Problem 29
Question
Six surfaces are given below. Without performing any integration, rank the surfaces in order of their surface area from smallest to largest. Hint: There may be some "ties." (a) The paraboloid \(z=x^{2}+y^{2}\) over the region in the first quadrant and inside the circle \(x^{2}+y^{2}=1\) (b) The hyperbolic paraboloid \(z=x^{2}-y^{2}\) over the region in the first quadrant and inside the circle \(x^{2}+y^{2}=1\) (c) The paraboloid \(z=x^{2}+y^{2}\) over the region inside the rectangle with vertices \((0,0),(1,0),(1,1)\), and \((0,1)\) (d) The hyperbolic paraboloid \(z=x^{2}-y^{2}\) over the region inside the rectangle with vertices \((0,0),(1,0),(1,1)\), and \((0,1)\) (e) The paraboloid \(z=x^{2}+y^{2}\) over the region inside the triangle with vertices \((0,0),(1,0)\), and \((0,1)\) (f) The hyperbolic paraboloid \(z=x^{2}-y^{2}\) over the region inside the triangle with vertices \((0,0),(1,0)\), and \((0,1)\)
Step-by-Step Solution
VerifiedKey Concepts
Surface Area Comparison
To rank the surfaces without performing integration, we analyze the contribution of each surface type to the area within specific boundaries. Both the shape of the surface and the domain's area play crucial roles.
- Paraboloids tend to contribute more area as they curve upwards, expanding away from the base.
- Hyperbolic Paraboloids have parts that curve both above and below the base line, often resulting in smaller net surface areas.
Paraboloids
For each shape this surface covers, the area can vary:
- Over a circular region (like in case (a)), the area inside the circle sector is determined by the radius, here being 1, resulting in a base area of \( \frac{\pi}{4} \).
- Within a rectangular region (case (c)), the base has a unit area of 1.
- A triangular region (case (e)) gives a triangular slice bag of area \( \frac{1}{2} \).
Hyperbolic Paraboloids
This characteristic makes calculating surface areas for hyperbolic paraboloids vary greatly depending on the domain.
- Inside a circle sector as in (b), the region's quarter-circle base offers an area of \( \frac{\pi}{4} \).
- With a unit square base in (d), the overall area becomes 1.
- The triangular slice under (f) has an area of \( \frac{1}{2} \).
Geometric Regions
- Circle Sector: Represented in exercises (a) and (b), this region is defined by a radius of 1, providing a base area of \( \frac{\pi}{4} \).
- Rectangle: Involves exercises (c) and (d), defined as a unit square, achieving a total base area of 1.
- Triangle: Covers exercises (e) and (f), with a right triangular base providing an area of \( \frac{1}{2} \).
First Quadrant Analysis
The first quadrant offers simplicity in examining surface interaction with each shape:
- Ensures positive values for both \(x\) and \(y\), reducing the complexity involved in handling different signs.
- Streamlines analysis of each surface area by providing a consistent frame of reference from one shape to the next.