Problem 29
Question
Show that \(S^{1} \times S^{1}\) and \(S^{1} \vee S^{1} \vee S^{2}\) have isomorphic homology groups in all dimensions, but their universal covering spaces do not.
Step-by-Step Solution
Verified Answer
The homology groups of \(S^1 \times S^1\) and \(S^1 \vee S^1 \vee S^2\) are isomorphic, but their universal covers are not.
1Step 1: Define Homology Groups for \(S^1 \times S^1\)
The space \( S^1 \times S^1 \) is a torus. For a torus, the homology groups are:\[H_0(S^1 \times S^1) \cong \mathbb{Z},H_1(S^1 \times S^1) \cong \mathbb{Z} \oplus \mathbb{Z},H_2(S^1 \times S^1) \cong \mathbb{Z},H_n(S^1 \times S^1) \cong 0 \text{ for } n \geq 3.\]
2Step 2: Define Homology Groups for \(S^1 \vee S^1 \vee S^2\)
The space \( S^1 \vee S^1 \vee S^2 \) (a wedge of two circles and a sphere) has the following homology groups:\[H_0(S^1 \vee S^1 \vee S^2) \cong \mathbb{Z},H_1(S^1 \vee S^1 \vee S^2) \cong \mathbb{Z} \oplus \mathbb{Z},H_2(S^1 \vee S^1 \vee S^2) \cong \mathbb{Z},H_n(S^1 \vee S^1 \vee S^2) \cong 0 \text{ for } n \geq 3.\]
3Step 3: Compare Homology Groups
Comparing the previously derived homology groups of both spaces, we observe:- \(H_0\) for both spaces is \(\mathbb{Z}\).- \(H_1\) for both spaces is \(\mathbb{Z} \oplus \mathbb{Z}\).- \(H_2\) for both spaces is \(\mathbb{Z}\).- \(H_n\) is zero for both spaces for \( n \geq 3 \).Thus, \(S^1 \times S^1\) and \(S^1 \vee S^1 \vee S^2\) have isomorphic homology groups in all dimensions.
4Step 4: Consider Universal Covers
The universal cover of \( S^1 \times S^1 \) is \( \mathbb{R}^2 \), as it is a 2-dimensional manifold with no holes, making all its homology groups zero, except \( H_0(\mathbb{R}^2) \cong \mathbb{Z} \).For \( S^1 \vee S^1 \vee S^2 \), the universal cover consists of infinite copies of \( S^2 \), because its fundamental group is a free group on two generators; it doesn't contract to a point. Each \( S^2 \) contributes \( H_2 \cong \mathbb{Z} \).
5Step 5: Compare Universal Covers
Comparing universal covers:- Universal cover of \(S^1 \times S^1\): \(H_0(\mathbb{R}^2) \cong \mathbb{Z}\), \(H_n(\mathbb{R}^2) = 0\) for all \(n \geq 1\).- Universal cover of \(S^1 \vee S^1 \vee S^2\): \(H_2\) is non-trivial (\(\mathbb{Z}\)), unlike any homology group of the universal cover of \(S^1 \times S^1\).Therefore, their universal covers are not homologically equivalent.
Key Concepts
Homology GroupsUniversal Covering SpacesTorusWedge SumFundamental Group
Homology Groups
Homology groups are algebraic constructs that allow us to study topological spaces using the language of algebra. They provide a set of groups for each dimension, capturing essential information about a space's structure, such as holes and voids. For the torus, denoted as \(S^1 \times S^1\), the homology groups are:
- \(H_0(S^1 \times S^1) \cong \mathbb{Z}\)
- \(H_1(S^1 \times S^1) \cong \mathbb{Z} \oplus \mathbb{Z}\)
- \(H_2(S^1 \times S^1) \cong \mathbb{Z}\)
- \(H_n(S^1 \times S^1) \cong 0\) for \(n \geq 3\)
- \(H_0(S^1 \vee S^1 \vee S^2) \cong \mathbb{Z}\)
- \(H_1(S^1 \vee S^1 \vee S^2) \cong \mathbb{Z} \oplus \mathbb{Z}\)
- \(H_2(S^1 \vee S^1 \vee S^2) \cong \mathbb{Z}\)
- \(H_n(S^1 \vee S^1 \vee S^2) \cong 0\) for \(n \geq 3\)
Universal Covering Spaces
The universal covering space of a topological space is, essentially, the most simplified version of the space that covers it without any "twists" or "holes." Every loop on the universal cover can be shrunk to a point but preserves the same number of copies of the original space. For example, the universal cover of a torus \(S^1 \times S^1\) is \(\mathbb{R}^2\).
- Homology of \(\mathbb{R}^2\): \(H_0(\mathbb{R}^2) \cong \mathbb{Z}\), \(H_n(\mathbb{R}^2) = 0\) for all \(n \geq 1\)
- Homology of infinite spheres: \(H_2 \cong \mathbb{Z}\), showing non-trivial nature in dimension 2
Torus
A torus, denoted \(S^1 \times S^1\), is essentially the shape of a doughnut. It's formed by revolving a circle around an axis, which creates a cylindrical structure with a hole. This shape gives it rich topological properties.The fundamental feature of the torus is its two loops: one along the circle of the torus and another around the hole. These loops correspond to the generators of its homology:
- First circle (meridian) representing \(H_1\)
- Second circle (longitude) representing another part of \(H_1\)
Wedge Sum
The wedge sum, often denoted by the symbol \(\vee\), is a method to combine topological spaces at a single shared point. For example, \(S^1 \vee S^1 \vee S^2\) combines two circles and a sphere.In forming a wedge sum, each component's independent loops are preserved, giving rise to new homology characteristics:
- Each circle \(S^1\) contributes to \(H_1\)
- The sphere \(S^2\) affects \(H_2\)
Fundamental Group
The fundamental group, denoted \(\pi_1\), is the topological space's "loop space." It provides insight into the geometry of a space by examining the loops beginning and ending at a single point. For \(S^1 \times S^1\), this group is \(\mathbb{Z} \times \mathbb{Z}\) because it can repeatedly "wrap" around two independent circles.For \(S^1 \vee S^1 \vee S^2\), the fundamental group is more complex, represented as a free group on two generators. This free group property implies intertwining loops that cover an infinite spectrum of arrangements.Understanding the fundamental group allows us to predict universal covers:
- The torus's fundamental group indicates a simple, repeating structure (\(\mathbb{R}^2\))
- The wedge sum's free group structure suggests repeat copies (infinite \(S^2\))
Other exercises in this chapter
Problem 25
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Use the Mayer-Vietoris sequence to show there are isomorphisms \(\tilde{H}_{n}(X \vee Y) \approx\) \(\tilde{H}_{n}(X) \oplus \tilde{H}_{n}(Y)\) if the basepoint
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For \(S X\) the suspension of \(X,\) show by a Mayer-Vietoris sequence that there are isomorphisms \(\tilde{H}_{n}(S X) \approx \tilde{H}_{n-1}(X)\) for all \(n
View solution