Problem 29
Question
Two equipotential surfaces surround \(\mathrm{a}+1.50 \times 10^{-8}-\mathrm{C}\) point charge. How far is the 190-V surface from the 75.0 -V surface?
Step-by-Step Solution
Verified Answer
The distance is approximately 1.09 meters.
1Step 1: Understand the Concept of Equipotential Surfaces
Equipotential surfaces are surfaces where the electric potential is constant. The difference between these surfaces indicates a change in potential energy. In this problem, we are dealing with two surfaces at potentials of 190 V and 75 V.
2Step 2: Recall the Formula for Electric Potential Around a Point Charge
The electric potential (V) at a distance (r) from a point charge (q) is given by the formula: \[V = \frac{k \cdot q}{r}\]where \(k\) is the Coulomb's constant (\(8.99 \times 10^9 \text{ N m}^2/\text{C}^2\)) and \(q\) is the point charge.
3Step 3: Express Distances Based on Potentials
Let \(r_1\) be the distance to the 190-V surface and \(r_2\) be the distance to the 75.0-V surface. Using the electric potential formula, we have:\[190 = \frac{k \cdot a}{r_1}\]\[75 = \frac{k \cdot a}{r_2}\]
4Step 4: Relate the Two Equations
From the equations derived, solve for \(r_1\) and \(r_2\):\[r_1 = \frac{k \cdot a}{190}\]\[r_2 = \frac{k \cdot a}{75}\]The difference \(r_2 - r_1\) will give the distance between the two surfaces.
5Step 5: Calculate the Distance Between the Surfaces
Substitute \(a = 1.50 \times 10^{-8} \,\text{C}\) and \(k = 8.99 \times 10^9 \,\text{N m}^2/\text{C}^2\) into the equations:\[r_1 = \frac{8.99 \times 10^9 \,\text{N m}^2/\text{C}^2 \times 1.50 \times 10^{-8} \,\text{C}}{190} \approx 0.7105 \,\text{m}\]\[r_2 = \frac{8.99 \times 10^9 \,\text{N m}^2/\text{C}^2 \times 1.50 \times 10^{-8} \,\text{C}}{75} \approx 1.798 \,\text{m}\]Thus, the distance between the two surfaces is:\[1.798 \,\text{m} - 0.7105 \,\text{m} = 1.0875 \,\text{m}\]
6Step 6: Conclusion
Therefore, the 190-V equipotential surface is approximately 1.09 meters from the 75.0-V equipotential surface.
Key Concepts
Equipotential SurfacesElectric PotentialCoulomb's ConstantPoint ChargePotential Difference
Equipotential Surfaces
Equipotential surfaces are fascinating and essential concepts in electrostatics. These surfaces represent regions in an electric field where every point has the same electric potential. Imagine them as invisible map contours but in the realm of electric fields. Along these surfaces, the potential energy does not change. Consequently, no work is done when moving a charge along an equipotential surface.
- They are always perpendicular to electric field lines.
- In the case of a point charge, these surfaces are spherical shells centered around the charge.
- The potential difference between any two equipotential surfaces gives insight into how much work would be needed to move a charge between them.
Electric Potential
Electric potential is a critical concept in understanding electric fields. It refers to the amount of electric potential energy per unit charge at a specific point in the field. It is often thought of as the energy landscape for charges within the field.
- Measured in volts (V), a scalar quantity.
- Describes the electric condition of an object placed in the field.
- Provides insight into how an electric field will influence a test charge.
Coulomb's Constant
Coulomb's constant, often represented as \(k\), is a fundamental physical constant used in electrostatics. It ensures that we can quantify the amount of electrostatic force or electric potential exerted by a charge over a distance.
- The constant value is \(8.99 \times 10^9 \, \text{N m}^2/\text{C}^2\).
- It signifies the strength of the electrostatic force within a vacuum.
- Used in formulas like the electric potential formula \(V = \frac{k \cdot q}{r}\).
Point Charge
In electrostatics, a point charge is an idealized model representing a charged object with negligible physical dimensions compared to the problem's scale. Through this simplification:
- All the charge is considered to be located at a single point.
- Commonly used in theoretical models and problems to simplify calculations.
- Allows the use of straightforward equations to determine electric potential and field strength.
Potential Difference
Potential difference, also known as voltage, is the measure of the difference in electric potential between two points. It's the "push" or "pull" that drives electric charges to move through a conductor.
- Measured in volts.
- Represents the work needed per unit charge to move a charge between two points against an electric field.
- In the exercise, it signifies the difference in potential energy between the two equipotential surfaces.
Other exercises in this chapter
Problem 26
One particle has a mass of \(3.00 \times 10^{-3} \mathrm{~kg}\) and a charge of \(+8.00 \mu \mathrm{C}\). A second particle has a mass of \(6.00 \times 10^{-3}
View solution Problem 27
A spark plug in an automobile engine consists of two metal conductors that are separated by a distance of \(0.75 \mathrm{~mm}\). When an electric spark jumps be
View solution Problem 30
The inner and outer surfaces of a cell membrane carry a negative and positive charge, respectively. Because of these charges, a potential difference of about \(
View solution Problem 31
When you walk across a rug on a dry day, your body can become electrified, and its electric potential can change. When the potential becomes large enough, a spa
View solution