Problem 29
Question
Write a plausible Lewis structure for crotonaldehyde, \(\mathrm{CH}_{3} \mathrm{CHCHCHO},\) a substance used in tear gas and insecticides.
Step-by-Step Solution
Verified Answer
The plausible lewis structure for crotonaldehyde is: H₃C-CH=CH-CHO, with 22 valence electrons distributed to achieve maximum stability.
1Step 1: Determine Total Number of Valence Electrons
Firstly, calculate the total number of valence electrons in the molecule. Carbon (C) has 4 valence electrons, Hydrogen (H) has 1 valence electron, and Oxygen (O) has 6 valence electrons. For our molecule, we have 4 Carbon atoms, 5 Hydrogen atoms, and 1 Oxygen atom. So, the total number of valence electrons is \((4*4) + (5*1) + (6*1) = 22\) valence electrons.
2Step 2: Draw the Skeletal Structure
Next, connect the atoms to form the skeletal structure of the molecule. Typically, Carbon is the central atom, Hydrogen and Halogens are generally terminal. So, the skeletal structure will look something like this: H₃C-CH=CH-CHO.
3Step 3: Distribute electrons
Now, we distribute the electrons to satisfy the Octet Rule. The double lines represent a double bond, which means there are four electrons between those Carbon atoms. The remaining bonds are single, each representing two shared electrons. After connecting the atoms and satisfying the Carbon atoms Octet rule, if there are some valence electrons left, place them on the Oxygen atom.
4Step 4: Review and check
Finally, check the structure to ensure that every atom (other than Hydrogen) obeys the octet rule, and the total number of used electrons matches the number of valence electrons calculated in Step 1. If it does not satisfy these conditions, reevaluate your structure.
Key Concepts
Valence ElectronsOctet RuleCarbon Compounds
Valence Electrons
Valence electrons play a critical role in determining how atoms bond with one another. They are the electrons located in the outermost shell of an atom. Knowing how many valence electrons are involved is key in drawing Lewis structures.
For example, in crotonaldehyde (\(\text{CH}_3\text{CHCHCHO}\)), you'll first need to calculate the total number of valence electrons. This involves adding the valence electrons of each atom in the molecule:
These valence electrons will be shared or transferred between atoms to create bonds and satisfy the Octet Rule, which is essential in forming a stable molecule.
For example, in crotonaldehyde (\(\text{CH}_3\text{CHCHCHO}\)), you'll first need to calculate the total number of valence electrons. This involves adding the valence electrons of each atom in the molecule:
- Carbon (C) has 4 valence electrons.
- Hydrogen (H) has 1 valence electron.
- Oxygen (O) has 6 valence electrons.
These valence electrons will be shared or transferred between atoms to create bonds and satisfy the Octet Rule, which is essential in forming a stable molecule.
Octet Rule
The Octet Rule is a guideline in chemistry that suggests atoms are often more stable when they have eight electrons in their valence shell. This rule is particularly applicable for nonmetals and helps you draw accurate Lewis structures.
When constructing Lewis structures like that of crotonaldehyde:
This rigorous step-by-step arrangement ensures the resulting structure is not only accurate but also energetically favorable.
When constructing Lewis structures like that of crotonaldehyde:
- Begin by arranging the atoms in a logical manner, adhering to organic chemistry rules.
- Form bonds between atoms by sharing pairs of valence electrons.
- For crotonaldehyde, you need double bonds between a couple of the carbon atoms, represented by double lines.
This rigorous step-by-step arrangement ensures the resulting structure is not only accurate but also energetically favorable.
Carbon Compounds
Carbon compounds, also known as organic compounds, form the basis of organic chemistry. Carbon's tetravalency—ability to form four bonds—allows it to create complex structures such as chains, rings, and branches.
In crotonaldehyde, carbon forms the backbone of the molecule. This compound is a good example because it showcases carbon’s ability to form different types of bonds:
Understanding carbon compounds and their bonding helps you appreciate the vast possibilities of molecular structure and chemical reactions in organic chemistry.
In crotonaldehyde, carbon forms the backbone of the molecule. This compound is a good example because it showcases carbon’s ability to form different types of bonds:
- Single bonds, as seen between carbon and hydrogen.
- Double bonds, as present between certain carbon atoms.
- Oxygen, which often forms a double bond with carbon in organic compounds, completes its octet.
Understanding carbon compounds and their bonding helps you appreciate the vast possibilities of molecular structure and chemical reactions in organic chemistry.
Other exercises in this chapter
Problem 27
The following polyatomic anions involve covalent bonds between O atoms and the central nonmetal atom. Propose an acceptable Lewis structure for each. (a) \(\mat
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Write a plausible Lewis structure for \(\mathrm{C}_{3} \mathrm{O}_{2},\) a substance known as carbon suboxide.
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Which of the following molecules would you expect to have a resultant dipole moment \((\mu) ;\) (a) \(\mathrm{F}_{2}\), (b) \(\mathrm{NO}_{2}\) (c) \(\mathrm{BF
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