Problem 29
Question
Use the method of Example 1 to calculate \(f^{\prime}(x)\) for the given function \(f\). $$ f(x)=\sqrt{3 x+7} $$
Step-by-Step Solution
Verified Answer
The derivative of the function is \(f'(x) = \frac{3}{2\sqrt{3x + 7}}\).
1Step 1: Identify the Outer and Inner Functions
The function given is a composite function. Identify that the outer function is the square root function, and the inner function is the linear function: \(g(x) = 3x + 7\) and \(h(u) = \sqrt{u}\), where \(u = 3x + 7\).
2Step 2: Differentiate the Outer Function
Find the derivative of the outer function \(h(u) = \sqrt{u}\). The derivative is \(h'(u) = \frac{1}{2\sqrt{u}}\).
3Step 3: Differentiate the Inner Function
Differentiate the inner function \(g(x) = 3x + 7\). The derivative is \(g'(x) = 3\).
4Step 4: Apply the Chain Rule
Apply the chain rule, which states that if \(f(x) = h(g(x))\), then \(f'(x) = h'(g(x)) \cdot g'(x)\). Substitute the derivatives found in steps 2 and 3: \(f'(x) = \frac{1}{2\sqrt{3x + 7}} \cdot 3\).
5Step 5: Simplify the Expression
Simplify the expression for \(f'(x)\): \(f'(x) = \frac{3}{2\sqrt{3x + 7}}\).
Key Concepts
DifferentiationComposite FunctionsDerivative of Square Root Function
Differentiation
In calculus, differentiation is the method of finding the derivative of a function. Essentially, it measures how a function changes as its input changes. Understanding this concept is crucial in tackling problems related to rates of change, slopes of curves, and motion.During differentiation, certain rules and functions need to be understood and applied:
- The Power Rule: Useful for differentiating terms like \(x^n\), where this results in \(nx^{n-1}\).
- The Constant Rule: The derivative of a constant is always zero.
- The Sum/Difference Rule: The derivative of a sum (or difference) of functions is simply the sum (or difference) of their derivatives.
Composite Functions
Composite functions involve combining two or more functions into a single function. It’s like nesting functions within each other. If you have a function \(f(x)\) and another function \(g(x)\), forming \(f(g(x))\), you create a composite function.Understanding the components of composite functions means identifying the inner function and the outer function. In formal terms, for \(f(g(x))\):
- The inner function is \(g(x)\).
- The outer function is \(f(u)\), where \(u = g(x)\).
Derivative of Square Root Function
The derivative of a square root function involves some specific rules and transformations, specifically when the function is embedded in a composite setting.For a basic square root function, \(f(x) = \sqrt{x}\), its derivative can be found using the chain rule because it can be rewritten using a power: \(f(x) = x^{1/2}\). Differentiating this using the power rule results in:\[f'(x) = \frac{1}{2} x^{-1/2} = \frac{1}{2\sqrt{x}}\]In the context of composite functions like \(\sqrt{3x + 7}\), the derivative must first identify the inner function \(3x + 7\) and apply the chain rule. This involves finding the derivative of the outer function first (the square root) and then multiplying by the derivative of the inner function. This combination allows you to approach more complex functions systematically, achieving not just the derivative of simple expressions, but of much more involved ones.
Other exercises in this chapter
Problem 29
A function \(f\) and a point \(P\) are given. Find the slope-intercept form of the equation of the tangent line to the graph of \(f\) at \(P\). $$ f(x)=5 x^{2}
View solution Problem 29
Use the Quotient Rule to compute the derivative of the given expression with respect to \(x .\) $$ (x-1) /(x+1) $$
View solution Problem 30
Differentiate the given expression with respect to \(x\). $$ \operatorname{arcsec}(1 / x) $$
View solution Problem 30
Find \(d y / d x\) and \(d^{2} y / d x^{2}\) at the point \(P_{0}\) by implicit differentiation. \(y^{3}-2 x y=20 \quad P_{0}=(-3,2)\)
View solution