Problem 29
Question
Solve each equation. $$ x^{2}-4 x-21=0 $$
Step-by-Step Solution
Verified Answer
The solutions are \(x = 7\) and \(x = -3\).
1Step 1: Identify the Equation Type
The given equation is a quadratic equation of the form \(ax^2 + bx + c = 0\), where \(a = 1\), \(b = -4\), and \(c = -21\). We are going to solve it using the factoring method.
2Step 2: Factor the Quadratic
To factor the equation \(x^2 - 4x - 21 = 0\), we need two numbers that multiply to \(-21\) and add to \(-4\). The numbers \(-7\) and \(+3\) satisfy these conditions because \(-7 \times 3 = -21\) and \(-7 + 3 = -4\).
3Step 3: Write the Factored Form
Write \(x^2 - 4x - 21 = 0\) as \((x - 7)(x + 3) = 0\). The quadratic is now expressed as a product of two binomials.
4Step 4: Apply the Zero Product Property
According to the Zero Product Property, if \(ab = 0\), then either \(a = 0\) or \(b = 0\). Apply this to \((x - 7)(x + 3) = 0\).
5Step 5: Solve for x
Solve each equation derived from the Zero Product Property:1. Solve \(x - 7 = 0\), giving \(x = 7\).2. Solve \(x + 3 = 0\), giving \(x = -3\).
Key Concepts
Factoring QuadraticsZero Product PropertySolving Quadratic Equations
Factoring Quadratics
Factoring quadratics involves rewriting a quadratic equation in a way that allows it to be broken down into simpler parts called factors. This process can make it easier to solve the equation. Quadratic equations often follow the standard form:
These numbers are \(-7\) and \(+3\) because:
- \(ax^2 + bx + c = 0\)
These numbers are \(-7\) and \(+3\) because:
- \(-7 \times 3 = -21\)
- \(-7 + 3 = -4\)
- \((x - 7)(x + 3) = 0\)
Zero Product Property
The zero product property is a fundamental principle in algebra that comes into play once a quadratic equation has been factored. This property states that if the product of two numbers is zero, then at least one of the numbers must be zero. Mathematically, if \((a)(b) = 0\), then:
- \(a = 0\)
- or \(b = 0\)
- \(x - 7 = 0\)
- or \(x + 3 = 0\)
Solving Quadratic Equations
Solving quadratic equations can be done efficiently using a variety of methods, but in our example, we used factoring and the zero product property. After factoring the quadratic equation \(x^2 - 4x - 21 = 0\) into \((x - 7)(x + 3) = 0\), we leveraged the zero product property to break it down into simpler problems.
Solving for \(x\) through each factor, we approach:
Solving for \(x\) through each factor, we approach:
- \(x - 7 = 0\) leads to \(x = 7\)
- \(x + 3 = 0\) leads to \(x = -3\)
Other exercises in this chapter
Problem 29
Factor. $$ a^{3}-27 $$
View solution Problem 29
Factor each trinomial. See Example 4 or Example \(10 .\) $$b^{2}-9 b-36$$
View solution Problem 29
Factor. See Example 2 or Example 6. $$ 8 x^{2}-22 x+5 $$
View solution Problem 29
Find the GCF of each list of terms. $$ 20 c^{2}, 12 c $$
View solution