Problem 29
Question
Step-by-Step Solution
Verified Answer
The function \( f \) is bounded by \(|L| + 1\) on the interval \((a-\delta, a+\delta)\).
1Step 1: Understanding the Given Information
We know that the limit \( \lim_{x \rightarrow a} f(x) = L \) and that \( f(a) \) exists. Although \( f(a) \) may not equal \( L \), the function approaches \( L \) as \( x \) approaches \( a \).
2Step 2: Applying the Definition of Limit
By the definition of a limit, for any \( \epsilon > 0 \), there exists a \( \delta > 0 \) such that if \( 0 < |x - a| < \delta \), then \( |f(x) - L| < \epsilon \). This means \( f(x) \) is very close to \( L \) in the interval \( (a - \delta, a + \delta) \) except possibly at \( a \).
3Step 3: Choosing an Appropriate \( \epsilon \)
Choose \( \epsilon = 1 \). Therefore, there exists a \( \delta > 0 \) such that if \( 0 < |x - a| < \delta \), then \( |f(x) - L| < 1 \). This implies that \( L - 1 < f(x) < L + 1 \).
4Step 4: Defining the Bounded Interval
The interval \((c, d)\) can be defined as \((a-\delta, a+\delta)\). By our choice of \( \epsilon \), we know that \(|f(x)| < |L| + 1\) wherever \(0 < |x-a| < \delta\).
5Step 5: Bounding the Function on the Interval
Since \(|f(x)|\) is bounded by \(|L| + 1\) in the interval \((a-\delta, a+\delta)\), the function is indeed bounded in this interval. Hence, \( |f(x)| \leq M = |L| + 1 \) for all \( x \) in \((a-\delta, a+\delta)\).
Key Concepts
Definition of limitBounded functionEpsilon-delta definition
Definition of limit
In calculus, the definition of a limit describes the behavior of a function as it approaches a particular point. When we say that \( \lim_{x \rightarrow a} f(x) = L \), it means that as \( x \) gets closer and closer to \( a \), the function \( f(x) \) gets closer to the value \( L \). Importantly, the concept of a limit does not require \( f(x) \) to actually equal \( L \) at \( x = a \), or even that \( f(a) \) exists or equals \( L \). This is because the limit concerns how \( f(x) \) behaves near \( a \), not exactly at \( a \).
For many functions, knowing about limits allows us to predict the function's behavior very precisely. In practice, it means we can talk about the value a function is approaching. Limits are foundational in calculus as they lay the groundwork for more complex topics like continuity and derivatives.
For many functions, knowing about limits allows us to predict the function's behavior very precisely. In practice, it means we can talk about the value a function is approaching. Limits are foundational in calculus as they lay the groundwork for more complex topics like continuity and derivatives.
Bounded function
A function is considered bounded on a particular interval if there is a real number \( M \) such that the absolute value of the function is always less than or equal to \( M \) for any point in that interval. In simpler terms, a bounded function does not go to infinity and stays within a certain range on the specified interval.
To visualize it, imagine a function that oscillates up and down. If we can place a horizontal band around the graph of the function within a certain interval, and the graph never leaves that band, then the function is bounded in that interval.
To visualize it, imagine a function that oscillates up and down. If we can place a horizontal band around the graph of the function within a certain interval, and the graph never leaves that band, then the function is bounded in that interval.
- A bounded function guarantees that the values remain within some minimum and maximum.
- This concept is useful in proving certain properties, like continuity, as it prevents the function from having infinite oscillation near a point.
Epsilon-delta definition
The epsilon-delta definition is a formal way of defining what it means for a limit to exist. This definition uses two numbers: \( \epsilon \) and \( \delta \).
Here's how it breaks down:
Here's how it breaks down:
- We choose a very small number \( \epsilon > 0 \). Think of \( \epsilon \) as a tiny window around \( L \), the value we believe our function approaches.
- We then find a \( \delta > 0 \) such that whenever \( x \) is within \( \delta \) distance from \( a \), the function \( f(x) \) falls within the \( \epsilon \) window around \( L \). This is represented as: \( 0 < |x - a| < \delta \) implies \( |f(x) - L| < \epsilon \).
Other exercises in this chapter
Problem 28
Find the limits. \(\lim _{t \rightarrow-3^{+}} \frac{t^{2}-9}{t+3}\)
View solution Problem 29
How long does it take money to double in value for the specified interest rate? (a) \(6 \%\) compounded monthly (b) \(6 \%\) compounded continuously
View solution Problem 29
In Problems 24-35, at what points, if any, are the functions discontinuous? $$ g(u)=\frac{u^{2}+|u-1|}{\sqrt[3]{u+1}} $$
View solution Problem 29
Find the limits. \(\lim _{t \rightarrow 3^{-}} \frac{t^{2}}{9-t^{2}}\)
View solution