end{aligned} $$
View solution