Problem 29
Question
Water traveling along a straight portion of a river normally flows fastest in the middle, and the speed slows to almost zero at the banks. Consider a long straight stretch of river flowing north, with parallel banks 40 \(\mathrm{m}\) apart. If the maximum water speed is \(3 \mathrm{m} / \mathrm{s},\) we can use a quadratic function as a basic model for the rate of water flow \(x\) units from the west bank: \(f(x)=\frac{3}{400} x(40-x)\) $$\begin{array}{l}{\text { (a) A boat proceeds at a constant speed of } 5 \mathrm{m} / \mathrm{s} \text { from a }} \\ {\text { point } A \text { on the west bank while maintaining a heading }} \\ {\text { perpendicular to the bank. How far down the river on }}\end{array}$$$$ \begin{array}{l}{\text { the opposite bank will the boat touch shore? Graph the }} \\ {\text { path of the boat. }}\end{array}$$ $$\begin{array}{l}{\text { (b) Suppose we would like to pilot the boat to land at the }} \\ {\text { point } B \text { on the east bank directly opposite } A . \text { If we }} \\ {\text { maintain a constant speed of } 5 \mathrm{m} / \mathrm{s} \text { and a constant }} \\ {\text { heading, find the angle at which the boat should head. }} \\ {\text { Then graph the actual path the boat follows. Does the }} \\ {\text { path seem realistic? }}\end{array}$$
Step-by-Step Solution
VerifiedKey Concepts
Boat Trajectory Calculations
- The boat's speed perpendicular to the bank (5 m/s).
- The river's speed as a function: \(f(x) = \frac{3}{400} x(40 - x)\).
Perpendicular Speed and Drift
- Determine the average speed along the river width, thanks to the quadratic profile.
- The time taken for the boat to cross (40m / 5m/s = 8s).
- Estimate the downstream drift: average river speed (1.5 m/s) multiplied by crossing time: 12 meters drift.
Graphing River and Boat Paths
- Start at the point of origin, A (0,0).
- Consider the effect of river flow, leading to an endpoint at (40,12) to account for drift.
- The path results in a slanted line from west to east, illustrating downstream displacement.