Problem 29
Question
Solve each inequality. $$(3 v-11)^{2}>-20$$
Step-by-Step Solution
Verified Answer
The inequality \((3v - 11)^2 > -20\) is true for all values of \(v\) since any squared expression is non-negative and always greater than a negative number. Therefore, the solution is \(v \in \mathbb{R}\).
1Step 1: Observe the inequality
Notice that the left side of the inequality is a squared expression, which means it is non-negative. Therefore, it will always be greater than any negative number on the right side, such as -20.
2Step 2: State the solution
Since any squared expression (including \((3v - 11)^2\)) is greater than any negative number (such as -20), the inequality is true for all values of \(v\). Thus, the solution is:
$$v \in \mathbb{R}$$
Key Concepts
Algebraic ExpressionsQuadratic InequalitiesReal NumbersMathematical Reasoning
Algebraic Expressions
Algebraic expressions are a fundamental concept in mathematics that consist of variables, numbers, and operational symbols. For instance, in the exercise given, the expression \((3v - 11)^2\) is an algebraic expression. It includes:
- A variable, \(v\), which represents any number.
- Coefficients, which are the numbers multiplied by the variables—in this case, 3 is the coefficient of \(v\).
- Constants, such as 11, which are fixed values.
Quadratic Inequalities
A quadratic inequality involves a quadratic expression, usually in a form like \(ax^2 + bx + c\), where the highest power of the variable is squared. In the exercise, the quadratic expression is \((3v - 11)^2\).
Here are a few things to keep in mind about quadratic inequalities:
Here are a few things to keep in mind about quadratic inequalities:
- Just like quadratic equations, they may involve terms like \(x^2\).
- The solution can often be a range or set of values, rather than specific numbers.
- Quadratic inequalities are often solved by finding the roots of the corresponding quadratic equation and examining the intervals between these roots.
- However, in special cases like the given problem where the square of something is always non-negative, the inequality may simply be satisfied by all real numbers.
Real Numbers
Real numbers (\(\mathbb{R}\)) include everything you might count or measure, from positive numbers like 1 and 2, through zero, to negative numbers like -1. In the context of the exercise, when we say \(v \in \mathbb{R}\), we mean that \(v\) can be any real number.
This encompasses all numbers that are not complex, including:
This encompasses all numbers that are not complex, including:
- Rational numbers, like fractions and whole numbers.
- Irrational numbers, such as \(\sqrt{2}\) or \(\pi\), that cannot be expressed as simple fractions.
Mathematical Reasoning
Mathematical reasoning is the process of using logical thinking to solve mathematical problems. In the exercise, reasoning was used to conclude that since a squared expression is non-negative, it satisfies the inequality \((3v - 11)^2 > -20\) for all \(v\).
Here are the key components of strong mathematical reasoning:
Here are the key components of strong mathematical reasoning:
- Observation - Note the properties of the expressions and inequalities such as non-negativity of squares.
- Logical Deduction - Apply logical principles to deduce facts, like knowing \((3v - 11)^2\) is always greater than a negative number.
- Generalization - Extract general conclusions from specific observations, as in concluding the given inequality holds for all real numbers \(v\).
Other exercises in this chapter
Problem 29
Solve. $$\frac{1}{x-6}-\frac{1}{x}=\frac{6}{x^{2}-6 x}$$
View solution Problem 29
Simplify. $$(-2 n)^{3}(5 n)^{2}$$
View solution Problem 29
Identify the center of each hyperbola and graph the equation. $$\frac{(x-2)^{2}}{9}-\frac{(y+3)^{2}}{16}=1$$
View solution Problem 29
Solve each system. $$\begin{aligned} &y=-x^{2}-2\\\ &x^{2}+y^{2}=4 \end{aligned}$$
View solution