Problem 29
Question
The mean of \(n\) items is \(\bar{x}\). If each item is successively increased by \(3,3^{2}, 3^{3}, \ldots .3^{n}\), then new mean equals (A) \(\bar{x}+\frac{3^{n+1}}{n}\) (B) \(\bar{x}+3 \frac{\left(3^{n}-1\right)}{2 n}\) (C) \(\bar{x}+\frac{3^{n}}{n}\) (D) \(\bar{x}+3 \frac{\left(3^{n}-1\right)}{2 n}\)
Step-by-Step Solution
Verified Answer
The new mean is option (B): \(\bar{x}+3 \frac{(3^{n}-1)}{2n}\).
1Step 1: Calculate Original Total Sum
The original mean of the items is given as \( \bar{x} \). Therefore, the total sum of the \( n \) items is \( n \times \bar{x} \).
2Step 2: Calculate Change in Each Item
Each item is successively increased by powers of 3. This means the increments are \( 3, 3^2, 3^3, \ldots, 3^n \).
3Step 3: Calculate Total Change in Value
Sum the series of changes: \( 3 + 3^2 + 3^3 + \ldots + 3^n \). This is a geometric series with the first term \( a = 3 \) and common ratio \( r = 3 \), up to \( n \) terms.
4Step 4: Sum of Geometric Series Formula
Use the formula for the sum of a geometric series: \( S_n = a \frac{r^n - 1}{r - 1} \). Plugging in our values gives: \( 3 \frac{3^n - 1}{3 - 1} = \frac{3(3^n - 1)}{2} \).
5Step 5: Calculate New Total Sum
Add the total change to the original total sum: \( n \times \bar{x} + \frac{3(3^n - 1)}{2} \).
6Step 6: Calculate New Mean
Divide the new total sum by \( n \) to find the new mean: \( \bar{x} + \frac{3(3^n - 1)}{2n} \).
7Step 7: Select the Correct Option
Comparing this new mean with the options, the correct one is (B): \( \bar{x} + 3 \frac{\left(3^{n}-1\right)}{2 n} \).
Key Concepts
Understanding Mean CalculationIncrement in SequenceGeometric ProgressionSum of Powers
Understanding Mean Calculation
The mean, often referred to as the average, is a central concept in statistics that helps summarize a set of numbers. It's calculated by adding up all the individual values and then dividing by the number of items you have. This gives you one single number that represents the central tendency of the data.
To better understand how this is applied in practical situations, consider that the mean is not just about numbers in isolation. Instead, it tells a story about all the data points at once. For example, if you have three test scores: 85, 90, and 95, the mean would be calculated as follows:
To better understand how this is applied in practical situations, consider that the mean is not just about numbers in isolation. Instead, it tells a story about all the data points at once. For example, if you have three test scores: 85, 90, and 95, the mean would be calculated as follows:
- Add together the numbers: 85 + 90 + 95 = 270
- Divide the total by the number of scores: 270 / 3 = 90
Increment in Sequence
Increment refers to a gradual increase in quantity. In sequences, increments often follow a specific pattern. In mathematical sequences, a common form of increment is represented through constant additions or multiplications.
In this exercise, each item in the original set is being increased by powers of 3. This is a special case of increment represented by:
In this exercise, each item in the original set is being increased by powers of 3. This is a special case of increment represented by:
- First increment by 3
- Second increment by 9 which is 3 squared
- Third increment by 27 which is 3 cubed, and so on
Geometric Progression
Geometric progression, or geometric sequence, is a sequence of numbers where each term after the first is found by multiplying the previous one by a fixed, non-zero number called the common ratio. In the exercise, increments of 3, 9, 27, etc., form a geometric sequence. The first term is 3 and the common ratio also is 3.
Such sequences are characterized by their exponential growth or decay, depending on the common ratio.
Such sequences are characterized by their exponential growth or decay, depending on the common ratio.
- Common ratio greater than one: sequence grows exponentially.
- Common ratio between zero and one: sequence shrinks.
Sum of Powers
The sum of powers in a geometric series is a concept that allows us to add up a sequence of numbers that are raised to incrementing powers. Specifically, when confronted with series like 3, 9, 27, ..., these numbers are powers of 3.
To calculate the sum of such a series where each term is found by multiplying by a consistent base, we use the formula to find the sum of a geometric series:
\[ S_n = a \frac{r^n - 1}{r - 1} \]
Here, for example, the first term \( a \) is 3, the ratio \( r \) is also 3, and you determine \( n \) depending on how many terms you have. Using our knowledge of powers and geometric series formulae lets us find the total sum quickly, which could otherwise be computationally intensive.
To calculate the sum of such a series where each term is found by multiplying by a consistent base, we use the formula to find the sum of a geometric series:
\[ S_n = a \frac{r^n - 1}{r - 1} \]
Here, for example, the first term \( a \) is 3, the ratio \( r \) is also 3, and you determine \( n \) depending on how many terms you have. Using our knowledge of powers and geometric series formulae lets us find the total sum quickly, which could otherwise be computationally intensive.
Other exercises in this chapter
Problem 26
If the variate of a distribution takes the values 1,2 , \(3, \ldots n\) with frequencies \(n, n-1, n-2, \ldots .3,2,1\), then mean value of the distribution is
View solution Problem 27
The means of five observations is 4 and their variance is \(5.2\). If three of these observations are 1,2 and 6 , then the other two are (A) 2 and 9 (B) 3 and 8
View solution Problem 32
The average salary of male employees in a firm was Rs. 520 and that of females was Rs. 420 . The mean salary of all the employees was Rs. \(500 .\) The percenta
View solution Problem 33
The average weight of students in a class of 35 students is \(40 \mathrm{~kg}\). If the weight of the teacher be included, the average rises by \(\frac{1}{2} \m
View solution