Problem 29
Question
Solve. If \(y\) varies jointly as \(x\) and \(z,\) and \(y=60\) when \(x=4\) and \(z=3,\) find \(y\) when \(x=7\) and \(z=2\)
Step-by-Step Solution
Verified Answer
When \(x = 7\) and \(z = 2\), the value of \(y\) is 70.
1Step 1: Understand Joint Variation Formula
Joint variation means that a variable varies with the product of two or more other variables. In this case, \(y\) varies jointly as \(x\) and \(z\). The formula for joint variation is \(y = kxz\), where \(k\) is the constant of variation.
2Step 2: Substitute the Given Values and Solve for k
In the first scenario, the values are \(x = 4\), \(z = 3\), and \(y = 60\). We can substitute these values into the joint variation formula to solve for the constant of variation \(k\).
\[60 = k(4)(3)\]
3Step 3: Solve for k
The equation from step 2 simplifies to:
\(60 = 12k\)
Now, we divide both sides by 12 to solve for \(k\).
\(k = \frac{60}{12}\)
\(k = 5\)
4Step 4: Substitute the k-value and the New x and z Values
Now that we have found the constant of variation \(k = 5\), we can find \(y\) in the second scenario, where \(x = 7\) and \(z = 2\). We'll use the joint variation formula with the given values and our constant of variation:
\(y = (5)(7)(2)\)
5Step 5: Calculate the New y-value
The equation from step 4 simplifies to:
\(y = 5\times 7\times 2\)
\(y = 70\)
So, when \(x = 7\) and \(z = 2\), the value of \(y\) is 70.
Key Concepts
Constant of VariationAlgebraic ExpressionsSolving Equations
Constant of Variation
In joint variation problems, the relationship between variables involves a constant, known as the constant of variation, represented by the letter \(k\). This constant helps to express how one variable changes in response to changes in other variables. For joint variation, the formula we use is \(y = kxz\). Here, \(k\) shows how strongly \(y\) changes with respect to \(x\) and \(z\).
To determine \(k\), you need specific values of \(x\), \(y\), and \(z\). First, plug these values into the formula. For instance, if \(y = 60\), \(x = 4\), and \(z = 3\), you substitute these into the equation to find \(k\):
To determine \(k\), you need specific values of \(x\), \(y\), and \(z\). First, plug these values into the formula. For instance, if \(y = 60\), \(x = 4\), and \(z = 3\), you substitute these into the equation to find \(k\):
- \(60 = k \times 4 \times 3\)
- This simplifies to \(60 = 12k\)
- By dividing both sides by 12, you find \(k = 5\)
Algebraic Expressions
Algebraic expressions are combinations of numbers, variables, and arithmetic operations. They are used to represent mathematical relationships involving variables. In our joint variation problem, the key algebraic expression is \(y = kxz\). Here, the expression delineates a relationship between the variables \(y\), \(x\), and \(z\).
The expression is comprised of:
The expression is comprised of:
- Variables \(x\), \(y\), and \(z\) representing numbers that can change or take on different values.
- A constant \(k\) which helps define the specific relationship in this joint variation scenario.
- Operations include multiplication, highlighting how each part of the expression influences the overall relationship.
Solving Equations
Solving equations in joint variation involves several straightforward steps. The goal is to find the unknown variable by expressing it in terms of known quantities. Following these steps helps you decipher problems more efficiently.
To solve the exercise problem about joint variation, start by identifying the given values. In the initial case:
To solve the exercise problem about joint variation, start by identifying the given values. In the initial case:
- \(y = 60\)
- \(x = 4\)
- \(z = 3\)
- \(60 = k \times 4 \times 3\)
- Simplifies to \(60 = 12k\)
- Now divide, \(k = \frac{60}{12}\)
- So, \(k = 5\).
- \(y = 5 \times 7 \times 2\)
- Simplified to \(y = 70\)
Other exercises in this chapter
Problem 29
Let \(f(x)=3 x-7\) and \(g(x)=x^{2}-4 x-9 .\) Find each of the following and simplify. $$g(3)$$
View solution Problem 29
For each equation, identify the vertex, axis of symmetry, and \(x\) - and \(y\) -intercepts. Then, graph the equation. $$x=-(y-4)^{2}+5$$
View solution Problem 29
Rewrite function in the form \(f(x)=a(x-h)^{2}+k\) by completing the square. Then, graph the function. Include the intercepts. \(y=x^{2}+6 x+7\)
View solution Problem 30
The radius of a circle is half its diameter. We can express this with the function \(r(d)=\frac{1}{2} d,\) where \(d\) is the diameter of a circle and \(r\) is
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