Problem 29
Question
Perform the addition or subtraction and write the result in standard form. $$(5+\sqrt{-27})-(-12+\sqrt{-48})$$
Step-by-Step Solution
Verified Answer
The result of the addition/subtraction of the two given complex numbers is \(-7 + 7\sqrt{3}i\).
1Step 1: Rewrite the problem using imaginary numbers
First, rewrite the exercise with imaginary numbers, as \((5 + 3\sqrt{3}i) - (12 - 4\sqrt{3}i)\). That's because \(\sqrt{-27}= \sqrt{27}\cdot i = 3\sqrt{3}\cdot i\) and \(\sqrt{-48}= \sqrt{48}\cdot i = 4\sqrt{3}\cdot i\).
2Step 2: Perform the subtraction
Subtract the terms by performing subtraction of corresponding real parts and imaginary parts separately, giving us \((5 - 12) + (3\sqrt{3}i - -4\sqrt{3}i)\) = \(-7 + 7\sqrt{3}i\).
3Step 3: Write the final result
The result, \(-7 + 7\sqrt{3}i\), is already in standard form for complex numbers, \(a+bi\).
Key Concepts
Imaginary NumbersStandard Form in Complex NumbersAddition and Subtraction of Complex Numbers
Imaginary Numbers
Imaginary numbers might sound complicated, but they're quite simple once you get to know them! They'll become your helpful sidekick when you're dealing with square roots of negative numbers. In math, we know that squares of any real numbers give us positive outcomes. So what do we do when we encounter calculators screeching errors at us with the square root of a negative number? That's where imaginary numbers come to the rescue. These numbers use the unique unit called 'i'.
- 'i' is defined as the square root of -1, making it a special number that helps solve otherwise impossible problems.
- For example, if you see \(\sqrt{-4}\), you can rewrite it as \(2i\) because it's \(\sqrt{4}\times i\).
Standard Form in Complex Numbers
The standard form of complex numbers is easy to grasp and provides a straightforward way to express these characters of mathematics. Complex numbers are a mix of real and imaginary numbers, and the standard form shows this perfectly. If you like things neat and orderly, then you'll love the standard form!
- The standard form for any complex number is written as \(a + bi\), where:
- 'a' is the real part of the complex number.
- 'bi' is the imaginary part where 'b' is a real number coefficient for 'i'.
- For example, in the complex number \(3 + 4i\), 3 is the real part, and \(4i\) is the imaginary part.
Addition and Subtraction of Complex Numbers
Manipulating complex numbers is much like handling regular numbers, but with a neat twist: managing both real and imaginary parts. When adding or subtracting complex numbers, you need to treat the real and imaginary parts as separate components, conducting operations on each part independently.
Similarly, for subtraction such as \((5 + 3i) - (2 + i)\), subtract the real components \(5 - 2 = 3\) and the imaginary parts \(3i - i = 2i\) to get \(3 + 2i\).
Handling complex numbers like these lets you seamlessly perform arithmetic while respecting all components. This method ensures clarity and accurate results, offering a rewarding crunch of numbers under your fingertips.
- For addition: Simply add together the real parts separately from the imaginary parts.
- For subtraction: Subtract the real parts and then subtract the imaginary parts accordingly.
Similarly, for subtraction such as \((5 + 3i) - (2 + i)\), subtract the real components \(5 - 2 = 3\) and the imaginary parts \(3i - i = 2i\) to get \(3 + 2i\).
Handling complex numbers like these lets you seamlessly perform arithmetic while respecting all components. This method ensures clarity and accurate results, offering a rewarding crunch of numbers under your fingertips.
Other exercises in this chapter
Problem 29
Solve the equation by extracting square roots. List both the exact solutions and the decimal solutions rounded to the nearest hundredth. $$(3 x-1)^{2}+6=0$$
View solution Problem 29
Solve the equation algebraically. Then write the equation in the form \(f(x)=0\) and use a graphing utility to verify the algebraic solution. $$12(x+2)=15(x-4)-
View solution Problem 29
Solve the equation (if possible). $$\frac{5 x-4}{5 x+4}=\frac{2}{3}$$
View solution Problem 30
Solve the inequality and sketch the solution on the real number line. Use a graphing utility to verify your solution graphically. $$0 \leq \frac{x+3}{2}
View solution