Problem 29
Question
Use the quotient rule to simplify the expressions in Exercises. Assume that \(x>0.\) $$\frac{\sqrt{150 x^{4}}}{\sqrt{3 x}}$$
Step-by-Step Solution
Verified Answer
The simplified version of the given expression \(\frac{\sqrt{150 x^{4}}}{\sqrt{3 x}}\) using the quotient rule is \(5x\sqrt{2}\).
1Step 1: Rewrite the expression using the quotient rule
Apply the quotient rule for radicals on the given expression which says that \(\sqrt{\frac{a}{b}} = \frac{\sqrt{a}}{\sqrt{b}}\). The expression becomes: \(\frac{\sqrt{150 x^{4}}}{\sqrt{3 x}}.\)
2Step 2: Simplify the square roots separately
Here, separate the factors under the radical that have perfect square roots and simplify: \(\sqrt{150 x^{4}} = \sqrt{25*6*\left(x^{2}\right)^{2}} = 5x^{2}\sqrt{6}\) and \(\sqrt{3 x} = \sqrt{3*x^{1}} = x\sqrt{3}\). So, the expression becomes \(\frac{5x^{2}\sqrt{6}}{x\sqrt{3}}\).
3Step 3: Reduce the expression to lowest term
In this step, the goal is to cancel out common terms in the numerator and the denominator. On simplifying, \(\frac{5x^{2}\sqrt{6}}{x\sqrt{3}} = 5x\sqrt{\frac{6}{3}} = 5x\sqrt{2}\).
Key Concepts
Radical ExpressionsSimplificationSquare Roots
Radical Expressions
Radical expressions involve roots, most commonly square roots. When working with radicals, the key is to understand how to manipulate them in the form of an expression. For example, in the problem, we deal with
Radical expressions can look complicated, but understanding the role of factors under the radicals allows us to find perfect squares and ease the simplification process.
- The square root of a number: \(\sqrt{150x^4}\).
- The radical part of a fraction: \(\frac{\sqrt{a}}{\sqrt{b}}\).
Radical expressions can look complicated, but understanding the role of factors under the radicals allows us to find perfect squares and ease the simplification process.
Simplification
Simplification is the process of reducing an expression to its simplest form. In math, this often means eliminating radicals or reducing them to easy-to-manage terms. When simplifying, start by splitting the factors inside the radicals into perfect squares. For example:
The last step in simplification involves reducing the rational expression by canceling common terms in the numerator and the denominator, such as reducing \(\frac{5x^2}{x} = 5x\). This results in a cleaner and more concise version of the original expression.
- The number \(150\) can be split into \((25 \times 6)\), so \(\sqrt{150} = 5\sqrt{6}\).
- Similarly, \(x^4\) can be broken down to \(\left(x^2\right)^2\), simplifying to \(x^2\).
The last step in simplification involves reducing the rational expression by canceling common terms in the numerator and the denominator, such as reducing \(\frac{5x^2}{x} = 5x\). This results in a cleaner and more concise version of the original expression.
Square Roots
Square roots ask the question, "What number multiplied by itself gives this value?" For example, the square root of \(25\) is \(5\) because \(5 \times 5 = 25\).
In expressions with variables, like \((x^4)\), the square root works similarly but focuses on powers. The square root of \(x^4\) is \(x^2\) because \((x^2 \times x^2 = x^4)\). When dealing with non-perfect squares like \(\sqrt{150}\), we look for the largest perfect square factor, which is \(\sqrt{25}\) in our case.
Breaking down and understanding the underlying factors allows simplification of square roots even if the term isn't perfect.
In expressions with variables, like \((x^4)\), the square root works similarly but focuses on powers. The square root of \(x^4\) is \(x^2\) because \((x^2 \times x^2 = x^4)\). When dealing with non-perfect squares like \(\sqrt{150}\), we look for the largest perfect square factor, which is \(\sqrt{25}\) in our case.
Breaking down and understanding the underlying factors allows simplification of square roots even if the term isn't perfect.
- Identify parts that are perfect squares. For \(150\), this is \(25\).
- Simplify. \(\sqrt{25} = 5\).
Other exercises in this chapter
Problem 28
Find each product. $$\left(7 x^{2}-2\right)\left(3 x^{2}-5\right)$$
View solution Problem 28
Simplify each exponential expression in Exercises 23–64. $$x^{11} \cdot x^{5}$$
View solution Problem 29
Multiply or divide as indicated. $$\frac{x^{2}-25}{2 x-2} \div \frac{x^{2}+10 x+25}{x^{2}+4 x-5}$$
View solution Problem 29
Factor each trinomial, or state that the trinomial is prime. $$ 4 x^{2}+16 x+15 $$
View solution