Problem 29
Question
Suppose \(f(x)=\frac{1}{3} x^{3}\). Estimate \(f^{\prime}(2), f^{\prime}(3)\), and \(f^{\prime}(4)\). What do you notice? Can you guess a formula for \(f^{\prime}(x)\) ?
Step-by-Step Solution
Verified Answer
The derivatives are approximations suggesting \(f'(x) = x^2\).
1Step 1: Understand the Derivative Definition
The derivative of a function, represented as \( f'(x) \), gives us the rate at which \( f(x) \) changes with respect to \( x \). It can be estimated using the limit definition: \[ f'(x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h} \]Our task is to apply this approximation to estimate the derivatives at specific points.
2Step 2: Calculate the Estimated Derivative at x = 2
Plug \( x = 2 \) into the function \( f(x) = \frac{1}{3} x^3 \) and calculate \( f(2) \) and \( f(2+h) \) for very small \( h \). Use these in the derivative formula approximation:\[ f'(2) \approx \frac{f(2+h) - f(2)}{h} \]Choose small \( h \) (like \( 0.001 \)):\( f(2) = \frac{1}{3}(2)^3 = \frac{8}{3} \)\( f(2+h) = \frac{1}{3}(2+h)^3 \approx \frac{1}{3}(8 + 12h + 6h^2 + h^3) \)Therefore, substituting these:\[ f'(2) \approx \frac{4h + 2h^2 + h^3}{h} = 4 + 2h + \frac{h^2}{h} \approx 4 \] when \( h \to 0 \).
3Step 3: Calculate the Estimated Derivative at x = 3
Repeat the approximation for \( x = 3 \):\[ f'(3) \approx \frac{f(3+h) - f(3)}{h} \]Calculate:\( f(3) = \frac{1}{3}(3)^3 = 9 \)\( f(3+h) = \frac{1}{3}(27 + 27h + 9h^2 + h^3) \)The substitution gives:\[ f'(3) \approx \frac{9h + 3h^2 + h^3}{h} = 9 + 3h + \frac{h^2}{h} \approx 9 \] when \( h \to 0 \).
4Step 4: Calculate the Estimated Derivative at x = 4
Repeat the approximation for \( x = 4 \):\[ f'(4) \approx \frac{f(4+h) - f(4)}{h} \]Calculate:\( f(4) = \frac{1}{3}(4)^3 = \frac{64}{3} \)\( f(4+h) = \frac{1}{3}(64 + 48h + 12h^2 + h^3) \)Substitute into the approximation:\[ f'(4) \approx \frac{16h + 4h^2 + h^3}{h} = 16 + 4h + \frac{h^2}{h} \approx 16 \] when \( h \to 0 \).
5Step 5: Observe the Pattern and Guess the Formula
From the calculations, we've observed that:- \( f'(2) \approx 4 \)- \( f'(3) \approx 9 \)- \( f'(4) \approx 16 \)Notice the pattern: \( 4 = 2^2 \), \( 9 = 3^2 \), \( 16 = 4^2 \). This suggests that the derivative formula for \( f(x) = \frac{1}{3}x^3 \) might be \( f'(x) = x^2 \).
Key Concepts
Derivative EstimationLimit Definition of DerivativePolynomial FunctionsFunction Analysis
Derivative Estimation
Estimating the derivative involves approximating the rate of change of a function at a specific point. This is particularly useful when you do not have the ability to compute the derivative directly using symbolic differentiation. To estimate a derivative, the difference quotient is often employed. This quotient is:
- \( \frac{f(x+h) - f(x)}{h} \)
Limit Definition of Derivative
The limit definition of a derivative is a foundational concept in calculus. It defines the derivative as the limit of the difference quotient as \( h \) approaches zero:
- \( f'(x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h} \)
Polynomial Functions
Polynomial functions, such as \( f(x) = \frac{1}{3} x^3 \), are algebraic expressions consisting of variables and coefficients. These functions are widely used because they can model many natural phenomena. The structure for any polynomial function is based on terms raised to whole-number powers:
- \( a_nx^n + a_{n-1}x^{n-1} + \cdots + a_1x + a_0 \)
Function Analysis
Analyzing a function involves exploring its properties and behaviors. Through differentiation, we gain insight into the function's rates of change, critical points, inflection points, and overall shape. The first derivative tells us where the function is increasing or decreasing.
- A positive derivative implies a rising function.
- A negative derivative indicates a falling function.
- Zero derivative marks possible local maxima or minima.
Other exercises in this chapter
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