Problem 29
Question
Solve each equation in using both the addition and multiplication properties of equality. Check proposed solutions. $$2 x+1=11$$
Step-by-Step Solution
Verified Answer
The solution to the equation \(2x + 1 = 11\) is \(x = 5\).
1Step 1: Isolating the x-term using Addition Property of Equality
First, we need to isolate the term with the variable (2x) on one side. To do this subtract 1 from both sides of the equation \(2x + 1 - 1 = 11 - 1\). This results in the equation \(2x = 10\)
2Step 2: Solving for x using Multiplication Property of Equality
Now, to solve for 'x', divide '2x' by '2' on the left side and '10' by '2' on the right side of the equation to get \(x = 10 / 2\). This gives us \(x = 5\).
3Step 3: Checking the Solution
Substitute the solution for 'x' back into the original equation to verify if it's correct. So, \(2 * 5 + 1 = 11\) simplifies to \(11 = 11\). This is a true statement, thus the solution is correct.
Key Concepts
Addition Property of EqualityMultiplication Property of EqualityChecking Solutions
Addition Property of Equality
In math, when you have an equation, it's like a balance scale. Imagine that each side of the equation is a plate on the scale. For the balance to remain, you need to treat both sides equally. The Addition Property of Equality allows you to add or subtract the same number from both sides of an equation without changing its balance. In our exercise, we start with the equation: \(2x + 1 = 11\). To isolate \(2x\), we subtract 1 from both sides. Performing the same operation on both sides keeps our equation balanced:
- Subtract 1 from the left: \(2x + 1 - 1 = 2x\)
- Subtract 1 from the right: \(11 - 1 = 10\)
Multiplication Property of Equality
After using addition, we often use multiplication or division to solve for the variable's value. The Multiplication Property of Equality tells us we can multiply or divide both sides of the equation by the same number, and the equation will still hold. In our simplified equation \(2x = 10\), we need \(x\) by itself. Here, we divide both sides by 2 (the number attached to \(x\)):
- Divide the left side by 2: \(\frac{2x}{2} = x\)
- Divide the right side by 2: \(\frac{10}{2} = 5\)
Checking Solutions
Once you've solved for the variable, it's crucial to ensure your solution is correct. Checking solutions helps confirm you haven't made an error, and the original equation remains true. To check a solution, substitute the variable's value back into the original equation.In our case, we found \(x = 5\). Plug this back into the initial equation \(2x + 1 = 11\):
- Substitute \(x\): \(2 \times 5 + 1 = 10 + 1 = 11\)
Other exercises in this chapter
Problem 29
Solve the formula for the volume of a circular cylinder for \(h\)
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Use the addition property of inequality to solve each inequality and graph the solution set on a number line. \(5 x-9
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Use the percent formula, \(A=P B: A\) is \(P\) percent of \(B,\) to solve. What is \(18 \%\) of \(40 ?\)
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Solve each equation. Be sure to check your proposed solution by substituting it for the variable in the original equation. $$10(z+4)-4(z-2)=3(z-1)+2(z-3)$$
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